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Help Me With This Physics Question I

Can you help me with this physics question?

The pendulum continues in an arc of reduced radius of L-D (L being the length of string).Okaay, so if it can get to the "highest point of the new reduced arc", let's write an energy balance for it: the starting energy (gravitational potential energy mgL) should equal the sum of kinetic energy and potential energy at the "highest point of the new reduced arc".mgL = 2mg(L-D) + 0.5 m v^2             (1) (2mg(L-D) because the ball rises to a height of 2(L-D) or twice the reduced radius)So if you want the D, you need the V. (I'm so sorry.) We can find v from the condition that D is the MINIMUM peg distance for which the string remains juuust taut, so in this limiting case, the tension in the string is juuust zero. Write a force balance for the ball when it is just at the "highest point of the new reduced arc" for this limiting case. Why, the only force seems to be gravity and the only acceleration of the ball is the centripetal acceleration. From Newton's law,m v^2/(L-D) = mg (centripetal acceleration is mv^2/r remember?)or, m v^2 = mg(L-D)                          (2)Substituting the above in Eqn. 1, mgL = 2.5 mg(L-D)or, D = 3/5 L Sic transit gloria mundi.

Help with physics question I'm stuck on?

To get to the top of a lift hill El Toro's train is vertically lifted by 53.3 meters. The average mass of a loaded El Toro train with passengers is 9750 kg. It takes 18.55 seconds to reach the top of the lift hill. What is the work done by the motor to lift the train and passengers to the top of the hill?

Can I please have help with a Physics question?

You’re supposed to just ask the question. People will answer if they feel like it.If it’s a homework question or an exam question, count me out; I don’t answer those. But others do, so you should always indicate whether it is a homework or exam question.

10 Points to who can help me with this Physics Question! (On Energy/Force)?

I have a test tomorrow, and any help would be greatly appreciated! I'm not understanding incline questions, one that i cannot figure out is:

A 45.0 kg box initially at rest slides from the top of an incline as described in the diagram*. If the box reaches the bottom of the incline at a speed of 5.0 m/s, what is the force of friction on the box along the incline.
*(The diagram is of a right triangle symbolizing the incline, the height of the incline is 5.0m and the distance from the top of the incline to the bottome of the incline (the hypotoneus) is 12.5m. The box is drawn at the top of the incline, and that's all the information given on the diagram.)


So any help on inclines or work, energy, and force is very appreciated even if you can't answer the question, i have a test tomorrow, and need to figure this unit out a.s.a.p. Thanks!

Plz help me with this physics question. i'm stuck :(?

When the cylinder rolls, there is a force F=15N at the top and a static frictional force f preventing slipping.
everything in usual notation,
acceleration A=R*a (a=angular acceleration)
Newton's second law implies'
MA=F-f (resultant force)
also for torques,
Ia=FR+fR (for the axis passing through the centre)
FRom the two equatins,
2F=mA+Ia/R
i.e. 2F=maR+Ia/r
a=2F/(mR+I/R)
I=0.5MR^2=0.05
plugging hte values,
a=16
therefore, A=aR
=16*0.1
A=1.6

Can anyone help me answer this physics question?

No, there is not enough information. The position the clown maintains in the air would change his air resistance and thus flight time and distance. However if you assume no air resistance, you can:resolve the vector for the vertical componant (sin23*51), to give the vertical speed initially,divide this value by the acceleration incurred by gravity (9.8ms^-2) and this will give you the time it takes for the vertical velocity to reach 0.Then you calculate the vertical distance travelled during this time (((initial vertical velocity+ final vertical velocity)/2)*time)((sin23*51+0)/2)*((sin23*51)/9.8)=d. This will give you the clowns height.Sub this value into (distance= initial velocity*time+1/2*acceleration*time^2), and hence using the vertical distancetravlled calculated in the previous step d=0*t+1/2*9.8*t^2, you can re-arrange to solve for t. (This should be equal to the value you obtained in step 2)Add the value of t to (sin23*51)/9.8 and you have the time spent in the air.Assuming no air resistance the horizontal speed does not change, so resolve for the vertical component (cos23x51) and multiply this by the time spent in the air and you have distance travelled from the canon.

Plz help me with a physics question I’ve got no idea how to do it?

Dee is on a swing in the playground. The chains are 2.5m long and the tension of each chain Is 350N when Dee is 45 cm above the lowest point of her swing. Tension is a vector directed along the chain, measured in Newtons, abbreviated N.
a) what is the magnitude of the horizontal component of the tension at this point in the swing?
b) what is the magnitude of the vertical component of the tension at this point in the swing?

I’d really appreciate some help I have no idea how to do this and it’s not in my notes.

Can I ask physics questions on Quora?

Yes,you can ask any kind of question on “Quora”.Either you knew answer or not, in both cases you are feel free to ask question and get quality answers from knowledgeable persons.you can follow the Physics - topic there are already 5M+ people those who followed this topic for question answer.

Can solving questions in physics help clear the NEET?

Physics is a subject, which can turn out to be the most scoring section, if understood well. The most important aspect in learning physics is understanding the concepts well. So always keep in mind, keep your CONCEPTS CLEAR.I would recommend you to start your chapter/topic from NCERT. Go through the theory part, understand it well. Highlight the points you think are important. Also mark the areas where you think you are lacking and need further clarification. Clear your doubts from your tutor. If not, surf the internet. You will definitely get some clue. Then attempt the solved and unsolved question of that chapter. The “Summary” and “Points to Ponder” section are very important for the ASSERTION REASON questions in AIIMS.After this move on to HC Verma, Arihant DC Pandey, or your Coaching Institute Material/Booklets(if any). Attempt as many question possible from these resources to get an idea of JEE level questions. HC Verma is a legendary book for preparing Physics for competitives.After completion of the above, move on to Previous Year Questions. Attempting and solving previous year questions is very important to get an idea of what kind of questions are asked in NEET.If you have done all of the above and feel confident about yourself, attempt a mock test on the chapters you have learnt in a stipulated time, say a month.Few more points to remember:Give a lot of time to Mechanics, especially Work Power Energy and Rotation. This is the section which could fetch you 100% score if understood well.You need to practice Mechanics repeatedly and don't lose your concepts. Mechanics need to be revised at least 3 times.Modern Physics is a very easy but conceptual section. Read it thoroughly both from NCERT and HC Verma. Mostly formula based questions are asked from this area.Optics is also a very easy section. Memorise all the formulas and know their right implementation on different types of question.Magnetics, Electrostatics can be a little complicated and confusing. Practice it well!!Memorize the range and frequency of each kind of wave in Electromagnetic Wave chapter well.Always keep brushing up on your concepts, or else you will forget it sooner or later.

Please help me with this physics question. I think I am making this harder than it seems.?

For this problem, you have to use the vector addition rule and the vector magnitude formula.

r = C+D =

= <7.0, -3.5, -6.4> + <4.1, -2.4, 3.3>

= <(7.0 + 4.1), (-3.5 - 2.4), (-6.4 + 3.3)>

= <11.1, -5.9, -3.1>

||r|| = (ri² + rj² + rk²)^(1/2)

= ((11.1)² + (-5.9)² + (-3.1)²)^(1/2)

= 12.9

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