Grade 9 Math Help??
i am doing a review for math for the regents and i am having some trouble on some questions. Here are a few of them: 1. For five algebra examinations, Maria has an average of 88. What must she score on the sixth test to bring her average up to exactly 90? 2. The graphs of the equations y = x[squared] + 4x - 1 and y+ 3 = x are drawn on the same set of axes. At which point do the graphs intersect?
Grade 9 Math help?
you would put together the common ones so -3x + 9x = 6x so now you have 9 - 6x - (-8y) - y so now put together 8y - y = 7y but the - is in front of the other - sign. it changes to 9y so now you have 9 - 6x +7y and i fixed my answer but the other person insulting me did not tell you how to get the answer.
Grade 9 math help?
Ok both of these are going to deal with two similar formulas. Volume of a Pyramid =Vp Volume of a Cone = Vc Vp = (length x width)h/3 Vc = (pie*radius^2)h/3 For the Square pyramid we add the answers we know. The Volume is equal to 100 cm^3. Or in other words Vp = 100 cm^3. And we know that the base area is = 40 cm^2. So here's the final formula. 100 cm^3 = (40 cm^2)x(height)/3. we'll call Height 'h'. And now it gives us a variable to work with. This is gonna be a routine algebra problem where the goal is to have your defined data on one side and the undefined on the other. And here's how we do it. Step 1. To remove that pesky "/3", multiply each side by three. 3(100 cm^3) = 3[(40cm^2)x(h)/3] <-- I know that looks complicated but if you write it out on paper it looks easier. 300 cm^3 = 40 cm^2 x (h) Now divide by 40 cm^2 (300cm^3)/(40 cm^2) = (h) 300/40 = 7.5 cm. For the cone one pie is equal to 'y'. Just cause I can't find the pie button. And I know I'm not spelling it right. Diameter 'd' = 34.4 Radius 'r' = d/2. h = 14.2 y = 3.14..... Vc = ([y(34.4/2)^2]*14.2 )/3 Vc = ([y*17^2]*14.2 )/3 <-- it's important to note that you do exponets before the multiplication. So 17^2 then times y. Not y*17 then squared. Vc = ([2829.4]*14.2) /3 Vc = (12885.9)/3 <--division is last. Take that whole number and divide it. I know it's big, but it's right. Vc = 4295.3 cm^3 b.) (Volume of the cone)/6.9 Hope that helps, I know it's long and boring to read...but yeah, I tried to make it easy.
Grade 9 Math Help?
5x+6y=7 is the equation you are given. If you rearrange this equation so that the you can make this equation into y =mx+b format, you will get: 5x+6y=7 6y=-5x+7 -- ---- --- 6 6 6 y= -5/6x+7/6 from this format you can see that the slope of the first line is -5/6 perpendicular lines have slopes so that wen you multiply the slopes you will get -1 you will flip and change the sign of the slope of the first line to get the slope of the lien perpendicular to this -5/6 flipped will be -6/5 and it will be a different sign so it would be positive so m = 6/5 in the line perpendicular to the first line x intercept is four to find the x intercept you set y=0 y=6/5x+b 0=6/5(4)+b 0=24/5+b -b=24/5 divide all by -1 b=-24/5 the line perpendicular to the given equation is y=6/5x-24/5
Grade 9 math help??????????????????????????...
9 1/2 minus 12 1/8 First, make them into fractions instead of mixed numbers 12 1/8 = 96/8 +1/8=97/8 9 1/2 = 18/2 +1/2 = 19/2 Now, in order to subtract you need to get the denominators (bottoms) the same). You can change 19/2 into something/8 by multiplying the top and bottom of the fraction by 4 19/2=(19*4)/*2*4)=76/8 Subtract: 76/8-97/8 = (76-97)/8 = -21/8 Now convert to a mixed terms: -21/8=-16/8+-5/8=-2 5/8 Make sure when you set up the subtraction you take the closing price minus the opening price. This turns out to be negative because the stock price went down. _/
How do I help my daughter cope with maths in grade 9? She is very good in the rest of the subjects.
Mathematics at this level is far more skill-based than knowledge-based. It takes a lot of practice and practice isn’t necessarily “fun”. I’m going to assume her problems are with word problems and we’re talking algebra.My approach is to think “model, pattern, grind”. To get a model she must translate the natural language (or picture or …) into something that is algebraically usable. A lot of this vocabulary: for example, “how far does X travel …” immediately tells me I’ve got a rate problem. Strangely enough, this is a “semantics to syntax” translation. The semantics of the problem must be translated into symbols that make sense in the algebraic world.Once the syntactic problem is available, start looking for patterns. She must know cold all the rules for manipulating algebraic expression. In fact, that’s probably the only thing in quantifier-free algebra that’s useful. Identify meanings of symbols and how they interact.Once you have some things you can work out, start grinding: for beginners, don’t get cute and take shortcuts. These problems are meant to practice patterns and manipulations. Old coots like me can do a lot of cutesy math, but I’ve been practicing a long time.
Grade 9 math homework help please :(?
ok please help me i have 2 questions.. 1) Each side of a square room is 10m. Tiles measuring 45 cm by 45 cm will cover the floor. How many tiles are needed?? 2) Ebonnie has a circular flower bed with a radius of 3.5m. Fertilizer costs $3.49 for a box that covers 20meter square. How much does it cost Ebonnie to fertilize her flower bed? i appreaciate it and i tried doing itbut i didn't understand so dont feel that im lazy thank you soo much <3
I need help in MATH grade 9 math!!?
1 : A = number of adults admitted, S = number of Students admited. Solve in terms of one side A + S = 950 A = (950 - S) 6.5S + 9A = 7675 6.5S + 9(950-S) = 7675 6.5S + 8550 - 9S = 7675 -2.5S = -875 S = 350 A = 950-350= 600 #2: The diagonal divides the square base into two equal area triangles, so the hypotenuse is this diagonal of this square, and the other two sides are equal. A^2 + B^2 = C^2 A^2 = B^2 So... 2A^2 = 23716 A^2 = 11858 A = 108.894444...
Grade 9 Mathematics--Correlation Help!?
it depends on you coordinates. if it is strong it will increase positively weak will be semi-positive but wont be grouped together. no correlation is scattered on the graph no pattern. weak is negative slope and scattered. strong is negative but grouped close.
Do you know any good math books for grade 9+ math?
By grade 9, I assume you are talking about the US Common Core system. Grades 9 and above are considered high school level, somewhat equivalent to Singapore Secondary 3/4 and Junior College 1/2 levelsIn US high schools, students typically go through the "Algebra I - Geometry - Algebra II" sequence, followed by a course in Pre-Calculus and finally, Calculus. Sometimes, Algebra I is done by students already in their 8th grade (middle school).The following books are recommended (click on the Amazon links):Algebra 2: E-Z Algebra 2 (Barron's E-Z Series) Meg Clemens, Glenn Clemens: 9781438000398: Amazon.com: BooksGeometry: Let's Review: Geometry (Barron's Review Course) (9780764140693): Lawrence S. Leff M.S.: BooksPre-Calculus: Pre-calculus Demystified Rhonda Huettenmueller: 9780071778497: Amazon.com: BooksCalculus: 1 . Calculus James Stewart: 9781285740621: Amazon.com: Books2. Barron's AP Calculus, 13th Edition (9781438004976): David Bock M.S., Dennis Donovan M.S., Shirley O. Hockett M.A.: BooksThe above books will give you ample preparation for the SAT Math or the Math I and II subject tests. The Calculus book by James Stewart is somewhat an overkill in that it covers Calculus I (single-variable), II (multi-variable) and III (vector). You only need Calculus I. But the material is really good. On the other hand, the cheaper and more concise Barron's AP Calculus will give you ample preparation for the AP Calculus AB/BC exams.