During the first part of a trip, a canoeist travels 28 mi at a certain speed?
let x = time to travel 28 mi let y = time to travel 9 mi x + y = 3 let a = speed going for 28 miles ax = 28 a = 28/x (a - 5) * y = 9 ay - 5y = 9 ay = 9 + 5y a = (9 + 5y) / y 28/x = (9 + 5y) / y 28y = x(9 + 5y) 28y = 9x + 5xy x + y = 3 y = 3 - x 28(3 - x) = 9x + 5x(3 - x) 84 - 28x = 9x + 15x - 5x^2 5x^2 - 52x + 84 = 0 (52 ± √1024) / 10 (52 ± 32) / 10 x = {2, 8.4} ignore the larger answer, since both times added can only equal three, this makes no sense) x = 2 hours y = 1 hour ax = 28 2a = 28 a = 14 mph for 28 mi 9 mph for 9 miles
During the first part of a trip, a canoeist travels 41 miles at a certain speed. The canoeist travels 23....?
t = d/v so let v = speed on first part of trip v - 5 = speed on second part of trip total time = 2 hours = 41/v + 23/(v - 5) multiply through by v(v - 5) 2v(v-5) = 41(v-5) + 23v 2v^2 - 10v = 41v - 205 + 23v 2v^2 - 10v =64v - 205 2v^2 - 74v + 205 = 0 using the quadratic formula with a = 2, b = -74, c = 205: v = 33.98 mph (call it 34mph for first 41 mile part) v - 5 = 28.98 mph (call it 29 mph for second 23 mile part) 41/34 = 1.206 hours 23/29 = .793 hours total = 2 hours (within rounding errors)
How many miles can I travel by boat in a day?
What kind of boat? There are different types….CanoeSailing frigateOceanlinerBattleshipEkranoplan
If an object is moving at the speed of 36 kilometers per hour, how many meters does it travel in one second?
Moving at 36,000 meters per hour you have given me.So there are 3600 seconds per hour (60 minutes per hour and 60 seconds per minute),so divide by 3600 to get meters per second.Looks like … 10 meters per second.
If a boat is moving upstream with a velocity of 14 km/hr. and goes downstream with a velocity of 40 km/hr., then what is the speed of the stream?
Let the velocity of the boat be b and that of the current in the stream be s.Velocity of the boat while going upstream = [math]b - s = 14 km/hr .....(1) [/math]Velocity while going downstream = [math]b + s = 40 km/hr ...........(2)[/math]Subtracting equation (1) from equation (2), we get :-[math]2s = 26 km/hr => s = 13 km/hr.[/math]Thus, the speed of the current in the stream is 13 km/hr.You could check out the following info-graphic for tip on solving Problems on Boats and Streams :-You may also be interested in these Aptitude Test Questions on Quantitative Aptitude, Reasoning Questions and English Grammar
Algebra Distance Rate Time Word Problems ?
O K, one the first on. Try to visualize two balls rolling dow a slope, one rolling faster than the other. The distance between the balls gets further, the longer the balls roll. That's what the car problem is. If car "A" travels 32 miles in the first hour and car "B" travels 47 miles in that same hour, they will be 15 miles apart. In the second hour the distance apart will be 30 miles, 45 miles after 3 hours, etc. To do this mathematically: car A = 32m/1h car B = 47m/1h remember: distance = rate * time d = rt lets substitute: 69 m = (B - A) t the rate is the difference in speeds of the 2 cars. 69 m = (74 m/1h - 23 m/1h) t 69 m = (15 m/1h) t Divide by "M" for simplicity 69 = 15/1h * 4.6 = 1/1h * t multiply by h (hours) 4.6 hrs = 1t t is the symbol used by us for "time" so the time it tkes for the distance to increase to 69 miles is equal to 4.6 hours. I know this is long, but if you can understand it, it's really kinda easy. good luck, bandit