What if I put Rs. 500 in my chemistry answer sheet in a board examination?
When I was in class XI, our chemistry teacher was briefing us about the type of question paper that used to come in the board, then all of a sudden she started smiling. When asked about the reason, she decided to tell us as it was our free period (time when the whole syllabus was complete). She told us-“It was way back in 2007, when I was checking the board copies, amongst the whole lot, the next answer sheet that I picked up was light weighted and contained no extra sheets. Initially I was surprised but had a hope that the child must have written that much that she /he scored passing marks .”“I opened the answer sheet and wooo!! Blank sheet, further filled by the lyrics of Nothing's Gonna Change My Love For You and a crisp Rs 500 note giving the excuse that stated “Respected Ma'am/Sir, as I was busy with my sister's wedding I was unable to study for the exam, I request you to kindly grant me passing marks” and I was rolling on the floor laughing!”Then what?The whole group of teachers ordered samosas and chai and needless to say, the child failed.
Chemistry question. need answer now. pls. help!!!!!!!?
five darts strike the center of the target. Whoever threw the dart is a. accurate, not precise b. both accurate and precise c. precise, not accurate d. neither precise nor accurate pls. choose one of these answers. thanks!!!!
Chemistry Question Needs to be answered?
molar mass Na3PO4 x 7 H2O = 163.94 + ( 7 x 18.02)=290.08 g/mol moles Na3PO4 x 7 H2O = 9.4 / 290.08 g/mol=0.0324 moles water = 7 x 0.0324 = 0.267 V = nRT/p = 0.267 x 0.08206 x 373 K/ 1.00=6.94 L
Chemistry help!!!!!!!! NEED NOW PLEASE?
PV=nRT (735 torr) * (23.5 L) = n * (62.3636 L*torr/ mol*K) {the R value for torr} * (304.15 K) {not C} n= .91061794249 mol n/ L = molarity .91061794249 mol / .750 L = 1.21415725666 M sig figs 1.2 M
CHEMISTRY problem, I need help NOW?!?
232Th 90 ultemately changes to 208Pb82. Loss of one alpha particle woll results in loss of mass by 4 units and atomic number by 2 units. Loss of mass = 232 - 208 = 24 24 units of mass will be lost if 6 alpha particle are lost.from Th. Loss of 6 alpha particles will results in loss of atomic number by 12 units (2x6). So the atomic number should be 78 (90 -12 = 78). But atomic number is 82. it is possible if 4 beta particles are lost (78+4=82). 232Th90 ------> 208Pb82 + 6 4He2 + 4 e-
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You have 485 ml of a 0.125 M HCL solution and you want to dilute as much as possible of it in one dilution to 0.100 M. Describe the procedure taken. (Remember how to use the volumetric flasks, which come in sizes on 10.00 mL, 50.00 mL, 250.00 mL, 500.00 mL, and 1.00 L.)
CHEM QUESTIONS NEED TO BE ANSWERED NOW?
PLEASE DON'T BE INTIMIDATED BY HOW LONG THIS IS! JUST ANSWER THE MOST YOU CAN :) These are chapter 19 Review Questions in Modern Chemistry Texbook: 22. If a strip of Ni were dipped into a solution of AgNO3,whatt would be expected to occur? Explain, using E^0 values. 23. a. What would happen if an aluminum spoon were used to stir a solution of Zn(NO3)2? b. Could a strip of Zn be used to stir a solution of Al(NO3)3? 31. A voltaic cell is made up of a cadmium electrode in a solution of CdSO4 and a zinc electrode in a solution of ZnSO4. The two half-cells are separated by a prous barrier. a. What is the cathode, and which is the anode? b. In which direction are the electrons flowing? c. Write balanced equations for the two half-reactions, and write a net equation for the combined reaction. These areSupplementt Questions: S3) A cell is based on the reaction Ni(s) + 2Ag+(aq) = Ni2+(aq) + 2Ag(s) What would be the effect on the cell voltage if: a.) some AgNO3 was dissolved into the solution around the silver electrode b.) some NiSO4 was dissolved into the solution around the nickel electrode c.) Ag2S was precipitated out of the system by adding H2S to the Ag+/Ag(s) half of the cell? S4) The E^0 value for the half-reaction Ag(s) = Ag+(aq) + e- as written is -0.80 volt. What would happen to the measured half-cell value (H+/H2 reference) if a salt solution (NaCl) was added to the solution around the silver electrode? Which one of the following values would be most reasonable: -0.40 -0.80 -1.20 Explain your answer
Need help on these chemistry questions! Need answers now. Please.?
I really need help with these chemistry questions. I need the answer and a reason on how I solved the question. 1. You have a 23-g sample of ethanol with a density of 0.7893 g/mL. What volume of ethanol do you have? 2. Complete the following problems in scientific notation. Round off to the correct number of significant figures: (5.31X10^-10cm)X (2.46X10^5cm) (3.78X10^3m) X (7.21X10^2m) 3.Evaluate the following conversion. Will the answer be correct? Explain: Rate= 75m/1s X 60s/1min X 1h/60min 4. Three students use a meterstick to measure a length of wire. One student records a measurement of 3cm. The second records 3.3m. The third records 2.87cm. Explain which answer was recorded correctly. 5. Express each quantity in the unit listed to its right a. 3.01 g cg b. 6200m km c. 6.24 X 10^-7g ug d. 0.2 L dm^3 e. 0.13 cal/g kcal/g f. 3.21 mL L
I need help with chemistry right now. Please.?
A piece of aluminum foil is 0.0150 cm thick. I need to calculate the thickness of the aluminum foil in terms of the Number of aluminum atoms. The aluminum atoms are spheres with a radius of 143 pm, and i need to assume that they are stacked one on top of another. please help me. i know that 1 pm is equal to 10 to the -12 m
I need some help with this chemistry problem. I ve already taken care of the balanced chemical equation, but have no idea what to do now.?
Write the balanced reaction between magnesium and oxygen to create magnesium oxide and calculate the true value for this heat of combustion using the heats of formation values from your textbook found in Appendix 3. Please show all work. Your final answer should be in kJ/1mole of magnesium. According to my textbook, the heat of formation is -601.8 jK/mol, but I have no idea what to do with it.