Calculate the equivalent blackbody temperature...?
Mercury is 5.8x10^7 km away from the sun and its albedo is 0.06. Calculate the equivalent blackbody temperature of Mercury. My problem is calculating the solar constant because I dont think its 1368 W/m^2 since were talking about Mercury and not Earth.... Also how does the 5.8x10^7 play into the equation? Thanks!
Is there a way I can calculate the temperature of a star in Kelvin with only its mass and radius?
How would you detect the star in the first place? If you can see it (or an ultra-violet or infra-red photographic plate can “see” it), then by knowing the colour of the star, you know its temperature. The relevant equations (ignoring relativistic effects) are:Energy of a photon is E = hf (h = Planck constant, f = radiation frequency)Black body radiation equation E = kT (k = Boltzman constant, T = temperature).
Is there some gravitational equivalent of the Black Body radiation (BBR), with gravitons playing the role of the photons in BBR?
Gravitational waves are as they describe. They do not convey value to define spacetime. They just fluctuate the density. Other propagations give value and define the fabric of spacetime gravity waves apply to.LIGO uses the term graviton the same way most use the term photon. Both terms are misleading. A photon is a virtual particle in that it has potential to interact and confine. A graviton is virtual only in regard to putting the numbers into material context. It does not confine into matter. It can help matter confine, just as an x-ray is perturbed by the density around a black hole. Enabling is not giving the value to create though. Light gives the value. Gravitons do not.Black bodies are hypothetical objects used for mathematical purposes to describe ideal absorption of energy. There is no such object. Black holes have a singularity into which matter is pushed, but energy alone cannot be absorbed. It generally follows the gravity well around or deflects as x-rays.
Is there a formula between the peak point of a black-body radiation and temperature? Also, what is the formula?
For a rough, conceptual development, remember that temperature is the average kinetic energy of a molecule: T =(mv^2)/(3k) where T is in Kelvin and k is the boltzmann constant. So 1/2mv^2 = 3/2Tk.The energy of a photon is E = hf = 3/2 TkThat gives you the relation thatT = 2/3 hf/kPlugging in for the constants,T = 0.6667*6.63E-34 J-s / 1.38E-23 J/K * f = 3.2E-11 f where frequency is in hertz and T in degrees KWriting this in terms of wavelength, where wavelength = speed of light/frequency, gives:T = 3.2E-11*3E8/wavelength = .0011/wavelength where wavelength is in metersThis solution fails to work, however, because an actual hot body will radiate a wide range of photon frequencies, not just a single one. The relation between temperature and peak wavelength was developed by a scientist named Wien in the 1890s as:T = .0029/wavelength = .0029 * f/c = 9.7E-12 fThis is the conversion factor that we use to convert photon frequencies to equivalent temperatures.
Does Charles Law show that at the absolute zero temperature volume of a gas becomes zero?
Yes. For a hypothetical “ideal gas” the volume at absolute zero is also zero. This is because the molecules of which the ideal gas is composed have zero volume.At ordinary temperatures and pressures, the volume of molecules is negligible so Charles’s Law works fine. However, working at high pressures in particular there are modified versions which allow for the volume of the molecules.The hypothetical ideal gas does not (of course) condense to a liquid, which real gases do because of interactions which are not accounted for in Charles’s Law.
Blackbody Radiation Physics Problem?
An astronomer is trying to estimate the surface temperature of a star with a radius of 5.0 x 10^8 m by modeling it as an ideal blackbody. The astronomer has measured the intensity of radiation due to the star at a distance of 2.5 x 10^13 m and found it to be equal to 0.055 W/m^2. Given this information, what is the temperature of the surface of the star? any help is greatly appreciated!
Calculating the fraction of infrared radiation absorbed by Venus atmosphere, help ?
In the absence of any greenhouse effect, Venus s average surface temperature, like Earth s, would be about 250 K. In fact, it is about 730 K. Use this information and Stefan s law to estimate the fraction of infrared radiation leaving Venus s surface that is absorbed by carbon dioxide in the planet s atmosphere.
Fundamental frequency in an aluminum rod?
A longitudinal standing wave can be created in a long, thin aluminum rod by stroking the rod with very dry fingers. This is often done as a physics demonstration, creating a high-pitched, very annoying whine. From a wave perspective, the standing wave is equivalent to a sound standing wave in an open-open tube. In particular, both ends of the rod are anti-nodes. What is the fundamental frequency of a 1.90 m-long aluminum rod?