Electrochemistry help?
Shown below is a galvanic cell with anode compartment b containing anode a and cathode compartment d containing cathode c. Electrons flow through wire f, ions flow through salt bridge e, and the cell potential is read using voltmeter g. This galvanic cell uses the reaction: Cu(s)+2Ag+(aq)→2Ag(s)+Cu2+(aq) Identify the electrodes and the direction of electron flow. A. a is Ag, c is Cu and electrons flow from a to c. B. a is Ag, c is Cu and electrons flow from c to a. C. a is Cu, c is Ag and electrons flow from a to c. D. a is Cu, c is Ag and electrons flow from c to a.
Electrochemistry help?
STANDARD CELL NOTATION: 1. The anode is always written in the left side of the || 2. States are separated by a |; species of a common state are separated by a comma 3. The salt bridge is represented by || Reaction is: 2Al(s) + 3Co2+(aq) ====> 2Al3+(aq) + 3Co(s) Al is the anode: Answer is: C. Al(s) | Al3+(aq) || Co2+(aq) | Co(s) Answer is:
Electrochemistry Help?
The molar masses of HgO and Zn are: 216.59 g/mol and 65.38 g/mol, respectively. Hence HgO is the limiting reactant, and it has: (1.60g)/(216.59 g/mol) = 0.007387 mole Assuming the reaction can be completed, this amount of HgO can be lasted for: 0.007387*96485*2/0.30e-3 = 4.752e6 (s) = 1320 (hr)
Electrochemistry help please?
2NaCl(aq) + 2H2O(l) --> 2Na+(aq) + Cl2(g) + 2OH- + H2(g) anode:oxidation: 2Cl-(aq) -2e- --> Cl2(g) cathode:reduction: 2H2O(l) + 2e- --> H2(g) + 2OH-(aq) the reaction on the cathode is such be cause it takes less energy to reduce water than Na+ to Na n(NaCl(aq))/n(OH-(aq))= 2/2 --> n(NaCl(aq))= n(OH-(aq)) OH-(aq) + HCl(aq) --> H2O(l) + Cl-(aq) n(OH-)/n(HCl)= 1/1 --> n(OH-)= n(HCl) c= n/V --> n= c*V n(OH-)= c(HCl)*V(HCl)= 0,15 mol dm^-3 * 18,25*10^-3 dm^3= 2,74*10^-3 mol n= Q/(z*F) --> Q= n*z*F= 2,74*10^-3 mol * 2 * 96500 Asmol^-1= 528,82 As (z= 2 be cause it takes 2 electrons to convert water to OH- and H2) Q= I*t --> I= Q/t= 528,82 As / (10*60) s= 0,88 A ;) ps if you need or if you're interested in further explanation i'll be glad to elaborate it
Electrochemistry Help me please!!!?
In the following, "d" = delta (change) dGo = - n F Eo There are 10 mol e- gained and lost, n = 10. 1 Volt = 1 joule/coulomb = 1 J/C dGo = - 10 mol x 96,500 C/mol x 0.54 J/C (volt) dGo = - 521,100 J = -521.1 kJ or -520 kJ (2 sig figs)
Electrochemistry? AP Chemistry help, please?
During the discharge of an alkaline battery, 19.3 g of Zn are consumed at the anode of the battery. What mass of MnO2 is reduced at the cathode during this discharge? I missed class and I'm not sure how to solve this problem. Can you please show all your work and how you solved? Thanks so much!
What are the effects of electrochemistry in life?
While the effect is hard to discern, electrochemistry plays a major role in many industrial processes that are central to modern life. A non-exhaustive list is given below:Industrial electrolysis (ex. Al, Zn, Ni, Cu, Mg, Cl2, H2 ++)Batteries both primary (single-use) and secondary (ex. rechargeable, Li-ion, Ni-MH, Ni-Cd, Lead-acid)Electroplating (ex. anodic corrosion protection, i.e., Zn sacrificial anode)Electrowinning (ex. purification of Cu)Fuel cells (ex. PEM fuel cell, SOFC, AFC)Electrochemical sensors (ex. penicillin, glucose, CO)Through these examples, it is clear that electrochemistry has a major effect on life.
How should I tackle electrochemistry of IIT JEE?
Let me try to answer the question now.If u have a good teacher to teach you..go for it.seek his help with concepts... because it is a ‘seemingly more difficult to understand ’ chapter.It's really easy once you get thorough with the concepts.So first of all seek some expert help in understanding the concepts.If u don't have a good teacher to ask, go for YouTube.Some famous teachers have their lessons uploaded.. it'll probably help.Lastly..if you are unable to understand even after following these steps ..leave it.. complete other chapters..come again afresh at last and try once more. But esa bilkul mat hone Dena ki sirf is topic ko strong krne k liye baaki easy topics Jo abhi class me chl rhe h unhe miss Kar do.And ek free advise…if u wanna conquer your weak concepts..never ever hesitate to ask doubts.Hopefully it will helpA request:pls tell the medium u have for studying..
Shorthand notation/electrochemistry help?
For the galvanic cell reaction, expressed below using shorthand notation, what half-reaction occurs at the cathode? Zn(s) | Zn2+(aq) || Fe 2+(aq) | Fe(s) A. Zn2+(aq) + 2 e- → Zn(s) B. Fe(s) → Fe 2+(aq) + 2 e- C. Zn(s) → Zn2+(aq) + 2 e- D. Fe 2+(aq) + 2 e- → Fe(s)