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Help Help Help The Formula Is F=kq^2/r^2 Re-arrange Into The Form Y=mx C

Slope, y-intercept, equation, standard form??? HELP?? =( I seriously don't understand!!!??

The point slope form is:
y – y1 = m(x – x1)
This follows directly from the defintion of slope which is just (y - y1)/(x - x1)

The standard form is:
Ax + By = C

The slope-intercept form is:
y = mx + b

1. (6,2, m=1/2) (6,2) is a point on the line and m is the slope. All you do is substitute these values into the standard form:

y - 2 =(1/2)x - 6
y - 2 = (1/2)(x - 12)

2. (4,1), (-3,6) In this case you have two points and do not know the slope.
Find the slope:
y - y1 = m(x - x1)
m = (y - y1)/(x - x1) = (6 - 1)/(-3 - 4) = -5/7

Put this value of m back into the standard equation along with either of the points. Using the first point:
y - 1 = (-5/7)(x - 4)

You can check by putting in the second point.
6 - 1= (-5/7)(-3 -4) = 5 which is right

3. (1,5), m=0 This is a special case since the slope is 0. This is just a line parallel to the x-axis. You end up with y - y1 = 0 so:
y = 5

4.(-2,5), (9,5) Again this is two points. Follow the same procedure that was used for 2.

Find the slope:
m = (5 - 5)/(9 - (-2)) = 0/11 = 0

This is another line parallel to the x-axis so:
y = 5

You can also tell by inspection since the y value is the same for both points.

5. (-5,7), (0, 1/2)
First find the slope:
m = (1/2 - 7)/(0 - (-5)) = (-13/2)/5 = -13/10

Using this and the first point in the point-slope form:
y - 7 = (-13/10)(x - (-5)) = (-13/10)(x + 5)
y - 7 = (-13/10)x - 13/2
y + (13/10)x = 1/2

Check by putting in the second point:
1/2 + (13/10)(0) = 1/2 which is right

6. m=-3, b=0
Slope intercept form is: y = -3x + 0
so: y = -3x

7. x=2y -7
The slope and y intercept can be found by changing the form of the equation to slope-intercelt (y = mx + b)

2y = x + 7
y = (1/2)x + 7/2
So slope = 1/2 and y intercept is 7/2

8. 1/2x+1/4y=3
Do as in 7.
(1/4)y = (-1/2)x + 3
y = -2x + 12

So slope is -2 and y intercept is 12

9. 5x1/2y=2
do you mean (5x)[(1/2)y] = 2 ????
or 5x[1/(2y)] = 2 ?????
I'm sorry I don't know what you mean here

How to rearange F=ma to A=?

heres an idea which always helps me rearrange equations.
a formula triangle.
draw out a triangle and then create three boxes inside by drawing a T. In each of the boxes you've created you need to put one of the letters from the equation. The equation you currently have is F= m*a. To rearrange this equation put the m and the a into the bottom boxes and the F above. Because there is a vertical line between the m and the a, this means you times them. If there is a horizonal line between two letters you divide them. So to find a, you must divide F by m.

this works for almost any three part equation.
more help? just ask =]

Y = mx + c ..... quick help?

What you would do is substitute the co-ordinates (17.5, 3.17) into the equation y = mx +c.

You get: 3.17 = 0.08* 17.5 +c
Then you rearrange the equation so that c is isolated.
3.17-1.4 =c
c= 1.77
Then simply put c = 1.77 into you equation.

So..... y = 0.08x + 1.77

Hope this helps!

Intro Calculus (grade/year 11) question. Equations in form: y=mx+c...?

are you trying to get strangers to do your homework?

the first questions are all just a matter of basic algebra.
1a) 3x-2y=12
subtract 3x from both sides:
-2y=12-3x
divide by -2
y=-6+(3/2)x
re-arrange
y=(3/2)x-6
voila! m=(3/2) b=6

you can do parts b,c,d on your own unless someone else answers them for you.

Question 2:
the y intercept is where x=0
0/a+y/b=1
y/b=1
multiply by b
y=b

the x intercept is where y=0
same thing:
x/a+0/b=1
x/a=1
multiply by a
x=a

for the gradient (slope) we need to get into y=mx+b form
again just algebra
x/a+y/b=1
subtract x/a
y/b=1-x/a
multiply by b
y=b-(b/a)x
gradient=b/a

Question 3:
solve algebraically,
3x-2y=12
2x-5y=19
there's a number of ways to do this, I'm not sure which you are familiar with. My personal favorite is cancellation

multiply the first equation by 2 and the second by three to get
6x-4y=24
6x-15y=57
now subtract the two equations:
0x+11y=-33
divide by 11
y=-3
now substitute y=-3 back into one of the equations
3x-2(-3)=12
3x+6=12
subtract 6
3x=6
divide 3
x=2
the solution is x=2, y=-3

Question 4
I'm going to be naughty and not explain myself on these it's late and I'm tired
a)(x+5)(x-2)
b)(2x-1)(x-3)
c)(3x+2)(x-3)

ta daa!

PLEEAASSEEE!!! : re-arranging equations to y=mx+c?

x + y = 2*y + 4

Step 1) move all the terms containing a 'y' to the left side. And, move everything else to the other side.

y - 2*y = -x + 4

Step 2) Simplify if you can

-y = - x + 4

Step 3) Divide everything by whatever is in front of 'y'. In this case, it is a -1

y = x - 4


It is a systematic and mechanical process. You move all the terms containing 'y' to one side and everything else to the other side. What follows should be natural.

Finding the equation of a straight line? Please help :)?

There are two things here that you need to figure out. You have the equation y = mx + b, and you need to figure out the slope (m) and the y-intercept (b) of your perpendicular line.

First things first, put the equation of your original line into y = mx + b form. You will get y = 6/7 x + 2/7. You now know the slope of your original line, which is 6/7.

Well, you know that the perpendicular line's slope will be the reciprocal of the original line's slope. Therefore, the slope of its perpendicular line is -7/6.

Now, you need to figure out the y-intercept of the perpendicular line (b). You already know that the line goes through the points (4, 0). And you know the slope. You can use your y = mx + b equation to figure this out. Input your slope in place of m and the points (4, 0) in place of the y and x in this equation to get 0 = -7/6 * 4 + b. Solve this equation to find that your b is 4.667. Now you have figured out that the y-intercept of your perpendicular line is at (0, 4.667)

You have figured out all the variables that you need. Now plug them into your y = mx + b equation, and you will find that the equation to your perpendicular line is:

y = -7/6 x + 4.667

In decimal form, it would be y = -1.167x + 4.667.
In fraction form, it would be y = -7/6 x + 14/3

I am having a problem with this algebra problem?

Find the x and y intercepts individually.

Firstly, the x intercept is where y = 0

so, 2x + 5 = 0 => x = -5/2.....intercept (-5/2, 0)

The y intercept is where x = 0

so, -2y + 5 = 0 => y = 5/2......intercept (0, 5/2)

You could re-arrange the original equation to get:

2y = 2x + 5

so, y = x + 5/2......in the form y = mx + c, where m is the intercept and c the y intercept.

From this we see that the slope or gradient is 1 and the intercepts are as before.

:)>

Perpendiclular Lines?

first re arrange the formula.. in the form y = mx + c

4x + 3y = -6
4x + 6 = -3y
-3y = 4x + 6
y = -4/3*x - 2

m is the gradient of the line which is -4/3

the gradient of the perpendicular line multiplied by the gradient of the actual line will give and answer of -1.

Therefore let a = the gradient of new line..

-4/3 * a = -1
a = -1 * -3/4
a = 3/4

therefore the gradient of the perpendicular line is 3/4

now put it into the equation y = mx + c

.. y = (3/4)*x + c

we don't know "c" but we know the values of "x" and "y".. so put it into the above equation

1 = (3/4)*2 + c
1 = 6/4 + c
1 = 1.5 + c
1 - 1.5 = c
-0.5 = c
c = -0.5

therefore the equation of the perpendicular line is:

y = (3/4)*x - 0.5