Java Question - Programming Project?
You have a variable named lineup in the main function and in the Car class. This is not likely what you intended. For your code to function correctly in main you would need something like lineup.lineup[1] to access a car. It would be better if you put the lineup, that is the array of Cars, code in the Dealership class. It would be more obvious what is going on and the Car class would not be both a Car and a lineup of Cars.
The easiest way to do this is to take a basic course in Java programming, where you will learn the fundamentals of Java input operations, comparison operators, and output operations. From that you will find this program to be quite trivial.You can find these sort of classes at your local state Universities, as well as in a large number of online tutorials. As a professor at one such University I have my preference for which path you take (cough, cough, mortgage, cough) but you do what is best for you.
How can I fix this in my Java Program?
you're lacking a line of code. you have displayed "a=", "b=", and "entire", and you have calculated entire in simple terms positive. Now upload a line for device.out.println(entire); this could show the fee of the entire variable. 10 pts plz. :) everybody is telling you which you have tousled on the charges around the be conscious entire. it is not real. you have in simple terms printed the be conscious entire above the place the fee might desire to pass. After the line the place you positioned the fee of entire to be the sum of A and B, in simple terms print the fee of entire. it particularly is a greater expert look. think of exterior the container right here people. someone can label their values on the output show screen. this is all, and that i nonetheless am lacking 10 pts. :)
import java.util.Scanner;import java.util.Scanner;public class SumofTenNumbers{public static void main(String []args){java.util.Scanner in=new java.util.Scanner(System.in);int[] array=new int[10];int sum=0;for(int i=0;i
[Java] Strange problems with Scanner?
I've run into this problem with the way scanner operates nextLine() returns the entire line and removes the newsline char from the input stream nextDouble(), nextInt(), etc removes the next token that is that data type but leaves newline chars in the stream. You will have problems mixing these types of inputs. The easiest way to avoid the problem is to use nextLine() to read the entire user input through the newline and parse it with Integer.parseInt(str) or Double.parseDouble(str) > Later versions of Java allow you to switch(..) on a string. But you really should do it the easier way: char anyMore = inputScanner.nextLine().charAt(0); and then switch on that char: case 'Y': case 'y': Better yet: char anyMore = inputScanner.nextLine().toUpperCase().ch... now your case can just be the upper case: case 'Y': Hopefully these comments help: I don't really feel like debugging your entire code... ...
Multidimensional array in java?
I would do it like this int[][] x1 = {{1,2,3},{1,2,3}}; int[][] x2 = {{4,5,6},{4,5,6}}; int[][] x = new int[x1.length+x2.length][]; int ix = 0; for(int i = 0; i < x1.length; i++) x[ix++] = x1[i].clone(); for(int i = 0; i < x2.length; i++) x[ix++] = x2[i].clone(); The clone method creates a copy of an array. A two dimensional array is an array of one dimensional arrays. If I copy it I must make sure to also copy the arrays contained inside. Otherwise a change to one of the two arrays will automatically change both arrays. e.g. int[][] x = {{1,2,3},{1,2,3}}; int[][] y = x.clone(); x[0][0] = 7; System.out.println(y[0][0]); This would print out 7 because y[0] is an array and that array is not a copy of x[0] but it's the very same array. However if I do this int[][] x = {{1,2,3},{1,2,3}}; int[][] y = x.clone(); for(int i = 0; i < y.length; i++) y[i] = y[i].clone(); x[0][0] = 7; System.out.println(y[0][0]); Now it prints out 1 since x and y are now independent of each other. @husoski: My code already solves the problem by calling clone() on every contained array. So there is no need to go through the array again,
As you might be knowing that that outputs that a displayed in java are of string type.So no matter whatever may be the datatype of the variable you are displaying it is converted into string datatype and concatenation operation is performed on it.So if you want to display 12 in 3 digits i.e. 012 you just have to concat a string.The following code helpsSystem.out.println(“0"+a);where a is the variableThe code is:Hope you find the answer useful
This can be done in two different wayMethod 1 : this method uses type casting.Method 2 : this method uses the concept of ceil() and floor() function.Just go through the below code , i’m sure you will get it. code is written in Code::Blocks 16.01//Program to check whether number is int or float//July 17,2018//Narayan Lal Menariya#include
Write a SQL Query using SUM function?
I did the following one: 1)Write a SQL query to display the item description, price, quantity on hand, and value (PRICE * QOH) for item ID 5.in the Clearwater Traders database? SELECT ITEM_DESC, INV_PRICE, INV_QOH, (INV_PRICE * INV_QOH) AS VALUE FROM ITEM, INVENTORY WHERE ITEM.ITEM_ID = INVENTORY.ITEM_ID AND ITEM.ITEM_ID = 5; But I don't know how to do the following. I'm stumped. 2)Write a SQL query to display the item description, price, quantity on hand, and value (PRICE * QOH) for item ID 5.in the Clearwater Traders database, ALSO, calculate the sum of the values for all items, and display the output? Thanks
First of all as we have given an array 3 3 9 9 5, find the prefix_sum[i]%m.which will be 3 6 1 3 1.The key-logic is, if the larger index(say j) has smaller prefix_sum than any smaller index (say i), then that sub-array (from i to j) can be a contender for our solution provided it's sum%m is maximum.Consider following example : array is 3 2 7 4 and m = 7prefix_sum[i]%m = 3 5 5 2indices : 1 2 3 4Now prefix_sum % m for i = 1 and j = 4, prefix_sum[i] > prefix_sum[j], which means that sub-array from i to j (excluding i) is a contender. In simple words, prefix_sum[1]%m = 3 and prefix_sum[4]%m = 2, it means 6 or some multiple of 6 would have been added to get prefix_sum[j]%m, which is desired result.What we can do, is sort the array by their prefix_sum and corresponding indices.2 3 5 54 1 2 3Now, we have to find the minimum difference b/w all the prefix_sum % m, such that the first one's index is larger than the latter one's index, which is 1. Now subtract it from m and find the answer, which is 6 in this case.Tell me if I suck at explaining things. :P[C++] #include