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Calculate St And Bearing Of T From S Correct To The Nearest Degree

A lighthouse 7000 m from a ship is on a bearing of 315 degrees from the ship. How far is the ship south of the lighthouse? Leave your answer in the exact form.

“A lighthouse 7000 m from a ship is on a bearing of 315 degrees from the ship. How far is the ship south of the lighthouse? Leave your answer in the exact form.”I had the answer, off the top of my head, in about two seconds.Why? Because when I was in the Navy, 30 years ago, I was a submarine sonar operator. A big part of the job used trigonometry for vector analysis, calculating what all the other ships and subs around us were doing. It’s called TMA (Target Motion Analysis).Part of the memorized knowledge base was a simple sine table. Part of the table said that for angles less than 30 degrees, the sine is degrees/60. We also memorized certain values. For example, the sine of 45 degrees is .7 (actually, .707), 30 degrees is .5, 60 degrees is .866.SO?Here’s a diagram. We did these in our head. When I’m REALLY bored (in a doctors office, perhaps) and there’s no cell coverage (in a doctor’s office, perhaps), I might grab a bit of paper and make one, with pieces missing, and solve it. Why? Because after 14 years, it’s automatic. Which is how I was able to answer your question in two seconds.OK, so what does that have to do with your homework assignment? (We know it is, because it’s obvious. Just read it. “Show your work” = homework.I won’t tell you. But I’ll give you a hint. What’s the sine (and cosine) of 45 degrees?PS I HATE homework questions on Quora! Do it your frickin’ self!

The bearing of point A to point B is 207 degree. What is the bearing from B to A?

Here, bearing of a line AB i.e. forebearing( FB)= 207Bearing of line BA ie backbearing (BB) = 207–180 = 27 is the required bearingYou can use this formula for the calculation of bearing.B.B. = F.B + OR - 180+ when F.B < 180- when F.B >= 180 ENJOY SURVEYING. AND UPVOTE THIS ANSWER IF IT IS HELPFUL…THANK YOU

Calculate ST and bearing of T from S correct to the nearest degree?

Distance of T from the lighthouse in x direction

Tx = 8.4cos(75)
= 2.1741 km

Distance of T from the lighthouse in y direction

Ty = 8.4sin(75)
= 8.1138 km

Distance of S from the lighthouse in x direction

Sx = 6.8cos(310)
= 4.3710 km

Distance of S from the lighthouse in y direction

Sy = 6.8sin(310)
= -5.2091 km

The distance between the ships is

ST = √[(2.1741 - 4.3710)^2 + (8.1138 - (-5.2091))^2]
= 13.5028 …
= 13.5 km

The bearing of T from S is

∠ST = arctan[(8.1138 - (-5.2091))/(2.1741 - 4.3710)]
= 99º

If a man walks 4m towards the east and then turns 60 degrees to the north and walks for another 4m, what would the net displacement be?

Instead of doing a lot of derivation and going into complicated trigonometry, I followed the simplistic approach: draw the whole figureSo what I did was to draw the whole process in PowerPoint and measure.The scale I chose was 1 cm = 1 mOn the right side, you can see that the height and width of the blue line is3.5 cm and 6 cm respectively.So I used Pythagoras Theorem to find out the length of this line[math]l = \sqrt{3.5^2 + 6^2} = 6.95[/math]And thus the answer I got was 6.95 mHowever, as you can see in the figure that the triangle formed is an isosceles triangle, the angles are known to us, and we can easily find the length of the opposite side using a little trigonometry.Use the sine rule to find the length of the side easily.Sine rule states that[math]\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/math]Where a, b, and c are three sides of any triangle. A, B, C are the angles opposite to sides a, b, and c respectively.Now the angle between two sides of 4 m each is [math]\frac{2\pi}{3}[/math]So, the value of other side goes like:[math]\dfrac{l}{\sin\frac{2\pi}{3}} = \dfrac{4}{\sin\frac{\pi}{6}}[/math]Which gives a more accurate answer:[math]l = 6.928m[/math]

In astronomy, what is the First Point of Aries? How do I measure the Right Ascension and Declination?

First point of Aries is the point where the ecliptic and celestial equator meets .each other.Due to Earth's axial precession, this point gradually moves westwards (Back ) at a rate of about one degree every 72 years. This means that, since the time of Hipparchus, it has shifted across the sky by about 30°, and is currently located within Pisces, near its border withAquarius. Currently, the closest major star to the First Point of Aries is λ Piscium, located at (22h 52m 37s, −07° 34′ 47″).The Sun now appears in Aries from late April through mid May, though the constellation is still associated with the beginning of spring.[1][2][3]Right ascension is measured from first point of Aries in 24 equal parts called hours.ITis furtur subdivided into arc minutes and arc seconds. Declination is measured to north and south of celestail equator.itis in degrees.Towards south is negative.  .In simple terms just think it as equivalent to Longitude+ right ascension and latitude as declination on celestial sphere.That will help you.

How do you calculate what angle to hit a pool ball?

There are two popular aiming methods Ghost and Fraction both provide a good baseline, but do not account for all the variables. See note below.Ghost ball is the literal top down method. Always go to the far end of the table on a long cut to get a top down view. Use a spare object ball to help find the center of the ghost ball when practicing.Fractional hit works from the point of view of the shooter while they are down on the shot. The diagram below shows typical fractions measured by fractions of a ball and showing the angles. You work backward from from the angle you need to find the fraction to hit to use. Egde of the ball is the easiest place to aim at and the easiest angle to recognize.  Make a relaxed peace/victory sign with your hand and your index and middle fingers will be about 30 degrees apart. Its also half of 60 degrees which you can see by holding three balls together. Which is also the visual proof for why this works when you look from the top you see the ghost ball angle. When you look from one of the three balls to the edge you can see the 30 degree cut would happen it you aim at the edge.Use both methods in conjunction but apply the ghost ball method first as you need to look down on the balls (or envision doing so).The sites these images come from are awesome resources and are linked below each.I also recommend Mike Page's ten minute guide to pool. Its more or less how I teach a one hour lesson but much faster.Caveat:You must account for an affect sometimes described as a type of "throw".You don't need to do this for shots that are almost perfectly straight or almost a full 90 degree cut.At about 45 degrees a variety of affects happen that result the object balls line moving up to a full ball forward of the tangent line these methods predict. One simplistic way to deal with this is always cut a little thinner than these methods indicate. We call cutting too thin missing on the pro side, because it shows you are aware of this issue and attempting to compensate. This is a continuum from full compensation at near 45 degrees going down to near 0 at 0 and 90 degrees.Linkshttp://billiards.about.com/od/pl...http://billiards.colostate.edu/t...

Trigonometry: How does tan X = 0.25 equal 14 degrees?

I'm currently doing trigonometry right now, and I don't understand it at all. One of the questions is: To the nearest degree, determine the measure of angle X for each value of tan X.

a) tan X = 0.25
b) tan X =1.25

I looked in the back of the book, and the answers are: a) 14 degrees b) 51 degrees.

Would someone please explain to me how to get those answers?

Bearings!!??! :(( Math help pleaseee!?

OK So heres some precalc fun for you (-__- nottt)

Its bearings and i dont understand the whole .... well everything.. and im really bad at word problems omg dont even get me started :(((

The problem is:

Two lifeguards, Tony and Sharon, are 22 kilometers apart and Tony is directly due south of Sharon on the beach. A stranded boat offshore is spotted by both lifeguards, and the bearings from Tony and Sharon, respectively, are N26E and S10E. Determine the distance the stranded boat is from the beach. Round answer to nearest tenth of a kilometer.

A. 1.8 kilometer
B. 2.8 kilometer
C. 4.0 kilometer
D. 4.7 kilometer
E. 5.7 kilometer

An airplane has a ground speed of 350 km/hr in the direction due west. If there is a wind blowing northwest at 40 km/hr, calculate the true air speed and heading of the airplane?

Hello my friend. Thanks for the A2A…Airspeed is the speed of the aircraft relative to the wind blowing around it.Ground speed is the speed of the aircraft relative to the ground.There will be higher ground speed and low true airspeed if there is a tailwind. There will be low ground speed and higher airspeed is a headwind.Now, Ground speed = True Airspeed + Windspeed. So,True Airspeed = Ground speed — Wind speed.Aeronautical Calculations of Headwind and Crosswind.Here it is given that the aircraft is moving towards west. Therefore it is heading 270 degrees at a Groundspeed of 350 kmph.Now, the wind is blowing from Northwest.It means it is blowing from 315 degrees. The wind is blowing from NW to SE.So, the aircraft has both headwind component as well as cross wind components.So, angle between the wind and aircraft is therefore 315 — 270 = 45 degrees.It is to be remembered thatHeadwind = Windspeed * Cos (A).Crosswind = Windspeed * Sin (A).So, here, the headwind will beHW = 40 * Cos 45 = 40 * 0.707 = 28.28 km/h.CW = 40 * Sin 45 = 40* 0.707 =28.28 km/h.True Airspeed (TAS) =350 — ( — 28.28) = 350+28.28 = 378.28 km/h.Windspeed will be negative as it is a headwind. It will be positive as it is a tailwind.Due to the 45 degrees of cross wind, the track of the airplane will change to the below calculated Drift Angle.Drift Angle = (Windspeed * Angle between aircraft & wind) / True Airspeed.Drift angle = (40 *45)/378.28 = 4.75 degrees towards the Wind.So, the drift angle will be also 4.75 degrees.So, the new heading of the aircraft will be 274.75 degrees (West north-West); the true airspeed of the aircraft will be 378.28 km/h.See that the groundspeed is less than the true airspeed. So, it is headwind.Hope you got your answer. Thanks a lot..

Coordinate geometry question?

Two planes leave an airport at the same time. The first travels on a bearing of 063° at
500 km/h. The second travels on a bearing of 153° at 400 km/h.
Calculate the bearing of the first plane from the second plane.

Can anyone show full working and explain thoroughly how to get the answer to this? I know that the answer is 024° but I want to know how to get that answer.

10 points for best answer

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