Chemistry Help?
1.) (8.90 × 10^23 atoms) / (6.022 × 10^23 atoms/mol) × (26.98154 g Al/mol) = 39.9 g Al 2.) (516.8 g CCl4) / (153.8227 g CCl4/mol) x (1 mol C / 1 mol CCl4) x (12.01078 g C/mol) = 40.35 g C 3.) (1.75 × 10^24 atoms) / (6.022 × 10^23 atoms/mol) = 2.91 mol
Chemistry Help?
1. Hydrogen sulphide ( sulfide - american spelling) 2. Ammonium acetate 3. Iron (II)chloride 4. Barium hydroxide 5. Mercuric (II)iodide 6. Sodium phosphate 7. Phosphorous pentachloride 8. Sodium sulphate ( sulfate - american spelling) 9. Aluminium cyanide 10. Copper (II)nitrate Hope that helped... PS- I am sure all the above is right! PSS- The II stands for the valency of metals. for eg. iron has two valencies +2 or +3. here the valency of the above mentioned metals are +2
Chemistry Help!?
A) If a 12.9 cm3 sample of lake water is found to have 160.9 ng As, what is the concentration of arsenic in the sample in parts per billion (ppb), assuming that the density of the lake water is 1.00 g/cm3? B)One of the volunteers suggests hiring an on-site water treatment company to remove the arsenic from the lake. The company claims their process takes 2.08 days to remove 35.60 kg of As from a water source. b) Calculate the total mass (in kg) of arsenic in the lake that the company will have to remove if the total volume of water in the lake is 0.450 km3. C)Based on the company\'s claim and the concentration of arsenic in the lake, how many years will it take to remove all of the arsenic from the lake, assuming that there are always 365 days in a year?
Chemistry help?
A competition experiment involves O2 and CO vying for hemoglobin (Hb) sites, defined by the equilibrium Hb(O2)4 + 4 CO --> Hb(CO)4 + 4O2 <-- Where --> signifies an equilibrium. <-- From Le Châtelier's principle, how is CO poisoning (too much CO bound to the Hb) reversed? a. decrease the amount of O2 available b. increase the amount of O2 available c. remove Hb
CHEMISTRY HELP!!!!!!!!!!!!! EASY 10 PTS?
balanced equation .. 1 Zn + 2 HBr ---> 1 ZnBr2 + 1 H2 if Zn is the limiting reagent, this much H2 is formed .. 5.00g Zn * (1 mol Zn / 65.68g Zn) * (1 mol H2 / 1 mol Zn) = 0.07648 mol H2 but if HBr is the LR, then this much H2 is formed .. 35.0mL HBr * (1L / 1000mL) * (4.00 mol HBr / L HBr) * (1 mol H2 / 2 mol HBr) = 0.07000 mol H2 since HBr gave less H2, it must be the LR and 0.07000 mol H2 is formed then .. PV = nRT .. P = nRT/V = (0.07000mol H2) * (0.08206 Latm/molK) * (298K) / (1.50L) = 1.14 atm
CHEMISTRY HELP (Recommend sites)!!!?
I need help in Chemistry, this is a new subect for me this year and IM totally lost, so I hoped someone could help me (by msn (I use this one the most) or yahoo msn, or could recommend me a site with tutotrials, info, work problems, etc. -Nomenclature -Limitin reagent problems
Chemistry help??!!10 pnts for best answer!!
go 2 afn.org library.duke.edu carnegielibrary.org tutorvista.com go.hrw.com garfieldlibraries.org pbclibrary.org greenvillelibrary.org members.aol.com groups.yahoo.com redesk.com gethomeworkhelp.com susexcountylibrary.org thinkquest.org southplainfield.lib.nj.us ocbc.org thehomeworkhelp.com voy.com microstsoft.com ct4me.net whatthehomework.com amazon.com thiz helped 4 me