What mass of oxygen would be produced by heating sodium nitrate? (NaNO3(s) NaNO2(g) + O2(g).?
Decomposition of sodium nitrate to NaNO2 and O2 2NaNO3(s) --Δ-> 2NaNO2(s) + O2(g) 1.00g ............. ................... ......?g 1.00g NaNO3 x (1 mol NaNO3 / 85.0g NaNO3) x (1 mol O2 / 2 mol NaNO3) x (32.0g O2 / 1 mol O2) = 0.188g O2 For each gram of NaNO3, you will produce 0.188g O2. You don't specify the mass of NaNO3, therefore, we have calculated a "ratio" for you. Simply multiply the mass of NaNO3 by the ratio, otherwise known as a conversion factor.... __ g NaNO3 x (0.188g O2 / 1 g NaNO3) = __ g O2
What happens when NaNO3 is heated?
Heating metal salts in a dry test tube and observing the change taking place there, is a preliminary way of detecting the presence of certain radicals (ions) in it. While most metal oxides decompose upon heating, to produce metal oxide and brown coloured nitrogen dioxide and oxygen, sodium nitrate (and potassium nitrate) upon heatling decomposes to produce sodium nitrite and colourless and odourless oxygen gas. The colourless oxygen gas is characterized when it rekindles a glowing wooden splinter. The nitrite of sodium (and potassium, of course) is stable to heat.2NaNO3 (s) → 2NaNO2 (s) + O2 (g)Our WebsiteTourist Guide | Tour Guide App | Tour Guides in India
What is the charge of N in NaNO3? Is that the same as the oxidation number of N?
The formal charge of nitrogen is +1 and it’s oxidation state is +5, so no, they’re not the same.For the formal charge, we can ignore the sodium and just look at the nitrate anion (see image below). In a nitrate anion, there is a central nitrogen atom that is bonded to three oxygen atoms. Even though the overall charge of the ion is -1, it actually contains two oxygens with -1 charge, partially balanced by a +1 charge on the nitrogen.Formal charge = number of valance electrons - ( number of bonded and unbonded electrons).For nitrogen in nitrate, this is: Formal charge = 5 - 4 = +1.For the oxidation number, you just need to sum up all the oxidation states to get the overall charge.For NaNO3 this is : Na = +1, N = x and O = -2 and overall equals 0.I.e. 1 + x + (3*-2) = 0. Therefore x = +5. That is, the oxidation state of nitrogen is +5.
How do I determine the molar mass of NaNO3?
Just look at the periodic table. Sodium Nitrate compound has three elements; Sodium (Na), Nitrogen (N), and Oxygen (O). It’s molar mass is found with addition of the elements’ molecular mass. Sodium is 22.9897g/mole, Nitrogen is 14.0057g/mole, Oxygen is 15.999g/mole. So, 22.9897 + 14.0057 + ( 15.999 x 3 ‘because of three oxygen’ ) = 84.9924g/mole of Sodium Nitrate (NaNO3) depends on this describe.On the other hand, if we want to find molar mass of Sodium Nitrate with own way, we will use cryoscopy technique and we will look freezing point depression.
What mass of oxygen would be produced by completly deomposing 4.25g of sodium nitrate NaNO3?
The reaction says, 2 moles of NaNO3 decomposes to give 2 moles of NaNO2 and one mole of O2. So, we have to find how many no. of moles 4.25g of NaNO3 would make. As, no. of moles=given mass/Molecular mass, computing molecular mass of NaNO3, we get it to be 85 amu. no. of moles of NaNO3 are 4.25/85 = 0.05 therefore it gives 0.05/2= 0.025 mole of O2. mass of 1 mole of O2 is 32 grams. mass of 0.025 mole should be 0.025*32/1 =0.8 grams. If you want you can find mass of NaNO2 formed by using law of conservation of mass. Hope you understand this!
How many oxygen atoms are in 125.0 g of sodium nitrate?
Hi! Your exactly right ! Perfect! That is exactly the same steps i do. Only thing i can suggest is you do not need to indicate 2.656*10^24 atoms 2.66 *10^24 atoms of Oxygen would 2.7*10^24 atoms of oxygen would be better because the whole point of scientific notation is to make it simple and short. However if your following significant digits rule your right! Your on the right track good job!
What volume of oxygen gas is produced by the decomposition of 100.0 g of sodium nitrate?
2 NaNO3 --> 2 NaNO2 + O2 NaNO3's molar mass = 85 100 g NaNO3 = 1.18 moles moles of O2 = 1/2 x 1.18 = 0.59 moles volume of O2 in STP will be 0.59 x 22.4 = 13.216 L
What will form when NaNO3 is strongly heated?
Heating metal salts in a dry test tube and observing the change taking place there, is a preliminary way of detecting the presence of certain radicals (ions) in it. While most metal oxides decompose upon heating, to produce metal oxide and brown coloured nitrogen dioxide and oxygen, sodium nitrate (and potassium nitrate) upon heatling decomposes to produce sodium nitrite and colourless and odourless oxygen gas. The colourless oxygen gas is characterized when it rekindles a glowing wooden splinter. The nitrite of sodium (and potassium, of course) is stable to heat.2NaNO3 (s) → 2NaNO2 (s) + O2 (g)So basically, when NaNO3 is strongly heated in a closes vessel, one O2 molecule is liberated and NaNO3 is left behind as increase in temperature always favours forward reaction.
127.6 grams of NaNO3 is how many moles?
The molecular mass of NaNO3 is 84.99 g/mole. So 127.6 g is 126.7/84.99 = 1.49 moles
How many grams are in 2.67 moles of NaNO3?
Solve it like thisTake your 2.67 moles and multiply it by (molar mass)/1 Mole. This will give your the grams.Molar mass is found on any periodic table, typically below the element's abbreviation.