Consider the balanced equation below. Which of the following correctly expresses the rate of reaction with re?
Can someone explain how to do these two problems? Consider the balanced equation below. Which of the following correctly expresses the rate of reaction with respect to [SO2]? 2 SO2 (g) + O2(g) → 2 SO3(g) A) Rate = -1/2 (Δ[SO 2] /Dt) B) Rate = +1/2(Δ[SO 2] /Δt) C) Rate = -Δ[SO 2] /Dt D) Rate = +2 Δ[SO 2]/Δt E) It is not possible to determine without more information. The decomposition of dinitrogen pentoxide is described by the chemical equation 2 N2O5(g) → 4 NO2(g) + O2(g) If the rate of disappearance of N2O5 is equal to 1.60 mol/min at a particular moment, what is the rate of appearance of NO2 at that moment? A) 0.800 mol/min B) 1.60 mol/min C) 3.20 mol/min D) 6.40 mol/min
Consider the reaction: C3H8(g)+O2(g)→CO2(g)+H2O(g). HELP with moles PLEASE!!!!?
Look at your coefficients. 1 mol of propane reacts with 1 mol of O2. So 2.5 mol of propane will react. Same for part B. It's a 1:1 ratio between O2 and CO2. So 2.5 moles of CO2 are produced. JUST KIDDING IT'S NOT A BALANCED EQUATION. Hold on a sec! Edit: so I typed that assuming it was balanced and everything was a 1:1 ration. But it's not. A balanced reaction equation would be: C3H8 5O2 --> 3CO2 4H20. So for every mol of propane, 5 moles of O2 gas reacts, right? therefore, 2.5 mol O2 * (1 mol propane/ 5 mol O2) = 0.5 mol C3H8. For part B, consider what your limiting reactant is. Your C3H8 only produces 0.5 mol for every 2.5 mol of O2, so it is your limiting reactant. Therefore, 0.5 mol C3H8 * (3 mol CO2 / 1 mol C3H8) = 1.5 mol CO2!
Consider the reaction described by the following equation.?
Consider the reaction described by the following equation. C2H4Br2(aq)+3I-(aq)------>C2H4(g)+2Br-(... The rate law is: rate=k[C2H4Br2][I-] Where k=4.27x10^-3 M-1 x S-1 What are the missing entries in the following table? Initial rate of information Run [C2H4Br2]0(m) [I-]0(M) of C2H4(Ms-1) 1 x 0.221 0.000834 2 0.221 y 0.000417 3 0.221 0.221 z x=_________M y=_________M z=_________Ms-1 Please explain! I need to understand this!!!!! :(
2HCl + Na2CO3 → 2NaCl + H20 + CO2
Chemistry Question. Consider the reaction A+B->products?
Consider the reaction A + B → products From the following data obtained at a certain temperature, determine the rate law, the order of the reaction, and calculate the rate constant k. Experiment 1: [A] = 0.010 M; [B] = 0.025 M; Initial Rate = 2.4 x 10-6 M/s Experiment 2: [A] = 0.005 M; [B] = 0.025 M; Initial Rate = 1.20 x 10-6 M/s Experiment 3: [A] = 0.010 M; [B] = 0.0125 M; Initial Rate = 0.60 x 10-6 M/s A. Rate = k[A][B] order of reaction = 2 k = 0.0096 /M2•s B. Rate = k[B]2 order of reaction = 2 k = 0.0038 /M2•s C. Rate = k[A][B]2 order of reaction = 3 k = 0.38 /M2•s D. Rate = k[A]2[B] order of reaction = 3 k = 0.96 /M2•s
In the most basic form, it is: 6CO2 + 6H2O = C6H12O6 + 6O2.The carbon from the inorganic carbon dioxide molecule is assimilated into the glucose molecule, while the oxygen in the water molecule becomes a part of the released oxygen.Here’s a helpful diagram showing the inputs and outputs to the light and dark reactions:
When acetic acid is added to water, due to electronegativity differences of oxygen and hydrogen in —OH group of acetic acid and dipole interaction with water molecule, the acetic acid is transformed into acetate ion and H+ ion which furthur combines with water to form hydronium ion. The reaction is —The mechanism can be represented as —Hope it helped !!
The molecular formula of octane is C8H18.The combustion of a hydrocarbon produces carbon dioxide and water. Thus the combustion of octane is given by -C8H18 + O2 ---> CO2 + H2OTo balance this equation, we need to balance the atoms on the left and right hand side. Octane has an excess of C and H and we use it as a reference. There are 8 carbon atoms and 18 hydrogen atoms in an octane molecule. Thus there should be 8 carbons and 18 hydrogens on the right, which is obtained by a prefix of 8 for CO2 and 9 for H2O.C8H18 + O2 ---> 8CO2 + 9 H2ONow we have to balance the oxygen atoms. On the right side, there are (8X2)+9 = 25 atoms. Thus we can balance the oxygen atoms by putting a prefix of 25/2 on the left side.C8H18 + 25/2 O2 ---> 8CO2 + 9 H2O.To obtain a equation containing whole numbers, we multiply the entire equation by 2. This gives the final equation.2 C8H18 + 25 O2 ---> 16 CO2 +18 H2O.
Propane ( C3H8 ) will burn completely when it combines with the oxygen (O2) in air to form carbon dioxide (CO2) and water (H2O). The equation looks like this: C3H8 + 5O2 ---> 3CO2 + 4H2O The heat generated in the exothermic reaction causes more and more propane to "break apart" and combine with oxygen in air to produce the end products carbon dioxide and water. This will continue until the concentration of propane in air falls below a "threshold" and not enough heat is generated to support the combustion of any remaining propane. There is enough oxygen in air in an open space to support the combustion of an extremely large volume of propane.