Help help! who can solve this! its a challenge!?
Elaine wants to deposit her summer earnings of $13,000 in a savings account to save for retirement. The bank pays 7% interest per year compounded semiannually (every months). How much will her tax-deferred account be worth at the end of 3 years?
Solve this question its a challenge for you guys!!?
Chathuringmes
Help.......It's a challenge............Plzzzzz?
i dont think this is possible
Its a challenge. a math challenge. anyone think they can solve it.......?
If the base (b) of a triangle is increasing at a rate of 3 inches per minute while its height (h) is decreasing at a rate of 3 inches per minute, which of the following must be true about the area (A) of the triangle? (a) A is always increasing (b) A is always decreasing (c) A is decreasing only when b < h (d) A is decreasing only when b > h (e) A remains constant
Math challenge on checkers?
Okay first off, i'm not trying to use yahoo answers as a homework help this is just a little challenge that my math teacher gave us to see if we can solve it. It is NOT graded. This is the problem: One checker has already been placed on this piece of a checkerboard. Place 9 more checkers, each on a different square, so that there are 4 checkers on each of 5 different lines. draw lines as proof. Here's how it looks... the red dot is the checker http://s1015.photobucket.com/albums/af276/1234acdc/?action=tageditmany http://www.flickr.com/photos/44468812@N05/?saved=1
Please Solve my question . Its a challenge for mathametics teacher?
thats easy. you do 1+2+3+4+5+6+7+(8*9) BUT if you want them to stay in the same order then: (1+2+3+4+5) x 6 = 90 then 90-7 = 83. then 83 + 8 + 9 = 100. And the second way kept em in order. not that hard..
Need help with chemistry: its a challenge!!?
Work out the initial moles of HBr in the solution Molarity = moles / litres therefore moles = Molarity x litres moles HBr = 0.550 M x 0.400 L = 0.220 moles of HBr are in 0.400 L of 0.550 M HBr Now, treat in two parts First work out the number of moles of HBr that were neutalised by the titration with NaOH NaOH + HBr -----> NaBr + H2O 1 mole HBr requires 1 mole NaOH to be neutralised moles of NaOH used::::: Molarity = moles / Litres therefore moles = Molarity x L moles NaOH = 0.500 M x 0.165 L = 0.0825 moles So 0.0825 moles of NaOH was required to neutralise the HBr left in the solution after the Zn(OH)2 was added. From the equation above you can see that 1 mole NaOH is required to neutralize 1 mole HBr. Therefore the 0.0825 moles of NaOH reacted with 0.0825 moles of HBr This means that there must have been 0.0825 moles of HBr left in the solution after the addition of Zn(OH)2. Now you can work out moles of HBr that must have reacted with the Zn(OH)2 The moles of HBr that the Zn(OH)2 reacted with must have been = (initial moles HBr) - (moles HBr remaining after Zn(OH)2) = 0.220 mol - 0.0825 mol = 0.1375 mole HBr The Zn(OH)2 reacted with 0.1375 mole HBr 2HBr + Zn(OH)2 ------------> ZnBr2 + 2H2O You can see from the balanced equation that 2 moles of HBr only requires 1 mole of Zn(OH)2 for neutralisation Therefore moles of Zn(OH)2 added = 1/2 x 0.1375 mol = 0.0688 moles Zn(OH)2 was added to the HBr now moles = mass / molar mass therefore mass = molar mass x moles molar mass Zn(OH)2 = 65.39 + (2 x 16.00) + (2 x 1.008) = 99.41 g/mol mass Zn(OH)2 = 0.0688 mol x 99.41 g/mol = 6.84 g Zn(OH)2
Can someone help me solve this riddle?
3 ² = 4 + 5 ░░░░░░░░░