How many number of moles are present in 3.6gram of water (H2O)?
As we know,Mole = weight in gram / molar massHere, weight = 3.6 gmMolar mass (H2O) = (2*1)+16 = 18By putting the values..Moles = 3.6/18 = 0.2Therefore 0.2 mole are present in 3.6 gms of H20.Hope it will help you..Thanks..:-)
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 6.60 of magnesium perchlorate, .?
Mg(ClO4)2 moles Mg = 6.60 moles Cl = 6.60 x 2 = 13.2 moles O = 6.60 x 8=52.8
How many O atoms are in 3.0 moles of CO2?
1 molecule of CO2 = 1 C atom + 2 O atom.1 mole of CO2 = 6.02 x 10*23 CO2 moleculesSo, 1 mole of CO2 contains (2 x 6.02 x 10*23) O atomsSo, 3 moles of CO2 contains (3 x 2 x 6.02 x 10*23) O atoms = 3.61 x 10*24 O atoms.
Is the amount of cl atoms contained in a mole of cl2 Avogadro's number (6.022*10^23)?
No. The amount of Cl atoms contained in a mole of Cl2 will be 2*( 6.022 e23)=1.204 e24. The reason for this is that one molecule of Cl2 will have 2 atoms of Cl, joined together by a bond. This means that since 1 mole is 6.022 e23 times 2 atoms/molecule =1.204 e24 Cl atoms.
How many grams of sulfur contain the same number of atoms as 3.10 grams of phosphorus?
No of moles of phosphorus = given mass / molar mass = 3.10/ 31 = 0.1No.of atoms = no. of moles x Avogadro number = 0.1 x 6.022 x 10^23 = 6.022 x 10^22No . of moles of sulfur = x / 32No. of atoms = x' / 32 x 6.022 x 10^23According to the question, No. of atoms of sulfur = No. of atoms of phosphorusx' / 32 x 6.022 x 10^23 = 6.022 x 10^22Solving the equation, we get,x'=3.2 gThere you go! Hope it helps !
What is the mass of 2.5 moles of CO2?
Atomic mass of Carbon is - 12.011Atomic mass of oxygen is- 15.999The molecular mass of CO2 is -At mass of C +At mass of O212.011+(2x15.999)=44.009As we know one mole =6.023 x 10*233 mole=3 X (6.023x10*23)And we r being asked that 3 mole CO2= 3 X (6.023 x 10*23)x 44.009 gOK thanks a lot
How much heat is released when 670. kg H2O2 decomposes in this reaction?
670 kg x 1 mol/.03402kg = 19694 mol H202 x 196.1kJ / 2 mol = 9847.15 kJ of heat released. Multiply given mass by the molar mass (I automatically converted from grams to kilograms) to get moles of peroxide then multiply by the ratio of heat to number of moles per reaction to get the amount released. Hope that helped.
How many moles of O2 are needed to react with 2.09 mol of aluminum? .?
The first step is to write a balanced equation. Aluminum oxide is Al2O3 because aluminum commonly takes on a charge of 3+, while oxygen tends to form ions with 2- charge. 4 Al + 3 O2 --> 2 Al2O3 Now, all you have to do is use the mole ratio (which comes from the balanced equation) to solve this problem. You are given moles of aluminum and asked to find moles of oxygen, so the mole ratio you want is that which relates those two, which would be 3/4 moles O2/moles Al (because those are the coefficients). So you just have to multiply the moles of Al by this ratio to find the number of moles of O2: (2.09 mol Al) * (3/4 mol O2/mol Al) = 1.57 mol O2