Does anyone know about Start10 app?
Start10 app is an app/program/software designed to give the users Windows 7 styled Start Menu. It replaces the original Windows 10 Start Menu with this new Start10 named Start Menu.It is for those Windows lovers who want to have feel of Windows 7 in Windows 10 to make their everyday lives easy with their windows. It is one of the good app but very expensive. I hope to see some cool stuff like Start10 in market soon.
Does anyone know how to move apps from Samsung Galaxy Tab A 10" to Samsung drive, Google cloud drive, Microsoft OneDrive, and Amazon drive?
I'm trying to download books from Google play books app and Amazon Kindle app. But I'm running out of internal and external storage space. I don't know what else to do. Can someone help me?
Does anyone know some good websites or apps to download free books to iBooks?
IBooks is like iTunes. You can buy books there. Many times the App is free but the items there are not free. Remember that authors write books to sell. They generally can't afford to give the books away for free. The following sites are FREE and LEGAL.
Anyone know of any apps that give you money?
Other than freeeats.com that pays you a dollar to your paypal for signing up (must link your paypal account to your phone number to do so), are there any other sites /apps that can give you money ? Survey sites like Inbox Dollars don t do it for me. They only pay you a few cents. Some of the surveys you take, u dont qualify for. Huge waste of time, that site...Anyone know of any good apps you can install on your phone/websites that give u money legitimately ?
Is anyone any good at...?
Well, you have to use the formula A = P ( 1 + r/n ) ^ (nt) A = final amount of money P = money you start out with r = interest rate (must be in decimal form) t = time in years n = number of times compounded per year So, first, you would plug in your numbers. You then get: 1000 = 500 ( 1 + .06/2 ) ^ 2t Then divide each side by 500. 2 = ( 1 + .03 ) ^ 2t Then you do the logs. log (1+.03) 2 = 2t (the (1+.03) is supposed to be below) log 2 / log (1.03) = 2t 23.44977225 = 2t Then divide both sides by 2. 11.72488613 = t