Can any one help me with my algebra homework?
let p = pens and n = notebooks 3p + 2n = 8.25 2p + 3n = 8.00 add these two equations together 5p + 5n = 16.25 p + n = 3.25 hope this is what you were looking for :-)
I need help on my algebra homework?
Find two polynomials with a sum and product that have the following degrees. if you cannot find the polynomials, explain why? A) the sum has degree of 3 and the product has degree 6.
Can u please help me with my algebra homework.?
Show work? 29. The Roll'n'Rocks group gives 3 performances at Municipal Stadium. They are paid $15 for each ticket sold plus a flat fee of $100,000 for each performances. If the stadium seats up to 65,000 people per performance, then what is the range of money they can earn for the 3 performances?
Can anyone help me with my Algebra homework?
Here's the question. I'm on section 5-5 #32 for a, b, and c. HOCKEY A hockey puck leaves the blade of a hockey stick, bouces off a wall, and travels in a new direction, as shown. a. Write an equation that models the path of the puck from the blade of the hockey stick to the wall. (the points for the hockey stick are (-4, 0), and the points for where the puck bounced off the wall is (0, 8). b. Write an equation that models the path of the puck after it bounces off the wall. (The points for where it bounced off the wall is (0, 8) and the points for the path after it bounces off the wall is (-4, 16). c. Does the path of the puck form a right angle? Justify your answer. (PLEASE HELP ME W/ THIS! COMMENT A.S.A.P.! WRITE TO ME THE STEPS AND HOW U GOT UR ANSWER, THANK YOU. BYE!) Oh, and can u make the answers at a more 8th grade/freshman Algebra formulas and equations.
Can someone help me with my algebra homework?
slow train takes 3:45=225 min moving at 1/225 min ^-1 fast train takes 1:50=110 min moving at 1/110 min^-1 slow train has gone 39/225 of the distance when the fast train starts. they cover 1-39/225=75/75-13/75=62/75 of the trip to meet. they are approaching at 1/110+1/225=45/4950+22/4950=67/4950 min ^-1 62/75/(23/4950)=(62/75)(4950/67)=61.07 min or i hr 1 min 4 sec
Can you help me with my algebra homework please?!?
well let x= the number of dimes Mia has. Since she has twice as many quarters, she has 2x quarters. One dime = 10 cents, so x dimes is 10x cents. One quarter = 25 cents so 2x quarters is 50x cents. Therefore, 10x+50x=360 60x=360 x=6 So she has 6 dimes and 12 quarters.
Can you please help me with my Algebra homework?
A juggler tosses a ring into the air. The height of the ring in feet above the juggler's hands can be modeled by the function f(x)=-16x^2+96x, where x is the time in seconds after the ball is hit. Find the ball's maximum height and the time it takes the ball to reach this height. Then find how long the ball is in the air.
How can I help my son with his algebra homework when I don't even understand it?
Hello,Algebra is an interesting topic for student and teacher both. It is a little complicated but a good mental exercise.If you don’t get an idea of how to help your child. I have a simple and effective solution for you. 15 ways to do Algebra homework efficiently.I will give some certain tips on how you can teach your child a very effective way.A formula is a key for Algebra and max math problem. That should be memorized by the student.Do homework in step by stepSilence is more importance for study. Always work on that your child should study in a silent environment.Doing homework with a friend is also a good Idea. They will discuss the question and answer when they got stuck.Visit some online website regarding mathematics problems. That will give a clear Idea.That all are regarding how to teach your child if you don’t understand Algebra or Math problems.Thanks for reading.
Can someone help me with my algebra 2 homework ?
Before I start, the angle variable "feta" is really spelled "theta." To calculate the amplitude of a sinusoidal function, look at the coefficient (the multiplier) outside of the function, if the function is sine or cosine. For example, the amplitude of y = 3 sin (theta) is 3. This is not the case with tangent, since it has a vertical asymptote at x = pi/2. So tangent has infinite amplitude. To find the period, look at what is inside the trigonometric function (inside the parenthesis). Divide 2*pi by the coefficient inside the parenthesis, and you will get the period. Remember, if there is no number inside the parenthesis, then the coefficient is one. Thus, the period for y = 3 sin (theta) is 2 pi (coefficient is 1). Also, the period for y = 6 sin (4*theta) is 0.5 pi (2 pi / 4). To find the phase shift, you have to look inside the parenthesis again. If you are adding to the angle, you will shift to the left. If you are subtracting from the angle, you will shift the function right. So for y = sin(theta + 90 degrees) + 2, the sine function will be shifted to the left 90 degrees. The vertical shift is found outside the trigonometric function. If you are adding to the function, you will move it up. If you are subtracting, you will move it down. This makes sense since you are adding or subtracting directly to the y value. For your example y = sin(theta + 90 degrees) + 2, you will move the sine function up 2 units. When you describe a transformation, you will need to apply all of the above characteristics: amplitude, period, phase shift, and vertical translation. Here's the first example y = 3 sin (3*theta) - 1 Amplitude: Increases by factor of 3 Period: Shrinks by a factor of 3 Phase Shift: None Vertical Translation: Down 1 unit Things get really tricky when you have an equation like this: y = 3 * (sin (3*(theta-180)) + 2) Is the vertical translation up 2 units? Not so fast. Multiply out the 3 so the equation looks like this: y = 3 * sin (3*(theta-180)) + 6 Now you can see the vertical displacement is really 6. You should do the same with the stuff inside the trigonometric function.
Can someone help me with my Pre-Algebra homework?
Order of operations is the key here. I usually use this PEMDAS which stands for parenthesis, exponents, multiplication/divisions (which ever comes first when going left to right) and addition/subtraction (which every comes first when going left to right) (3a)squared where you would do what is in the parenthesis first so: (3*2)squared (6) squared 36. 3a squared since there are no parenthesis, you would do exponents first so a squared which would be 2 squared= 4 and then that is 3*4 which is 12 (8b) squared same with #1 where you do parenthesis first so (8*-5) squared which is (-40) squared which is 1600 8b squared no parenthesis so exopenents -5 squared is 25 8*25 is 200 Hope that helps you!