Calculate Vrms The Root Mean Square Velocity In M/s Of So2 Molecules At 42 Oc.

Calculate vrms, the root mean square velocity, in m/s of SO2 molecules at 407degrees C.?

To solve this, we apply the law stating that the average kinetic energy of a gas molecule is directly proportional to the temperature in Kelvin:

= 1/2(mv^2)= 3/2(KT), where m is the mass of the gas molecule, v is the velocity, T is the temperature and K is the Boltzmann constant(1.38x10^-23m^2s^-2K^-1.

Expressing it in terms of v, we get v= √(3KT/m)

Relative Molecular Mass(RMM) of SO2= 64
6.02x10^23 molecules of SO2= 64g
1 molecule of SO2= 64/6.02x10^23
= 1.06x10^-22g
= 1.06x10^-25kg

Thus, v= √(3)(1.38x10^-23)(407+273)/1.06x10^-25)
= 515m/s(root mean square velocity of an SO2 molecule)

I hope this helps and remember, you can send me an e-mail anytime if you're stuck. Good luck!

Calculate vrms, the root mean square velocity, in m/s of SO2 molecules at (-3) oC.?

v(rms) = SQRT (3RT/M)

where:
v(rms) = root mean square velocity
R = gas constant = 8.314 J/mol*K
T = temperature = -3C + 273.15 = 270.15 K
M = molar mass SO2 (in kg) = 0.0641 kg/mol

Therefore,

v(rms) = SQRT[(3)*(8.314 J/mol*K)*(270.15 K)/0.0641 kg/mol] = 324 m/s

Calculate the root mean square velocity for the O2 molecules in a sample of O2 gas at 25.0°C. (R = 8.3145 J/K

bloop87 is right - except that m in the formula is the mass of one molecule, not the molar mass - but we can express the same formula as:

Vrms = sqrt(3RT/Mr) where Mr is the molar mass in kg/mol, T the temperature in Kelvin and R = 8.3145 J/K the universal constant.So:

Vrms = sqrt(3*8.3145*298/0.032) = 482 m/s

Calculate vrms, the root mean square velocity, in m/s of SO2 molecules at 238 oC.?

average kinetic energy = (1/2)m(Vrms)² = (3/2)kT

(1/2)(64 g/mol)(mol / 6.02e23 molecules)(Vrms)² = (3/2)(1.38e-23 J/K)(238 + 273K)

Vrms = 199 m/s

10 points!! Calculate the root mean square velocity, in m/s, of SO2 molecules at 226 oC.?

Wrong value of R. Molar mass must be in kg/mol

Here are some solved examples:

http://chemteam.info/GasLaw/gas-velocity...

(b) Calculate the rms speed of SO2 molecules at 33°C.?

vrms = sq. root ( 3RT / M ) the place R is 8.314 J/ok-mol T is temperature in kelvin (25C is 298K) M is molar mass of N2 it extremely is 28g/mol At 25C, vrms = sq. root (3*8.314*298 / 28) = sixteen.3 If the temperature is 50C, which skill in Kelvin it would be 273+50=323K. At 50C, vrms = sq. root (3*8.314*323 / 28) = 17.0 So, even nonetheless the temperature doubled in tiers C, the vrms in basic terms will enhance with the help of a ingredient of a million.04. and that's because of fact you utilize Kelvin in vrms calculations.

Calculate the root mean square velocity of nitrogen molecules at 25°C.?

r.m.s = square root of ( 3RT/M)

where R = 8.314 J/K/mole
T = 25 + 273 = 298 K
M = molecular mas of N2 in kg = 28 X 10^-3 kg

putting the values...

r.m.s. = square root of ( 3 X 8.314 X 298/28 X 10^-3) = square root of ( 265454.143) = 515.2 m/s

Calculate vrms, the root mean square velocity, in m/s of SO2 molecules at (-3) oC.?

v(rms) = SQRT (3RT/M)

where:
v(rms) = root mean square velocity
R = gas constant = 8.314 J/mol*K
T = temperature = -3C + 273.15 = 270.15 K
M = molar mass SO2 (in kg) = 0.0641 kg/mol

Therefore,

v(rms) = SQRT[(3)*(8.314 J/mol*K)*(270.15 K)/0.0641 kg/mol] = 324 m/s

Calculate the root-mean-square speed of molecular chlorine in m/s at 41°C.?

Root-mean-square. speed of an ideal gas:
v (rms) = sqrt(3RT/M)
where R = 8.31 J K−1·mol−1 is the gas constant, T is the absolute temperature, M the molar mass.
T = 41 + 273 = 314°K
M(chlorine) = 0.071 kg·mol−1

v (rms) = sqrt(3×8.31×314/0.071) = 332 m/s