Help With Algebra Equation

Algebra equations need help plz

John's rate (x):
x + 1/3x = $60
3/3x + 1/3x = $60
4/3x = $60
x = $60(3/4)
x = $45

Dennis' rate:
= 1/3($45)
= $15

Answer: $15 is Dennis' rate per hour.

Help with algebra 1-2 math questions???

we are doing system of equations in algebra 1-2 and i have 2 questions that i didnt understand-

1) The ratio of boys to girls in a school is about 3 to 5. There are about 800 students in the school. How many are boys? how many are girls?

2) Niki has 8 coins worth 1.40. Some of the coins are nickels and some are quarters. How many of each coin does Niki have?

[A] 4 quarters and 4 nickels [B] 6 quarters and 2 nickels
[C] 2 quarters and 6 nickels [D] 3 quarters and 5 nickels
[E] 5 quarters and 3 nickels


can you please do them in the format of system of equations AND tell me how you do it??? thank you :)

May you please help me with this algebra equation?

Hey! I've completed my whole algebra worksheet by myself but I'm having troubles with this one equation...
-4/7 p = -8

If you could please show me how to do it step by step so I could learn, that would be great! Thank you so much!

Help algebra linear equation?

First, I will assume simple interest, over a 1 year period.

There are two solutions. One where the amount invested at 4% earned $1600 more, and one where the amount invested at 6% earned more. To solve either way, you will need two equations. For both situations, one equation will be:

x + y = 70000

since the total investment is $70,000.

Let's start with the first case, where the amount invested at 4% earns $1600 more than the amount invested at 6%. The 2 equations are.

1) .04x - .06x = 1600
2) x + y = 70000

First, multiply the second equation by .04, so we can subtract the 2 equations (the Subtraction method).

1) .04x - .06y = 1600
2) .04x + .04y = 2800

Subtracting the two equations, we get:

-.1y = -1200, which simplifies to: y = 12000

Substituting that into the original second equation, we find that x = 58000.

So, the interest earned by $58000 at 4% = $2320,
and the interest earned by $12000 at 6% = $720,
which is a difference of $1600!

**************************************...

Now the second case, where the amount invested at 6% earns $1600 more than the amount invested at 4%. The 2 equations are.

1) .06x - .04x = 1600
2) x + y = 70000

First, multiply the second equation by .06, so we can subtract the 2 equations (the Subtraction method).

1) .06x - .04y = 1600
2) .06x + .06y = 4200

Subtracting the two equations, we get:

-.1y = -2600, which simplifies to: y = 26000

Substituting that into the original second equation, we find that x = 44000.

So, the interest earned by $44000 at 6% = $2640,
and the interest earned by $26000 at 4% = $1040,
which is, again, a difference of $1600!

Hope this helps!

Finite Math..Algebra Equation Help Needed???

I am having problems solving two equations. When I solve them they do not match with the answers in the answers document I have. Here are the equations and the solution.

7^(2x) = 823,543 =====> answer is x = 3.5

500 = 600 - 600e^(-0.4x) ======> answer is x = 4.474

Can someone help me get to these answers... I'm lost??

Best answer gets 5 stars ASAP!!!

Need help with Algebra Rational Equations and Rational Expressions?

Here are a few.

1) Find all numbers for which the rational expression is undefined .
4/v - 8

You can't divide by zero.
Set the denominator equal to zero to find where the expression is undefined.
The denominator is just v, so v = 0 is where the expression is undefined.

If you meant 4/(v-8), then the denominator is v-8.
v-8 = 0 means v = 8, so the expression is undefined when v = 8.

I hope you see the DIFFERENCE between 4/v - 8 and 4/(v-8).

2.) Divide and simplify
c + 6/c - 7 / 2c + 12/c - 1

With no parentheses, your expression is difficult to interpret.
What are the denominators? numerators?

3.) Solve
z - 1/z - 4 = 3/z - 4

Again, you don't have parentheses, but I THINK you mean
(z-1)/(z-4) = 3/(z-4) ....... but I am not 100% sure.

You could also mean z - 1/(z-4) = 3/(z-4).
Or possibly something else.

I'll assume you mean (z-1)/(z-4) = 3/(z-4).
Since the denominators are equal, you can just drop them.
z - 1 = 3
Add 1 to each side.
z = 4
Then go back to the original equation to see if this solution makes sense.
If you plug in z=4, then you will be dividing by zero. Therefore, there is no solution.

4.) Find the LCM of 7(x - 2) and 14(x - 2)
The LCM is 14(x-2).

5.)Solve
x/x + 7 - 7/x - 7 = x^2 + 49/x^2 - 49

Still no parentheses, but let's assume you mean
x/(x+7) - 7/(x-7) = (x^2+49)/(x^2-49)

Note that x^2-49 = (x-7)(x+7).
Multiply both sides by (x-7)(x+7).

x(x-7) - 7(x+7) = x^2 +49
x^2 -7x -7x -49 = x^2 +49
-14x - 49 = 49
-14x = 98
x = -7

Does this solution work in the original equation?
I'll let you determine that.

18.) Add and simplify if possible
4b/5b - 10 + 9b/10b - 20

I'll assume you mean 4b/(5b-10) + 9b/(10b-20).

Factor the denominators.
= 4b/[5(b-2)] + 9b/[10(b-2)]

The common denominator will be 10(b-2).
= 8b/[10(b-2)] + 9b/[10(b-2)]
= 17b/[10(b-2)]

I'll also let you attempt the rest. And please use parentheses the next time. When you have a fraction, it is best to place parentheses around the numerator and the denominator when you have multiple terms.

Help with Algebra! Does the equation have no solution, or is it an identity?

my teacher just gave us these problems without a lesson....
=|

3.6y=5.4+3.3y
4.3v-6=8+2.3v
6.1h=9.3-3.2h
-4.4s-2=-5.5s-4.2

thank you so muchh
it would also really help if you explained it...=]
thankss