How do you find the average speed and average velocity on a position vs time graph?
Hi, for average velocity differentiate the curve and put the value of and put the value of the point i.e., position and time in the differential equation to calculate the value of velocity. for average speed simply divide the difference in position with the difference in time, i.e (position at the point - position at time = 0) divided by (time at the point - 0) Hope this is helpful, keep smiling, bye.
Find the average speed?
The distance/rate/time formulas: D = RT R = D/T T = D/R Problem 1: R = D/T R = 780/2 R = 390 mph Problem 2: R = D/T R = 1.2 / 0.25 R = 1.2 * 4 R = 4.8 mph Problem 3: R = 3 / (2/3 hour) R = 3 * 3/2 R = 9/2 R = 4½ kph Problem 4: R = 1440 / (3 * 24 hours) R = 1440 / 72 R = 20 mph Problem 5: R = 115 / 2.5 R = 115 / (5/2) R = 115 * 2/5 R = 230 / 5 R = 46 pages per hour Problem 6: R = 6 acres / 4 hours R = 3/2 = 1½ acres per hour
Math question on average speed?
The airliner concorde flies 2000km at a speed of 1600km/hr and then returns due to bad weather at a speed of 1000km/h find the average speed for the whole trip Please show steps
Find the wave's frequency & average speed?
The relationship between propagation speed (c), frequency (ν), and wavelength (λ) for all waves is: c = λ*ν so ν = c/λ In this case,: ν = (4900 m/s)/(2400 m) = 2.04/s = 2.04 Hz The period of the wave (T, the time it takes to complete one cycle) is: T = 1/ν, so in this case, T = 1/(2.04/sec) = 0.49 sec If the amplitude of a wave is A, then the total distance that a particle in the medium travels in one complete cycle of the wave is 4*A, and it does this in one period. (Starting at the zero displacement point, the particle travels to +A, back to 0, then to -A, then back to 0 again, for a total distance of 4A) The average *speed* of a particle is then = 4A/T = 4A*ν. In this case, we have: = 4*(2.6 cm)/(0.49 sec) = 21.2 cm/s. Note that the average *velocity* of a particle in the wave is zero.
How do i find the average speed of 384ft in4 mins 16 secs?
there's just a couple issues with your question: there isn't an average without a multitude of speeds to compare. The word must represent something other than "Mean" which is typically what "Average" means mathematically. you haven't given us a desired unit of measure. Currently you have given us a speed and asked for it's speed. Anyways, you would first take your smallest unit with the mixed set (in this case time is both minutes and seconds and we need a single unit to be able to get a rate that we can convert. So the smallest unit is seconds. We need to convert 4 minutes into seconds (there are 60 in each so multiply by 4) and add the other 16. Then we need to divide the distance traveled by the total time in seconds. This will give us feet per second. Treat it like an equation and if you change the value of one side then you must adjust the value of the other to maintain equality. For example, 12 inches per minute = 1 foot per minute. Minute stays the same because 12 inches = 1 foot. But 1 yard per 1 hour = 1 foot per 20 minutes. 1 foot = 1/3 of a Yard so 20 minutes = 1/3 of an hour. If you want miles per hour, there are 5280 feet in one mile. There are 3600 seconds in an hour. Hour will be the constant so multiply feet by 3600 then divide total feet per hour by 5280 to get miles per hour. If you wanted Hours per mile though, as crazy as that sounds, You would divide 5280 by your feet per second. This tells you how many seconds you need to go one mile. Convert seconds into hours by dividing by 3600. hope this helps.
How can I find average speed if a boy walks to his school at a distance of 6 km with a speed of 2.5 km/h and walks back with a constant speed 5km/hr?
This question is very simple.Average speed = Total Distance / Total Time TakenWe have given speeds S1 and S2S1 = 2.5 km/hrS2 = 5 km/hrAnd Distance D1 and D2D1 = 6 kmD2 = 6 kmTotal Distance = D1 + D2 = 6 + 6 = 12 kmNowT1 = D1/S1T1 = 6/2.5 = 2.4 hrT2 = D2/S2T2 = 6/5 = 1.2 hrTotal Time = T1 + T2 = 2.4 + 1.2 = 3.6 hrNowAverage Speed = Total Distance / Total Time = 12 / 3.6Average Speed = 3.33 km/hr
Physics Problem: Average speed?
Avg speed = distance traveled /time V = speed of slower car 3V = speed of faster car D = distance traveled by slower car d = distance traveled by faster car D + d = 142 Both cars travel for 1.7 h = time D = 1.7V d = 1.7(3V) = 5.1V 1.7V + 5.1V = 142 6.8V = 142 V = 142/6.8 = 20.9 mph ANS