How do you find the volume of an irregular object?
Well, there are 2 basic methods.Using the physical measurements of a regular object (like a box) we multiply the width by the depth and then multiply that by the height. WxDxHIf it is irregular (weird shaped or inconvenient to measure) you can use displacement. To do that you submerge the object in a known quantity of liquid and then note the measurement of the liquid while the object is completely submerged. The volume of the object is the measurement of the liquid with the object submerged minus the initial measurement of the liquid. For example if you start with 77 ml of water and when the object is submerged you have 97 ml of water then you can calculate the volume of the object by taking 97–77 which equals 20 ml.
Explain how can you find the volume of an irregularly shaped object?
Displacement using water. Catch the water displaced, and weigh it. For all intents and purposes, water weighs 1 g cm^3
How to find the volume of a submerged object?
The water level in a rectangular prism tank 40 centimeters by 20 centimeters is 12 centimeters high. A rock submerged in the tank raises the water level 0.4 centimeters. What is the volume of the rock? im not saying tell me the answer im just asking how to solve it
How can you find the volume of an irregular shaped object?
Good lord, there is no such thing as "apparent mass," not in classical physics. What you would really be looking for is apparent weight, w = B - W; where B is buoyancy and W = mg is weight of the actual mass m (not apparent). One more time, because this is something you need to understand, m, mass, of the object is the same in the water as it is in the air. There is no apparent mass. I strongly urge you to reread your assignment and this time pay attention to the difference between mass and weight. To find the volume of an irregular shape, immerse it into a gradated beaker of water and note how high the water rises when the object is placed into it. The difference between before and after immersion is the volume of the irregular shaped object. If you are supposed to calculate the volume V from the apparent weight, w, then buoyancy B = W - w = Rho g V when the object is fully immersed. So V = (W - w)/(Rho g); where W = mg is the weight of the object, w is the apparent weight, Rho = 1000 kg/m^3 is the density of water, and g is g. I'm guessing you weighed the object in air to find W and then in the water to find w. So you have everything to find V. But, pay attention, there is no such thing as apparent mass...it's apparent weight. They are not the same. And that's the physics you should be learning at this point.
What method is used to determine the volume of irregular-shaped solid?..?
Put the irregular body (if small) in a calberated glass having water in it up to a certail level. The change in water give you the volume of the body.
How will you determine the volume of an irregular-shaped object like a rock?
Assuming it has no interior voids (or that interior voids count as part of the volume of the rock), I would use the fluid displacement method. Submerge the rock in a sufficiently large, calibrated container completely full of water and then measure how much water was left after removing the rock. The volume of water that was pushed out of the container would be equal to the volume of the rock.As a variation, put the rock in an empty, calibrated container, fill the container with water until the rock is covered, and measure the volume of the rock and water together. Remove the rock and measure the volume of the water alone. The difference is the volume of the rock.You can thank Archimedes (and King Hiero and his crown) for that one.
How can you measure the volume of an irregularly shaped thing (e.g. humans), aside from putting it in a tub of water and measuring the displaced water?
There are many forms of fluid displacement you could use, but I assume that if you want to proscribe water displacement, you actually mean all fluids.You could do this by using the ideal gas law to get the volume by measuring the pressure and temperature accurately. There are a variety of mechanical changes you can make to a system that includes your irregular object that can reveal the volume it occupies. They are all significantly more complicated than displacing fluid to get a volume, which is why we just use this system instead.And of course there is just direct measurement. If you know the density and the weight, you can get the volume. But presumably you can't do this because you don't know the density (of humans, for instance). This would be problematic for any object with non-uniform density.
Explain how the volume of a heavy irregularly shaped object may be determined experimentally.?
A eureka can may be used.You should fill the can to the marked level with water then add the object.The volume of water displaced by the object is equal to the volume of the object
How can I find the volume of an object using water displacement?
You need a graduated cylinder of some kind, that will be used to measure the volume of your object. You also need a jug of water that will be able to hold your object. Now pour water into the jug, until it is really full. Imerse your object into the jug, and collect the excess water into the graduated cylinder.Ideally, you want to make sure that the graduated cylinder is right next to the water jug, so that all the excess water, pours into it. You will then know the volume, by looking at how much water in ml or litres have collected in the graduated cylinder. That's the volume.If you measured the volume in litres, you can easily convert that into cubic centimeters.Edit: in Physics, the principal used here, is called Archimedes Principal.
What is the best way to measure the volume of an object?
This is a very interesting question. The short answer is that I don't know the most modern way of measuring a volume. I'll ask some of my experimental colleagues for ideas.Both Anon User's answerAchilleas Vortselas's answerwork, but we certainly must have advanced in our techniques in the past 2500 years.There are some real reasons why you wouldn't want to immerse something in a liquid. For instance, water is very reactive and if you want to know the volume of say a computer chip, submersing it in water may not be ideal.Next, the density of water changes a lot! 4% in a few degrees. There are lots of applications where 4% isn't good enough. Now you're having to measure temperatures incredibly precisely. You can measure temperature differences down to an accuracy of 0.01C pretty easily this will only get a 10^-4 accuracy and then you have to start really measuring temperatures and precisely.Measuring the volume of water isn't totally trivial either since drops of water can stick to the surface and now you're talking about changing the volume by 50 μL. That might not be good enough for your specific application. Finally, measuring the volume of water isn't easy. How accurate can you measure the rise and fall of a volume of water? I did this in chemistry, and you have that stupid meniscus. I'd guess 0.1% accuracy is what you'd be aiming at. Again, this may not be good enough. I suspect that there isn't a universal answer and it really depends on what you know about the system. For instance here 3 different methodsIf you have access to the geometry, but not the composition isn't particularly well known. Then you can survey the object and compute the volume the old fashioned way.Modern silicon has densities that are known to an accuracy of 1:10^8. That means that if you're measuring the volume of a solid piece of silicon from from a lab, you can simply weigh the object and then divide by the density.If you can submerse the material, you can probably use the Archimedian method. You probably wouldn't want to use water, but some other liquid with better expansion properties. But may be you could use that.My guess is that method 1 is the best in most circumstances with modern laser-ranging techniques and computer aided modeling.