Graphing linear equations? help?
I need help. I’m not the best at graphing linear equations, I can’t seem to get the gist of it. 1.) x-4y=-4 5x-4y= 12 2.) x+y=3 8x+y=-4 3.) y=-2x-4 y= 1/4x +3 4.) y= -3/2x +4 y= 3/2x -2 5.) x+3y =-12 5x-3y=-6
How do you graph linear equations? I don't understand how it works at all, and I really need help.
Source:Lines - Cool math Algebra Help Lessons - Equations of Lines (Graphing Method 2 - Slope Intercept Form)
Algebra 1- graphing & linear equations help? (:?
I'm taking classes online & they don't give you any review & i haven't seen this stuff for like a year. -__- help? lol. 1. y − 2x = −1 x + 3y = 4 a: (-1, 1) b: (1, 1) c: no solution d: none of the above 2. The graph of a system of equations will intersect at exactly 1 point. a) Always b) Sometimes c) Never 3. Solve the following system by using graph paper or graphing technology. 2x + 2y = –6 3x – 2y = 11 What is the solution to the system? a: (–1, –7) b: (1, –4) c: (2, –1) d: (3, –2) 4. Part 1: Provide a system of TWO equations in slope-intercept form, with only one solution. Using complete sentences, explain why this system has one solution. Part 2: Provide a system of TWO equations in slope-intercept form with no solutions. Using complete sentences, explain why this system has no solutions. Part 3: Provide a system of TWO equations in slope-intercept form with infinitely many solutions. Using complete sentences, explain why this system has infinitely many solutions. if you could help me with this, i'd be so happy~ 5 stars. (: thank you!
HOMEWORK HELP PLZ! Graphing equations!!!?
Ok, basically all you have to do is substitute the value you're given into the equation. So, with the first equation you have: y = 3x - 4 If you make x 50, this turns into: y = 150 - 4 Simplify this and you get the answer: y = 146 So, if we do the same for the next one. y = 3x - 4 goes to: 50 = 3x - 4 This ones a bit more complicated. First you want to get all the numbers onto one side. So, to get ride of - 4 you add 4 to both sides. (Whatever you do to one side, you have to do to the other.) So you get: 54 = 3x Then to find x, divide each side by three. You end up with: x = 18. Hope this helps!
Please help, Solve the system of equations by graphing: 4x - y = 30 and 4x + 5y = -6.?
Since we ordinarily graph equations with y as the dependent variable and x the independent variable, start by solving each equation for y in terms of x: 4x - y = 30 -y = 30 - 4x y = 4x - 30 4x + 5y = -6 5y = -4x - 6 y = (-4 / 5)x - (6 / 5) You can now graph these two equations; the x- and y-coordinates of the point of intersection is the solution to the system of equations. Hopefully, you will find that they intersect at the point, (x, y) = (6, -6); hence, the solution to the system is x = 6 and y = -6.
What are the steps to graphing the linear equation 12x-6y+3=0?
There are 2 ways to approach this the first is to find the x and y intercepts. To find the x intercept subtract 3 from both sides of the equation.12x -6y=-3Substitute a zero for the x.12(0) -6y=-3Simplify-6y = -3Solve for y by dividing both sides by -6-6y÷-6 = -3÷-6Simplifyy = 1/2So when x = 0 y = 1/2 as a point it is (0, 1/2). Graph this point. Now repeat the process only use zero for y.12x -6(0)=-312x = -3x= -3/12 Or -1/4Coordinate pair for the point is (-1/4, 0). Graph this point. Now use a straight edge and connect the two points.Most preferred way change the equation from standard form to slope-intercept form. We do this by solving the equation for all y values.Subtract the constant term to get12x -6y=-3Subtract the term with x variable.-6y = -12x -3Now divide everything by -6 the coefficient of y.Finally simplify.-12÷-6 =2 and -3 ÷-6 = 1/2y=2x +1/2
Help, I'm having Trouble Graphing Polar Equations w/ a Graphing Calculator?
I use the polar function mode of my ti 84 graphing calculator and plug in the polar equations r =.... but my graphs come out all butchered, it doesn't look anything like the ones from my textbook.. What's the problem here? Is my window not correct? Window consists of: theta min, max, step, x min, max, scl, y min, max, scl What does the step represent? Can anyone explain to me how to get the correct graph on my calculator for 10 points?
What is there to like about graphing equations (i.e. quadratic, rational, etc.)?
As a nerd I’m inclined to give two answers:As Glen said, it can be more practical. Especially if the function relates to the modelling of a real-life situation i.e. throwing a ball, or mapping out orbits.The beauty of it! Yes, yes, I’m a nerd, but some of the prettiest structures look butt ugly when written as equations, and absolutely gorgeous as graphs. Whether it’s fractals …Or a Lorenz system…Gosh maths just looks fun sometimes, doesn’t it?Anyway . Have a look at the following videos, for more info on the point of quadratics, and how to graph them. Not sure if you need it, but it seemed like the question was asked because you were studying them, and couldn’t figure out why:
Is it possible to graph any shape with the help of equations?
With Fourier series you can make a function which repeats that shape over and over. By taking more and more terms of the series you can match the shape to arbitrary exactitude. This is because convergence of the Fourier series requires only a very weak condition called “bounded variation”: if you add up all the absolute values of the changes in value (downs as well as ups counting positive) and that total variation does not diverge to infinity as you look at smaller and smaller little wiggles, then Fourier will work.
Need help in ALGEBRA (Writing and Graphing Equations in Two Variables)?
Peaches are being sold for $2 per pound. If x represents the number of pounds of peaches bought and y represents the total cost of the peaches, which best describes the values of x and y? A)The values of both x and y can be any real number. B)The values of both x and y will be real numbers greater than or equal to 0. C)The value of x can be any real number, but the value of y will always be a real number greater than or equal to 0. D)The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.