# Help Help Help The Formula Is F=kq^2/r^2 Re-arrange Into The Form Y=mx C

Slope, y-intercept, equation, standard form??? HELP?? =( I seriously don't understand!!!??

The point slope form is:
y – y1 = m(x – x1)
This follows directly from the defintion of slope which is just (y - y1)/(x - x1)

The standard form is:
Ax + By = C

The slope-intercept form is:
y = mx + b

1. (6,2, m=1/2) (6,2) is a point on the line and m is the slope. All you do is substitute these values into the standard form:

y - 2 =(1/2)x - 6
y - 2 = (1/2)(x - 12)

2. (4,1), (-3,6) In this case you have two points and do not know the slope.
Find the slope:
y - y1 = m(x - x1)
m = (y - y1)/(x - x1) = (6 - 1)/(-3 - 4) = -5/7

Put this value of m back into the standard equation along with either of the points. Using the first point:
y - 1 = (-5/7)(x - 4)

You can check by putting in the second point.
6 - 1= (-5/7)(-3 -4) = 5 which is right

3. (1,5), m=0 This is a special case since the slope is 0. This is just a line parallel to the x-axis. You end up with y - y1 = 0 so:
y = 5

4.(-2,5), (9,5) Again this is two points. Follow the same procedure that was used for 2.

Find the slope:
m = (5 - 5)/(9 - (-2)) = 0/11 = 0

This is another line parallel to the x-axis so:
y = 5

You can also tell by inspection since the y value is the same for both points.

5. (-5,7), (0, 1/2)
First find the slope:
m = (1/2 - 7)/(0 - (-5)) = (-13/2)/5 = -13/10

Using this and the first point in the point-slope form:
y - 7 = (-13/10)(x - (-5)) = (-13/10)(x + 5)
y - 7 = (-13/10)x - 13/2
y + (13/10)x = 1/2

Check by putting in the second point:
1/2 + (13/10)(0) = 1/2 which is right

6. m=-3, b=0
Slope intercept form is: y = -3x + 0
so: y = -3x

7. x=2y -7
The slope and y intercept can be found by changing the form of the equation to slope-intercelt (y = mx + b)

2y = x + 7
y = (1/2)x + 7/2
So slope = 1/2 and y intercept is 7/2

8. 1/2x+1/4y=3
Do as in 7.
(1/4)y = (-1/2)x + 3
y = -2x + 12

So slope is -2 and y intercept is 12

9. 5x1/2y=2
do you mean (5x)[(1/2)y] = 2 ????
or 5x[1/(2y)] = 2 ?????
I'm sorry I don't know what you mean here

How to rearange F=ma to A=?

heres an idea which always helps me rearrange equations.
a formula triangle.
draw out a triangle and then create three boxes inside by drawing a T. In each of the boxes you've created you need to put one of the letters from the equation. The equation you currently have is F= m*a. To rearrange this equation put the m and the a into the bottom boxes and the F above. Because there is a vertical line between the m and the a, this means you times them. If there is a horizonal line between two letters you divide them. So to find a, you must divide F by m.

this works for almost any three part equation.

Y = mx + c ..... quick help?

What you would do is substitute the co-ordinates (17.5, 3.17) into the equation y = mx +c.

You get: 3.17 = 0.08* 17.5 +c
Then you rearrange the equation so that c is isolated.
3.17-1.4 =c
c= 1.77
Then simply put c = 1.77 into you equation.

So..... y = 0.08x + 1.77

Hope this helps!

Intro Calculus (grade/year 11) question. Equations in form: y=mx+c...?

are you trying to get strangers to do your homework?

the first questions are all just a matter of basic algebra.
1a) 3x-2y=12
subtract 3x from both sides:
-2y=12-3x
divide by -2
y=-6+(3/2)x
re-arrange
y=(3/2)x-6
voila! m=(3/2) b=6

you can do parts b,c,d on your own unless someone else answers them for you.

Question 2:
the y intercept is where x=0
0/a+y/b=1
y/b=1
multiply by b
y=b

the x intercept is where y=0
same thing:
x/a+0/b=1
x/a=1
multiply by a
x=a

for the gradient (slope) we need to get into y=mx+b form
again just algebra
x/a+y/b=1
subtract x/a
y/b=1-x/a
multiply by b
y=b-(b/a)x

Question 3:
solve algebraically,
3x-2y=12
2x-5y=19
there's a number of ways to do this, I'm not sure which you are familiar with. My personal favorite is cancellation

multiply the first equation by 2 and the second by three to get
6x-4y=24
6x-15y=57
now subtract the two equations:
0x+11y=-33
divide by 11
y=-3
now substitute y=-3 back into one of the equations
3x-2(-3)=12
3x+6=12
subtract 6
3x=6
divide 3
x=2
the solution is x=2, y=-3

Question 4
I'm going to be naughty and not explain myself on these it's late and I'm tired
a)(x+5)(x-2)
b)(2x-1)(x-3)
c)(3x+2)(x-3)

ta daa!

PLEEAASSEEE!!! : re-arranging equations to y=mx+c?

x + y = 2*y + 4

Step 1) move all the terms containing a 'y' to the left side. And, move everything else to the other side.

y - 2*y = -x + 4

Step 2) Simplify if you can

-y = - x + 4

Step 3) Divide everything by whatever is in front of 'y'. In this case, it is a -1

y = x - 4

It is a systematic and mechanical process. You move all the terms containing 'y' to one side and everything else to the other side. What follows should be natural.

There are two things here that you need to figure out. You have the equation y = mx + b, and you need to figure out the slope (m) and the y-intercept (b) of your perpendicular line.

First things first, put the equation of your original line into y = mx + b form. You will get y = 6/7 x + 2/7. You now know the slope of your original line, which is 6/7.

Well, you know that the perpendicular line's slope will be the reciprocal of the original line's slope. Therefore, the slope of its perpendicular line is -7/6.

Now, you need to figure out the y-intercept of the perpendicular line (b). You already know that the line goes through the points (4, 0). And you know the slope. You can use your y = mx + b equation to figure this out. Input your slope in place of m and the points (4, 0) in place of the y and x in this equation to get 0 = -7/6 * 4 + b. Solve this equation to find that your b is 4.667. Now you have figured out that the y-intercept of your perpendicular line is at (0, 4.667)

You have figured out all the variables that you need. Now plug them into your y = mx + b equation, and you will find that the equation to your perpendicular line is:

y = -7/6 x + 4.667

In decimal form, it would be y = -1.167x + 4.667.
In fraction form, it would be y = -7/6 x + 14/3

I am having a problem with this algebra problem?

Find the x and y intercepts individually.

Firstly, the x intercept is where y = 0

so, 2x + 5 = 0 => x = -5/2.....intercept (-5/2, 0)

The y intercept is where x = 0

so, -2y + 5 = 0 => y = 5/2......intercept (0, 5/2)

You could re-arrange the original equation to get:

2y = 2x + 5

so, y = x + 5/2......in the form y = mx + c, where m is the intercept and c the y intercept.

From this we see that the slope or gradient is 1 and the intercepts are as before.

:)>

Perpendiclular Lines?

first re arrange the formula.. in the form y = mx + c

4x + 3y = -6
4x + 6 = -3y
-3y = 4x + 6
y = -4/3*x - 2

m is the gradient of the line which is -4/3

the gradient of the perpendicular line multiplied by the gradient of the actual line will give and answer of -1.

Therefore let a = the gradient of new line..

-4/3 * a = -1
a = -1 * -3/4
a = 3/4

therefore the gradient of the perpendicular line is 3/4

now put it into the equation y = mx + c

.. y = (3/4)*x + c

we don't know "c" but we know the values of "x" and "y".. so put it into the above equation

1 = (3/4)*2 + c
1 = 6/4 + c
1 = 1.5 + c
1 - 1.5 = c
-0.5 = c
c = -0.5

therefore the equation of the perpendicular line is:

y = (3/4)*x - 0.5