How can I calculate the number of moles of air?
For questions about situations from everyday life, we can use the so-called “Ideal Gas Law”. Even though ideal gases do not exist,the result will be good enough for everyday purposes.[math]p \cdot V = n \cdot R \cdot T [/math]This formula is the Ideal Gas Law. p is the pressure, expressed in pascal (Pa). V is the volume in cubic meters ([math]m^3[/math]). n is the number of moles. R is a constant, equal to about 8.31 [math]\dfrac{J}{K \cdot mol}[/math]. T is the absolute temperature, expressed in Kelvin (K).To calculate the number of moles of air in a given volume, you only need to perform a couple of simple operations.[math]p \cdot V = n \cdot R \cdot T[/math][math]\Leftrightarrow \dfrac{p \cdot V}{R} = n \cdot T[/math] (We divide both sides by R)[math]\Leftrightarrow \dfrac{p \cdot V}{R \cdot T} = n[/math] (We divide both sides by T)Now you will only need to know the pressure, volume and temperature and you can get the number of moles. As an example, I will perform the calculation for one litre of air at standard temperature and pressure (as defined by IUPAC).p = 100,000 PaV = 1 [math]dm^3[/math] = 0.001 [math]m^3[/math]T = 0 °C = 273.15 KR = 8.31 [math]\dfrac{J}{K \cdot mol}[/math][math]n = \dfrac{10^5 Pa \cdot 0.001 m^3}{8.31 \dfrac{J}{K \cdot mol} \cdot 273.15 K}[/math][math]n \approx 0.0441[/math] molStandard conditions for temperature and pressure Standard pressure
Calculate the number of moles of water at 0 degrees Celsius .....?
Calculate the number of moles of water at 0 degrees Celsius that can be frozen by one mole of dry ice (solid carbon dioxide). The value of deltaHsub for CO2 is 25.2 kj*mol
Calculate the number of moles of water in a glass of water (150g).?
moles=g/molec. wt moles H2O= 150 g/18 g/mole H2O
How many number of moles are present in 3.6gram of water (H2O)?
As we know,Mole = weight in gram / molar massHere, weight = 3.6 gmMolar mass (H2O) = (2*1)+16 = 18By putting the values..Moles = 3.6/18 = 0.2Therefore 0.2 mole are present in 3.6 gms of H20.Hope it will help you..Thanks..:-)
What is the number of hydrogen atoms in 5 moles of water?
You can calculate how many H2 atoms are in 5 moles of H2O by using Avogadro's number.Explanation:You'd go about calculating this by using Avogadro's number, which links the number of atoms or molecules of a substance with the number of moles of that substance you have.According to this relationship, every mole has 6.022 * 1O^23 atoms (or molecules, depending on the substance).Since water is a molecule, 1 mole of water will always have 6.022*10^23 molecules of water.Likewise, 1 mole of diatomic O2 will also have 6.023*10^23 molecules of oxygen.So, the question asks to calculate how many atoms are there in diatomic hydrogen in 5 moles of water.5 moles*2(because hydrogen is diatomic)*6.023*10^23 atoms =6.022*10^24 Hydrogen atoms.**Sometimes, students will calculate for all the atoms and will include oxygen, be careful to read the question properly.
The solubility of Oxygen in water at 0 degrees celcius and 1 atm is .073g/L. What is K in Henry's Law? p=Kc?
your question is missing something...what is the partial pressure of O2??? anyways i am giving a way through which you can calculate Kh knowing the solubility of a gas... let us assume that density of solution is same as that of solvent (water)....[this assumption is necessary for calculating the number of moles of oxygen and water].... now mass of 1 Litre solution = 1000 g (as density of water is 1 g/ml..actually at 0 degree centigrade the density is 0.99978 g/ml but i am taking it as 1 so as to make calculation easy) see the density of water at 0 degree at this link-- http://www.mrbigler.com/misc/Pvap-H2O.PDF now mass of solvent = solution - solute (in 1 litre) = 1000 - 0.073 = 999.927 (since we are dealing with 1 litre only ) so number of moles of water = 999.927/18 = 55.5 moles (mass of water = 18 g) number of moles of O2 = 0.073/32 = 2.28 X 10^-3 so mole fraction of oxygen in 1 litre of water = 2.28 X 10^-3/(55.5 + 2.28 X 10^-3) = 2.28 X 10^-3/(55.5 +0.002) = 2.28 X 10^-3/55.5 = 0.041 X 10^-3 now applying henry's law: PO2 = Kh X XO2 where PO2 is the partial pressure of O2 in gas phase... XO2 is the mole fraction of O2 as calculated above.. and Kh is Henry's constant... see the question should mention about PO2 ...otherwise i dont think it is possible to solve...
What is the volume of 1 molecule of water?
Density of water is 1000 g/L.The gram molecular mass of water is 18.02.The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles.1 mole of water = 6.022 x 10^23 molecules of water,So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water.3.34 x 10^25 molecules of water = 1 litre,1 molecules of water = 1 /3.34 x 10^25= 3.0 x 10^–24 litre.For more information you can visit worldofchemicals
What is the molar concentration of water in 1 liter of pure water?
Well at first we examine the relationship density - volume. Assuming that the density of water is 0,9970479 g/ml at 25°C, one liter water has the mass of 997,0469 g or 0,9970479 kg. The molar mass of water is 18,01528 g/mol. So n = m/M. It follows that one liter water contains 997,0469/18,01528 mol or 55,3445 mol. Thus the molar concentration is ~ 55mol/L