How do I lose thigh fat fast?
You can’t lose thigh fat quickly.It’s a process.I will give you effective tips which can help you.First, you should eliminate the causes of those extra pounds:Stop drinking sodasStop drinking alcohol (especially beer)Stop eating junk foodGo to bed earlierDon’t sit all dayStop eating at nightChange your dietNow, do everything opposite:Drink water (at least 8 glasses per day)Don’t skip meals - breakfast especially, eat an apple for a dinnerSleep enough (at least 7 hours)Don’t eat after 7 p.m.Eat high-fiber foods and high - protein foodsExercise and increase physical activitiesExercisesExercising is one of the most effective ways when it comes to losing weight.Plank is very effective when it comes to fat burning, especially belly fat.The plank can help you get rid of fat layers around the belly, waist, shape your buttocks, relieve the pain in your back, and speed up your metabolism.GRIT cardio is a 30-minute high-intensity interval training (HIIT) which improves your cardiovascular endurance, accelerates your movements and makes your body burn calories long after your training.Counting caloriesDon’t forget to create a calorie deficit in order to lose weight efficiently.SupplementsIn order to increase fat burning, you can think about some supplement. But just to be clear - there is no magic pill which will help you lose weight instantly.Supplements can be used just as an addition to balanced diet.Reference:Best Fat Burners That WorkDon’t forget - you didn’t gain weight over the night so you can’t lose it over the night.
Frog jumping 3 feet up 2 feet down per hour. How long to reach 30 feet high?
We can deduce that after an hour, the frog will jump eventually 1 feet up*.After 27 hours/jumps the frof is 27 feet high.Now, a well known mistake is to keep counting till 30. But wasn't the question.The question was about the moment in which the frog will reach 30 feet high.Let us resume to our case:The frog is 27 feets high and now it jumps - so by the question details it first jump 3 feets up.Which means, in that excat moment, the frog has reached 30 feets high.So the answer is between 27 and 28 hours, and if we want to make sure, we will take the maximum: 28 hours.
A monkey started climbing 20 ft tree each hour she climb 3 ft and slipes back by 2 ft so how much time she takes to reach the top?
As in an hour the monkey climbs 3ft and slips 2ft, distance the monkey climbs in an hour will be = 3ft-2ft = 1ft.So the time it takes to climb the first 17 feet will be = 17 hrsAfter climbing 17 ft, in the last 3ft the monkey climbs, it reaches the top and doesn’t slip back. So, it takes an hour to climb these last 3 feet.Hence, the total time it takes to cimb will be = 17hrs+1hr = 18hrs.
In climbing a round pole of 80 metres height, a monkey climbs 5 metres in a minute and slips 2 metres in the alternate minute. How much time would the monkey take to get to the top of the pole?
51 min!I hope this helps!![ (total height-climb height)/(climb height-slip height) ]*(time to climb and slip minutes)+1{Formula works for all similar questions}heretotal height=801 climb height=51 slip height=2time to climb and slip minutes=time taken for 1 consecutive climb and slip=2 mini.e; 1 minute to climb and another 1 minute to slip=2minNote1:If slip is also in same minute then=1 min“+1″ as last step.So,[(80–5)/(5–2)]*2+1[75/3]*2+1[25]*2+150+151 min.Note2:If u get in decimal value in brackets i.e; [(total height-climb height)/(climb height-slips height) ] then take next number into consideration!!
A stone is dropped from the top of a tower.If it hits the ground after 10 seconds, what is the height of the tower?
We can use the formula S=ut+([math]1/2)[/math]a[math]t^2[/math]Where u is initial velocity, ‘s’ is distance travelled (Height of the tower in this case), ‘t’ is time travelled and ‘a’ is the constant acceleration.So , here as the object is dropped , the initial velocity ,u is 0Acceleration is the acceleration due to gravity ‘g’ which is constant and has value of 9.8m/[math]s^2[/math]Time travelled is given as t=10 secondsSubstituting the values in the equation s=ut+([math]1/2)[/math]a[math]t^2 [/math]we gets=0 * 10 + ([math]1/2)[/math]* 9.8 * 10 *10s=490 metersSo, the height of the tower is 490 meters