Can you help with this physics problem?
Can you help me understand a physics problem?Here is the question you had in your comments section:I did it the same way as Mark Barton.The equation isn't really much help to me because I can never remember the sign convention. Instead, I just think about what makes sense physically. But supposing you need to learn to use it, maybe we can use it.Delta U = Q - W + EDelta U is the change of internal energy, which is zero in this case. E must be the energy added to the system, Q must be heat added to the system, and W must be the work done by the system. But why it's that why, I really don't know!So E = +8.4 x 10^5 J, W = n x 1960 J, and Q = n x 4 x -1960 J, where n is the number of reps. Note the minus sign on the Q.So the equation is:0 = -n x 7840 J - n x 1960 J + 8.4 x 10^5 Jn x 9800 = 840,000n = 85.7But since you can't do a fraction of a rep, then 86 reps.
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The first thing is to draw a picture. This problem looks something as follows -Edit - Sorry Didn't realise you actually added a picture. Here it is -Now first thing you should realise is that this question is begging for the origin to be placed at the position of the golfer (when he hits the ball). All distance are measured relative to that position.So initial position of the ball at t=0 is (0,0)The incline downwards can be expressed by the following equation y=-mx (equation of a straight line with -ve slope that passes through the origin)We're told that the ball lands at a point at a distance of 173m from the tee.Final position of the ball = (173, Y)What we need to find is Y.I hope you know that the trajectory of a projectile is parabolic in nature & the equation of the parabola is -Y = tan (ø)x - gx^2/(2v^2cos^2(ø))This is a trivial derivation. Just refer to wiki - Projectile motionPlug in the values & this basically becomes -Y = x/(√3) - gx^2/2400 (I hope I got that right)Now the final insight is that the point you're interested in (173, Y) is a point in both the line (Y=-mx) & the above described parabola. You've got 2 equations for 2 variables - m, Y.Solve for Y & that's your answer. You can also find the slope of the golf course if need be - m.Notice you don't have to take time into account at all in this problem. That's because we've already calculated the entire trajectory of the golf ball when we derived the equation for the parabola.
I need help with this physics problem.?
2. [3 points] Consider the following “infinite ladder” of resistors: Derive an expression for the equivalent resistance between points a and b in terms of R.
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As the engine rotates one time, it rotates an angle of 2 π radians. One minute is 60 seconds. One rpm = 2 * π/60 = π/30 rad/s ω = 2,400 * π/30 = 80 * π This is approximately 251 rad/s. One hour is 3600 seconds. t = 2.5 * 3600 = 9,000 seconds Let’s use the following equation to determine the angle the engine rotates. θ = ω * t θ = 80 * π * 9,000 = 720,000 * π This is approximately 2.26 * 10^6 radians. I hope this is helpful for you.
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1) and 5). In simple terms: -a capacitor lets high frequency through and blocks low frequency; -an inductor lets low frequency through and blocks high frequency; - a resistor isn't affected by frequency. ________ 1) acts as a low-pass filter because the capacitor is connected across the output; the capacitor therefore 'short-circuits' the high frequency parts of the signal preventing them from reaching the output. 2) has no filtering effect. 3) acts as a high-pass filter as the capacitor blocks the low frequency parts of the signal reaching the output. 4) acts as a high-pass filter because the inductor 'short-circuits' the low frequency parts of the signal preventing them from reaching the output. 5) acts as a low-pass filter as the inductor blocks the high frequency parts of the signal and lets through the lower frequencies.
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A penny with a mass of 2.5 grams is dropped from rest from the top of the Empire State Building, 381 meters high. Neglecting air resistance, what is the speed it will hit the ground with? Will it have a positive or negative velocity? (consider the point of origin) Use only energy equations in your response, NO Kinematics!
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the question is: calculate the change in the force of gravity between two objects if one mass is tripled, the other mass is doubled and the distance between the objects is 1/3 the original distance.Answer Choices: 6f, f/54, f/6, 18f, 54f or f/18
Can you help me with this Physics problem about springs?
For springs E = [math]1/2 kx^2[/math]Since energy is to be conserved and at max height the object has no kinetic energy. So you can say that mgh = 1/2 kx^2The question states mass and the max height and assumes you know g = 9.81. So you can fill in the left side of the equation to = 63.5688. [math]63.5688 = 0.5 [/math] ·[math] 450x^2[/math]Now just find x to equal.. 0.532 to 3.s.f