Help With These Derivatives

Help with derivative!?!?

wow ok this is pretty straight forward.

f(x) = x^3
f '(x) = 3x^2
f '(2) = 3(2)^2
f '(2) = 12

f(x) = sqrt of x
rewrite it as x^1/2
so the derivative is...
f '(x) 1/2x^3/2

lastly the derivative of the last one is
f(x) = x^2 + 3x + 2
f '(x) = 2x + 3
f '(2) = 7

you put the value of 2 into the derivative for the ones asking for f '(2)

Derivative help please!?

y= (5/cos x) + (1/tan x)
y = 5 secx + Cot x
dy/dx = 5 (-secx tanx) + (-cosce²x)
dy/dx = -5secx tanx - cosce²x

y= 7x^2 sin x + 14x cos x - 14 sin x.
dy/dx = 7{2xsin x + x^2 cosx} + 14{1 cos x + x (-sinx)} - 14 cosx
dy/dx = 7{2xsin x + x^2 cosx} + 14{cos x - xsinx)} - 14 cosx
dy/dx = 14xsin x + 7x^2 cosx + 14cos x - 14xsinx - 14 cosx
dy/dx = 7x^2 cosx