I need help on how to understand algebraic rule of an equation?
To find the rule:Step 1: Find slope, m, using formula for slope: (Y-y)/(X-x).Take 2 points,(0,0) & (20,10) and plug them into formula: (10-0)/(20-0)=10/20 = 1/2Step 2: Find b , using formula y = mx+bTake m=1/2 and one point, (0,0) and put them in formula:0 = 1/2(0) + b --> 0 = bSo b= 0, m= 1/2. Plug these into y=mx+b. y = (1/2)x THAT IS THE RULE. ---Fill in the table:For the first y value solve y = (1/2)(-4) --> y = -2For the next x value solve 5 = (1/2)x --> x = 10You try the rest....If you have trouble comment. x should always be twice y.
Will you help me understand supply and demand equation in solving for equilibrium price?
You can think of this as an algebra problem with two unkowns and two equations. You don't know the market clearing price or quantity. You do know that QS will equal QD in equilibirum. Solve by substitution: QD = 100-2P QS = 5+3P QD=QS ==> 100-2P=5+3P ==> 5P = 95, P=19
I dont understand quadratic equations can you help me solve these questions?
Hey Mo, Please follow the link I've provided you; it will give you the quadratic formula. a is the coefficient of x^2, b is the coefficient of x, and c is the constant. I'm confused if the first equation is equal to 16 or 36. Thus, I'll show you how to do the rest: For #2, x^2-2x-44=0. a=1, b= -2, c= -44. Plugging these into the quadratic equation, we get 2 possible values of 7.71 and -5.71. For #3, x^2-10x-11=0. a=1, b= -10, c= -11. Plugging these in, we get 2 possible values of 11 and -1. For #4, x^2-4x+1=0. a=1, b= -4, c=1. Plugging these in, we get 2 possible values of 3.73 and .268. For #5, 3x^2-6x+11=0. a=3, b= -6, c=11. For the discriminant formula, check out the other link I provide. The value of the discriminant will be -96. I hope this helps. Best, David
Help balance equation and help me understand how to do it..?
ok look i'm in gr. 11 chemistry and this stuff is very simple we did it last year... i'll help u out if u need it :D lol ok so ur equation is as follows: Li3PO4 + Zn(NO3)2 ----> LiNO3 + Zn3(PO4)2 now to balance it... you look at each of the individual elements on each side (start wit the left reactants side) and then make sure there are the same number of atoms/molecules (if diatomic) on each side... so start like this: Li3 ---> Li (so you need to put a 3 in front to make it balanced) therefore Li3 ---> 3Li (MAKE SURE YOU PUT IT INFRONT and you're not adding subscripts!!!! because you can't do that!) ok... so next one since PO4 is a polyatomic ion.. you treat it as a whole (that's why we use brackets sometimes when we need to criss-cross the charges... ok i hope you get the idea.... i'm not gonna go through the whole thing step-by-step... but if u have questions u can e-mail me :D your final equation will be: 2Li3PO4 + 3Zn(NO3)2 ----> 6LiNO3 + Zn3(PO4)2 this is a particularly more challenging one...but it's the same idea... you just need to think a little harder and VOILA :D good luck and i hope this helped! :)
Can someone please help me understand linear equations?
So.... when degrees = 21, calories = 3000 It says that when the temp drops 1 degree, the calories increase by 30. So... if degrees = 20, calories = 3030 Degrees would be your x value Calories would be your y value So, you have two points (21, 3000) and (20, 3030). a) you know if varies linearly because each variable changes at a constant rate. (If you drop Degrees by 1 degree, Calories increases by 30. Therefore if you drop degrees by 10, calories increases by 300.) Since you have two points (the two I gave above), you can write an equation. Slope = (3030 - 3000) / (20 - 21) = 30 / (-1) = -30 Using point-slope form: y - 3000 = (-30)(x - 21) y - 3000 = -30x + 630 y = -30x + 3630 b) Remember temperature is X, Calories is Y. So... Sahara = 50 Degrees so, x = 50 Plug that into the equation from part a. y = -30(50) + 3630 y = -1500 + 3630 = 2130 Antartica = -50 degrees so, x = -50 You can work this one out to find y. (Just like the Sahara example I did.) c) If you want to use NO CALORIES, that means y = 0 so... 0 = -30x + 3630 solve for x.
Can someone help me solve the equation: [math]x^2-22=0[/math] ?
To solve any equation like this, you need to understand the order of operations and understand exactly what these symbols mean. Basically, the left hand side IS the right hand side. You're dealing with one number right now: 0. Or put another way[math]x^{2} - 22 = 0 [/math].The next thing you need to recognize is that [math] x^{2} [/math] is just short-hand for multiplication. That little "2" just means that x is multiplied to itself two times, i.e.[math] x^{2} = x \cdot x [/math]To illustrate this further [math] x^{5} = x \cdot x \cdot x \cdot x \cdot x [/math]There are 5 x's multiplied to themselves. Then you have to understand that multiplication is just short-hand for addition, i.e.[math] x \cdot x = \underbrace{ x + x + x + \ldots + x}_{x \mbox{ times}} [/math]So basically [math] 3 \cdot 5 = 3 + 3 + 3 + 3 + 3 = 15 [/math]So really, this problem boils down to addition and subtraction.[math] x^{2} - 22 = \underbrace{x + x + x + \ldots + x}_{x \mbox{ times}} - 22 = 0 [/math]Notice that this is still just one number: 0. So what can we do with all these addition signs? Well, we can add 22 to both sides:[math] x^{2} -22 = 0 \longrightarrow x^{2} = 22 [/math]Now we want to know what x equals all by itself. But how do we do that when we know that [math] x^{2} [/math] is really a bunch of x's added to itself? We can't subtract here! We don't know what x is yet!Here, we need to use a little imagination and some backwards reasoning: What number, squared, gives me 22? Off the top of my head, I don't know. Nor should I know. The number is irrational and goes on forever without order! Instead of that, we use a short-cut and call it [math] \pm \sqrt{22} [/math], i.e. the square root of 22 keeping in mind the plus or minus, since a negative number times a negative number is a positive number.Thus: [math] x = \pm \sqrt{22} [/math]Ask your teacher how much simplification he/she requires because you may want to break it down into its prime factors, in which case:[math] x = \pm \sqrt{2} \cdot \sqrt{11} [/math]Thanks to Omkar Londhe for catching it: it is plus or minus square root of 22. I had a brain fart there.
Can someone help me with this equation:
X ∙ (x + 6) + 8x = 2 ∙ 4XX(X+6)+8X=8XX(X+6)=0X =0 or X=-6Also get help in Algebra 2
I don't understand how to solve this problem at all.?
The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation h(t)= -16t^2 + 60t. At what times will the object be at a height of 56 feet? Can you help me at least set up the equation so I can solve it? I don't know how to solve this!
No matter what I do, I can't seem to understand equation graphing. Why?
You’re having a hard time because math is taught as an academic subject rather than a practical one, and graphing an equation is a practical use. In addition to helping us solve for x, equations describe the way something changes as x changes. The graph shows the value of y, at each value of x. Pick a value of x, go upward until you hit the line, then go left until you hit the Y axis. That’s the answer to the equation for that particular value of x.Let’s look at the equation of a straight line y = mx+b. Just picking some random numbers to plug in, we have y = 2x + 5. What does this tell us? It says that when x is zero, y = 5. This is important when graphing as that’s the value on the y axis. The slope, 2, tells us what happens when we step forward or backward in x. At x = 1 (mx = 2*1 = 2), we take 2 steps up from where we were at zero (5+2 = 7). At x=2, (mx = 2*2 = 4) we go up 4 steps (4 + 5 = 9). If we step x to the left, we go downward.Does this help?
Someone please help me understand the following:?
I agree with changing Cot(Theta) into Cos(Theta)/Sin(Theta) sqrt(3)*Cot(Theta) = 2*Cos(Theta) sqrt(3)*Cos(Theta)/Sin(Theta) = 2 * Cos(Theta) sqrt(3)/2 = Sin(Theta) Theta = pi/3 and 2pi/3, or 60 degrees and 120 degrees.