Can anybody solve macroeconomy question?
As a former lecturer in macroeconomics and present international economist, I guess I should rise to the challenge... First, before you can get started you need to close your model, because your teacher made it more "interesting" by dropping a couple of identities. Disposable income: DI = y - T (I assume y is GDP, which is normally the case in such models) ; Supply balance: y + IM = x + I + G + C. (G is government purchases) Now, you don't know what IM and x are, but you know that x - IM is -80. Also, you know that I is 320, so by rearranging the supply balance a bit you get: y = -80 + 320 + C + G Secondly, insert my DI definition in your first equation, next insert your first equation in the supply balance: y = 240 + 120 + 0.8*(y - T) + G Finally, insert the definition of T: y = 360 + 0.8*(y - (200 + 0.25*y)) + G Go figure that one out - it's your equilibrium GDP, specified as a function of G. The second question follows directly from the equilibrium GDP. Once you have y as a function of G all you need to do is to ask, if G changes by one unit, what happens to y. That's your multiplier. Finally, you just need to use this reduced equation to determine what level of G is consistent with y=1800 - that's the level of government consumption that, in classical Keynesian economics, would be recommended. That would be the minimalist answer to the third question. If you want to be smart you can vary the example with one where you change not only G but also the tax-rate (in your example it's 25% - the 0.25 you multiply with y). That will change the multiplier and, hence, the level of G that is needed for full employment. Have fun!
Can anybody solve this brainteaser question?
Hey thanks for posting this interesting and teasing question. The answer is !@#$%^&*().
Can anyone solve this question, 0÷1=?
The answer is 0 Because any number divided by 0 the answer will be 0
Can anybody solve this problem? passage viii question number 113,114 and 115 please give detailed solution for 113,114,115 ?
By inspection of the sample data, a = 20, b = 5 and c = 4.Rest is easy.Eccentricity [math]e^2 = 1 - \frac{b^2}{a^2}[/math]= [math]1 - (\frac{1}{4})^2[/math]= 15/16SO, e = [math]\frac{\sqrt{15}}{4}[/math]Focii are [math](\pm ae, 0)[/math]So, [math](\pm 5\sqrt{15}, 0)[/math]Length of Latus rectum is [math]2*\frac{b^2}{a}[/math]So, length of latus rectum is 5/2.(Note: There is no easier way to do this problem than by inspection. Take any three integers from the set, and add the (reciprocals of the)highest two integers to see if you can get the (reciprocal of the )lowest integer. Your fondness with numbers and “do it in your head” will be tested in solving this problem.)
Can anybody solve this problem?
Well, we are looking for a fence that is 120 inches long. I'm assuming that the pickets at each end are included in the 10 feet (120 inches). If so then we have 19 of them, each 3 inches, so that's 57 inches. So we have 63 inches left for the spaces between the pickets. As for how many spaces there are, there will be 1 less than the number of pickets. If this is difficult to work out, draw a fence with 4 pickets, and you'll see that there is 3 spaces in between, then add anther few pickets, and notice that there are still 1 less spaces than pickets. So, if we have 18 spaces and 63 inches, then each space is 3.5. I hope this helped, good luck.
Can anybody solve this math?
Mean of sampling mean = mean of population = 106. Standard deviation of sampling distribution = standard deviation of the population divided by the square root of the sample size = 12/√25 = 2.4 Sampling distribution is normal as population is normal, so calculate z-scores using the mean and standard deviation as given. Make sure you know how to do these--they are the bread and butter of sampling problems.
Can anybody solve this. I don't get it.?
1). -5(3x-7)= the bracket stands for multiplication,so you multiply everything in the bracket with the number outside it. -15x+35. 2). -4x2(3x2-x+1)= -8(6-x+1) Like i said the bracket stands for multiplication so you expand and remove brackets. = -48+8x-8 collect like terms. 8x-8-48= 8x-52. 3). Am not sure of numbers 3 and 4 5). (x-4)(x+8) remove brackets and expand multiply the two brackets together x^2+8x-4x-32= x^2+4x-32 6). Same thing with 5 2x^2-18x-5x+45 2x^2-23x+45 7). (3x+4)2= 6x +8 8). (5+x)(3-2x) 15-10x+3x-2x^2= 15-7x-2x^2 It can also be re-written as 2x^2-7x-15 9) (2x-3)(2x+5x-3)= 4x^2+10x^2-6x-6x-15x+9 =14x^2-15x+9 I might be wrontg cos I don't seem to get some of your questions right. But I hope it's right. stay blessed.
Can anybody solve this puzzle ?
you have returned 200 to X and Y and have to give 1300 (negative)that will be equal to your spending and lost (negative 1000+ negative 300)1300 contain your lost amount and spent on clothes. you are making fool by adding again (300) {lost amount + spent on clothes + spent on clothes} you are adding spent on clothes 2 times.
Could anybody solve this problem?
Let total no. of oranges she had initially = xI customer get := (x/2 + 1/2)= (x+1)/2Remaining oranges after first selling := x - (x+1)/2= (x-1)/2II customer get :={(x-1)/2}/2 + 1/2= (x+1)/4Remaining oranges after second selling := (x-1)/2 - (x+1)/4= (x-3)/4III customer get := {(x-3)/4}/2 + 1/2= (x+1)/8Remaining oranges after third selling := (x-3)/4 - (x+1)/8= (x-7)/8IV customer get := {(x-7)/8}/2 + 1/2= (x+1)/16Now total sell should be equal to the no. of oranges as she is not left with any orange.So,(x+1)/2 + (x+1)/4 + (x+1)/8 + (x+1)/16 = x(x+1)(15/16) = xx = 15so total no. of oranges she had initially = 15 (option C)
Can anybody solve this math problem??
For the first question the equation would be: p - 0.15p = p(1-0.15) = 0.85p For number #5 on the link: it is B because the slope of y is -4/3 and the y-intercept is 5 and the shade area is right side of the line y. The line is dashed and not whole because the line is not included, meaning < (less than) and not <= (less than or equal to).