Trigonometry help?
Radians are a way of measuring angles. A full circumference is 360°. In radians, this is 2π. (So π radians = 180°) But why 2π? Because the circumference of unit circle (circle with r = 1) = 2πr = 2π But why use circumference of unit circle? In trig we often deal with the unit circle, and in that case, the radian measure of the angle just happens to be the same as the length of the arc with the same central angle. And for other circles with radius r, then arc length is just the central angle (in radians) multiplied by r. s = arc length s = rθ (in unit circle where r = 1, then s = θ) In trigonometry, angles are measured in a counter-clockwise direction starting at positive x-axis (this is called standard position). Sometimes an angle is said to be in a clockwise direction from positive x-axis. In that case, the angle has a negative value. An angle has 2 arms (or sides). The positive x-axis is the initial arm, while the other arm is called the terminal arm (or terminal side). https://www.mathopenref.com/trigterminal... Two angles are said to be coterminal if their terminal sides are in the same location. For example, if one angle is 1/4 of a rotation (90° or π/2 radians) about the circle (starting at positive x-axis) and another angle is 1 1/4 rotation (450° or 5π/2 radians), then their terminal arms will both be located along positive y-axis. These angles are said to be coterminal. https://www.mathopenref.com/coterminal.h...
Trigonometry HELP?
you can use your calculator to find the value of arcsine of 1/2 or any other angle. However in trigonometry, 30, 60, and 45 degrees are special angles. A 30 by 60 right triangle has sides of units 1, 2, and 2sqrt3, the hypotenuse being 2. A 45 degree right triangle has sides of units 1,1, and 2sqrt2, the hypotenuse being the latter. you can check this using the pythagorean theorem stating that in a right triangle the sum of the squares of the 2 adjacent sides is equal to the square of the hypotenuse. Remember these: sine = opposite/hypo cos = adjacent/hypo tangent = opposite/adjacent cosecant = 1/sine secant = 1/cosine cotangent = 1/tangent
Trigonometry help....?
None. The smallest positive solution is x = 0.4*pi
Help with trigonometry?
Find the radius of the circle defined by the 70 degree parallel of latitude. and Find the length of the 70 degree parallel of latitude, to the nearest 10 km. Assume that the radius of the Earth is about 6380 km. Thanks!
Help with trigonometry question HELP!!?
To solve this problem you just need to find the change in the distance of the fire using triangles. Set up a triangle where A is the horizontal side, B is the vertical side and C is the hypotenuse. We know B is 3248 and the angle between A and C is first 11.34 and then 13.54. We need to find A with both angles and determine the difference between the two answers. We use the tangent function because it deals with sides A and B (Adj and Opp). tan angle = opp/adj >>> tan 11.34= 3248/A A= 16240 tan 13.54 = 3248/A A= 13533 These 2 A's tell us the distances of the fire from the observer at 2 different points. If you subtract them you can find the displacement of the fire. A1-A2>>> 16240-13533= 2707 ft. This displacement was over a 5 minute period. If you divide the 2707 ft. by 5 minutes you can find ft/min. 2707/5= 541 ft/min There are 5280 ft in 1 mile, so convert feet to miles using this. 541 ft/5280 ft = .102 miles/min. Now we need to convert minutes to hours. There are 60 minutes in one hour so .102 * 60 minutes= 6.15 miles/hr. Final answer= 6.15 miles/hr
More help on trigonometry problems?
Problem A: (1 - cos C)(1 + sec C) = tanCsinC [How would I solve this one using the left side?] (1 - cos C)(1 + sec C) = (1 - cos C)(1 + 1/cos C) = (1 + 1/cos C - cos C - 1) = 1/cos C - cos C = (1 - cos² C)/cos C = sin² C/cos C = (sin C/cos C)(sin C) = tan C sin C Problem B: cotA -1/cotA + 1 = 1 - tanA/1 + tanA I regrouped the identity with parentheses? Disregard solution if I was wrong. (cotA -1)/(cotA + 1) = (1 - tanA)/(1 + tanA) (cotA -1)/(cotA + 1) = (cosA/sinA - 1)/(cosA/sinA + 1) = [(cosA - sinA)/sinA]/[(cosA + sinA)/sinA] = (cosA - sinA)/(cosA + sinA) Divide every term by cosA = (cosA/cosA - sinA/cosA)/(cosA/cosA + sinA/cosA) = (1 - tanA)/(1 + tanA)
Need help from trigonometry problem?
First, put 1+i into component form. Think of it as a point on a graph (1,1). The angle (in degrees) is 45. Therefore, z = cos45 + isin45. Next, find the angles for each. Divide the original angle by 3 (because cubed roots), and then add 120 (360/3) degrees twice. 45/3 = 15 angles: 15, 135, 255 Then, take the cubed root of the number multiplied by cos45 + isin45 (in this case this number is 1, so the cubed root is just 1). Now just put it all together. Multiply the cubed root of the number (1) by the cosine and i times the sine of each of the three angles. Answer: z1 = cos15 + isin15 z2 = cos135 + isin135 z3 = cos255 + isin255 - Anonymous