An object is travelling with a constant acceleration of 10m/s[math]^2[/math]. How much distance will it travel during the 3rd second of its journey assuming it starts from rest?
Here a body is moving with constant accleration so initial velocity musy be taken zeroSo, by formulaS= u+a/2 (2t—1)=0+10/2(2×3—1)=5(5)=25m
If an athlete can run 100 meters in 10 seconds, why would it be mathematically wrong to say that he ran 10 meters in 1 second? That is impossible.
100 meters in 10 seconds is the overall distance and time.an average can be calculated - 10 meters in 1 secondbased on this average it is mathematically correct to say that the athlete ran 10 meters in 1 secondMissing pieces of information:initial accelerationfinal speedNow breaking a sprint down down — there is a period where the athlete:accelerates from [math]0[/math] to some [math]v[/math]maintains the [math]v[/math] till the finish linewe do not care about what happens after the finish linewe could do some of the Kinematic Equations and do some solving to figure it outAlso:Well, I mean running 10 meters in 1 second sounds like a superhero feat and hypothetical, but factually isn’t it correct?! What laws of physics can deny or prove it?Two words: Usain BoltA Kinematics Analysis Of Three Best 100 M Performances EverThis ability, combined with longer stride allows him [Usain Bolt] to create very high running speed - over 12 m/s (12.05 – 12.34 m/s) in some 10 m sections of his three 100 m performances.
The function gives the distances (in feet) traveled in time t (in seconds),Find the velocity and accerleration?
The function gives the distances (in feet) traveled in time t (in seconds) by a particle.Find the velocity and acceleration at the given time. s=1/t+4, t= 5 s=4t^3+7t^2+3t+9, t=3
A car travels from A to B at the rate of 40 miles per hour, and then returns from B to A at the rate of 60 miles per hour. Is the average rate for the round trip more or less than 50 miles per hour? Why?
it 'll be 48 mph.let, the distance of A to B be 1mile.so,first the time=1/40hr.on return,it'll be 1/60hrso, in all for 2 mile the time=1/40+1/60hr.so, avg=2/(1/40+1/60)=48.
An object is dropped from a height of 500 meters. When will the object reach the ground? With what speed will it hit the ground?
Use following equations to get the answerTo calculate the time for it to reach the ground is given by[math]t=\sqrt{\dfrac{2s}{a}}[/math]Where s is 500 meter and a = g = 10 [math]m/s^2[/math]To calculate velocity use equation [math]v^2=2as[/math] or [math]v=at[/math]
How is a firework projectile motion?
Strictly speaking a launched firework is not a projectile until it runs out of fuel. A projectile has two things (ignoring air resistance) affecting its path: momentum and gravity. After the firework explodes, instead of being a single projectile -- it is many projectiles. Most of the burning elements are projectiles which are affected by their momentum after the explosion and gravity. Some of the burning elements are not projectiles at all! Those that go straight down after the explosion are just free fall objects whose initial velocity was greater than zero. Just because something is a projectile, that does not mean that its path will be a full parabola. Think of throwing a rock horizontally off of the edge of a cliff -- its initial vertical velocity is zero. For real life applications, I would stick with: arrows, stones shot from a sling shot or bullets/artillery shells.
In a 500 m race, the ratio of the speeds of A & B is 3:4. A has a head start of 140 m. Then, A wins by what distance?
20 mLet speed of A be 3x and B be 4x.A must travel 360m only.So time taken for A to finish the race is 360/3x=120/x.So in that time distance travelled by B is 120/x *4x=480mSo A wins by 20m.
Homework Question: Joe walked 4 miles north, 9 miles east, 8 miles north, and then 7 miles east. If Joe now decides to walk straight back to where he started, how far must he walk?
The answer provided by User-9597828242429937573 is great, but there are couple of omissions that make its precision unacceptable for practical purposes:1. Our planet is not spherical: its height is less than width due to its rotation. We should take it into account;2. Joe is not a point, but rather a material object. We have to make calculations probably for his geometrical center or, maybe, his center of mass. It should be discussed and decided. If agreed upon geometrical center, 1/2 of Joe's height should be added to the radius;3. Since the journey is long, the result depends on the time he starts and his speed - because of thermal expansion of the Earth's surface heated by the Sun. If Joe is walking while the surface is expanding, his trip back may be longer if the temperature is still high;4. Of course, we should consider the Earth deformation due to the Moon's gravity;5. The answer has to be expressed in closest integer number of Plank lengths. Otherwise, it would be absolutely unrealistic.Other than that, it is pretty accurate and will probably satisfy Joe. :)