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Can you guys help me in project?

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Can you guys help me with Kepler's law ?

So my teacher explains Kepler's 3rd law to be something like this
(Ta/Tb)^2 = (Ra/Rb)^3... The "/" represents a fraction not a division symbol. T represents time, and the R represents radius of from the sun to the planet. Or in official terms, the semi major/minor radius I guess.... Anyway I know this may not be current because there is an updated form of this but for the sake of this case let's use this.

The problem goes like this.

Pick a planet of your choice (other than the Earth) from the solar system. You can pick Pluto. You can look up distances here
Planet Distance from Sun in AU: Mercury 0.39, Venus 0.72, Earth 1.0, Mars 1.5, Jupiter 5.2, Saturn 9.5, Uranus 19.2, Neptune 30.1, Pluto (dwarf planet) 39.5.
Now, calculate the ratio of the orbital periods (time a planet takes to go around the Sun, once) of the Earth and the planet of your choice.

This is my work so far...

Mercury: .39
Neptune: 30.1

(Ta/Tb)^2 = (Ra/Rb)^3

(Ta/Tb)^2 = (.39/30.1)^3


I am stuck though I need help finding out the orbit time.

Can you guys help me? :)?

40 degrees, boy you complicate matters

Can you guys help me with algebra?

a radar system monitors a circular area approximately 450 square miles. which is closest to the radius of the circular area?
a.12 miles
b.25 miles
c.72 miles
d.140 miles

Can you guys help me solve this math hw ?

Often it necessary to rearrange an equation so that one variable is expressed In terms of others. For example the equation D =3t express D in terms of t. To express t in terms of D, divide both sides of this equation by 3 to obtain d/3 = t.
A) solve the equation c=2!r for r interns of C
B) solve the equation p= 2w + 2h for w in terms of p and h
C) solve the equation 3x -2y = 6 for y in terms of x

Can you guys help me with this Algebra Problem?

In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. If there were 45 baskets in a game and 96 points total, how many regular baskets r and long-distance baskets l were made? Show the correct system of equations.

Can you guys help me out with a Problem solving?

Let the width be x

(40- 2x) ( 30- 2x) is the area cut by Brad


Total area = 40 X 30 = 1200 square meters

So Brad has to cut 600 square meters

( 40 -2x ) ( 30- 2x) = 600

1200 - 60x - 80x +4x^2 = 600

4x^2 - 140x +600 = 0

x^2 - 35x + 150 = 0

( x-30) ( x-5) = 0

x = 30 OR 5

x cannot be 30

x = 5m ANSWER

CHECK
( 40- 10) ( 30-10) = 30X20 = 600 square meters

I don't know what my problem is. Can you guys help me figure it out?

1) The fact that you are not able to identify what your problem is your foremost problem.2) Secondly, you haven't asked a specific question. Others don't know the context of the problems - whether it's career or relationships, or something else. So, if you don't know to ask specific questions, then that's your second problem.3) Lastly, you have posted this question on Quora. Quora is somewhere people just follow questions, answers and people who answer questions well. So, people would hardly have any acquaintance with you, unlike FaceBook. So that's your third problem. You don't know where to seek solutions to your problems.

Can you help me, guys? A weight rod fell on my iPhone 6 S plus while I was in gym. It's mute button got suppressed and I am not able to unmute the phone. Is there any way I can unmute the phone with help of software since the button is broken?

Yes you can with the use of Assistive Touch ButtonHere's the procedure to enable the assistive touchSettings ➡️ General ➡️ Accessibility ➡️Assistive TouchEnable the Assistive touch toggleOnce enabled you will see a virtual home button like structure on the either sideways of your screenFor Mute/UnmuteAssistive Touch Button ➡️ Device ➡️ UnmuteThis is how you can virtually operate the functions of physical buttons

Guys can you help me on my electromagnetics homework?

A)
r < a
E 4 π r^2 = 4 π r^3 ρ / (3 εo)
E = ρ r / (3 εo)
r = a
E 4 π a^2 = 4 π a^3 ρ / (3 εo)
E = ρ a / (3 εo)
r > a
E 4 π r^2 = 4 π a^3 ρ / (3 εo)
E = ρ a^3 / (3 εo r^2)

B)
r < a
V = 1 / (4 π εo) ∫ dq / r = (ρ / εo) ∫ r dr
V = ρ r^2 / (2 εo)
r = a
V = 1 / (4 π εo) ∫ dq / r = (ρ / εo) ∫ r dr
V = ρ a^2 / (2 εo)
r > a
V = q / (4 π εo r)
V = ρ a^3 / (3 εo r)

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