How to find a right triangle!!!????? PLEASE HELP!!?
These three numbers do not make a right triangle. as mentioned in another answer, the Pythagorean theorem says "a" squared + "b" squared = "c" squared where c = the largest of the three numbers, and a and b equal the other two numbers. In your case, 55 squared + 44 squared = 70 squared or 3025 + 1936 = 4900 but that is not the case. 3025 + 1936 = 4961 and the squre root of 4961 = about 70.43. Most right triangles do not have whole numbers, but some do . . . like 3 by 4 by 5 3 squared + 4 squared = 5 squared or 9 + 16 = 25 which it does. this works with any multiple of 3, 4, and 5 like 21, 28,and 35, or 33 and 44 and 55, but not 44 nand 55 and 70. another right traingle with whole numbers is 5, 12, and 13 5 squared + 12 squared = 13 squared that is 25 + 144 = 169 which it does. Once again, any multiple of this will also work, such as 25, 60, and 65, but not 44, 55, and 70 YOu can make a right traingle with 2 of your numbers, such as 33 and 44 and 55 (the 3, 4, 5 right traingle multiplied by 11) but that does not use the 3 numbers you gave. Sorry I can't help more
Need help with finding the leg and hypotenuse of a right triangle.?
the hypotenuse of a right triangle is three times the length of one of the legs. the length of the other led is √ 128 feet. find the lengths of the leg and hypotenuse
URGENT HELP!! θ is an acute angle in a right triangle. Find the values of the six trigonometric functions given the following:?
(1 pt) Assume that θ is an acute angle in a right triangle. Find the values of the six triginometric functions given the following: cos(θ)=25/28. See attached photo please show the work and how its done please thanks soo much!!!!!
Is there a way to find the other two sides of a right triangle with the hypotenuse?
You can use these trigonometric formulas according to picture, if you know angles, to find out sides:-Then you can apply Pythagoras theorem also.Hypo^2= base^2 + side^2.Hope it helps !!
Find the missing side of the right triangle with legs: a = 12, b = 9 IS TH ANSWER 0.3 OR 15 OR 12 OR 1? HELP!
Standard Pythagorean theorem application problem a^2 + b^ 2 = c^2 a = 12, b = 9 12^2 = 144 9^2 = 81 144 + 81 = 225 root 225 = 15 or side c -- your second answer choice
Geometry Help! A right triangle has legs of 6 and 8. Find the lengths of...?
a) median to the hypotenuse. b) altitude to the hypotenuse. I'm not sure how you solve it! I know that a hypotenuse is square root of 2 times the leg, though....where do i go from here?
How do I find the type of triangle with the help of 3 coordinates?
If the coordinates of a triangle are given, we can find the type of triangle by measuring the distance between the points..For eg,Let A(x1,y1) , B(x2,y2) , and C(x3,y3) be the 3 coordinates of a triangle…Now, To find the type of triangle we now find the distance between the points as follows…Distance between the points AB,Distance between the points AC,And, distance between the points BC…Now, ifAB=AC=BC , then the triangle is an equilateral triangle..AB=AC≠BC / AB=BC≠AC / AC=BC≠AB , then the triangle is an isosceles triangle..AB≠AC≠BC, then the triangle is a scalene triangle…This is how we find the type of triangle using the 3 given coordinates…P.S.- The formula for finding the distance between 2 points is as follows..Let us consider 2 points, A(x1,y1) and B(x2,y2)..Thus, the distance between AB is given by the formulaAB=√{(x1-x2)²+(y1-y2)²}
How can we find the two sides of a right angled triangle if only one side is provided and no angle is given?
You can’t.Given that the triangle is a right triangle, we only know for sure two thingsThe length of one sideThat [math]a^2+b^2=c^2[/math]Knowing trig functions won’t help too much because you aren’t given an angle (that makes sin hard)Here’s the proof on why you can’t:Case 1. You know a (or b)Given side a, you do not know b or c, solving for a,[math]a=\sqrt{c^2-b^2}[/math]which allows c and b to be many possible things, for example, if a = 3,[math]3=\sqrt{c^2-b^2}[/math]c and b can be 4 and 5 respectively, [math]\sqrt{10}[/math] and [math]1[/math] respectively, \[math]sqrt{11}[/math] and [math]\sqrt{2}[/math] respectively, or anything else as long as [math]c^2-b^2[/math] is equal to 9.Case 2. You know c[math]c=\sqrt{a^2+b^2}[/math]this also allows for a lot of flexibility, for example, is c = 5a and b can be 3 and 4 respectively, [math]\sqrt{20}[/math] and [math]\sqrt{5}[/math] respectively, [math]\sqrt{21}[/math] and [math]\sqrt{4}[/math] respectively, or anything as long as [math]a^2+b^2[/math] is equal to 25.To those who think that in certain cases you can figure it out by special triangles, that is assuming that all three sides are integers. For example, in a triangle with a hypotenuse of 13, the legs CAN be 5 and 12, but they don’t HAVE to be. They can also be [math]\sqrt{168}[/math] and [math]1[/math], or anything as long as the legs satisfy:[math]c=\sqrt{a^2+b^2}[/math].Hope this helps! :D