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Ok so you know.. 1.N.05+D.1+Q.25=4.05 2.D+7=N 3.N+D+Q=40 ok first you wanna get rid of one the variables in the 1 and 3 equation, you can do this by using the addition method, so im going to multiply the 3 equation by -.25 -N.25-D.25-Q.25=-10 + N.05+D.10+q.25=4.05 = -.N.20-D.15=-5.95 ok now you wanna take the equation D+7=N and alter it to N-D=7 Then multiply the equation by .2 N.2-D.2=1.4 + -N.20-D.15= -5.95 = -D.35=-4.55 divide both sides by -.35 D=13 you now know you have 13 times so you plug it into equation 2 13+7=N N=20 Then you plug N and D into equation 3 13+20+Q=40 Q=7 So the final answer is you have 7 Quaters, 20 Nickels, and 13 Dimes
How can i solve this problem??4?
To find the length of the side opposite the 42.4 angle. Sin 42.4 = x/55.5 55.5 (sin 42.4) = x 37.42 = x Then you can use the pythagorean theorem to find the length of the third side. (37.5)² + b² = (55.5)² 1406.25 +b² = 3080.25 b² = 1674 b = 40.91 Now add the 3 sides to find the perimeter. 40.91+ 37.42 + 55.5 133.83
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James and Sarah stand on a stationary cart with frictionless wheels. The total mass of the cart and riders is 130 kg. At the same instant, James throws a 1.0 kg ball to Sarah at 4.5 m/s, while Sarah throws a 0.5 kg ball to James at 1.0 m/s. James’s throw is to the right and Sarah’s is to the left. a. While the two balls are in the air, what is the velocity of the cart and its riders? b. After the balls are caught, what is the speed of the cart and its riders?
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1. a. First find the mass of 1.43L of octane from the density given. Mass = Density x volume = 1.43 * 0.702 = 1.004 kg b. Then find out how many moles of octane in 1.004 kg. 1 mole of octane is (8 * 12) + (18 * 1) = 114 grams. So there are 1004 / 114 = 8.8 moles (approx). c. 1 mole gives out 5.45 x 10^3 kJ. So, 8.8 moles of octane will give 5.45 x 10^3 x 8.8 = 4.8 x 10^4 kJ Answer: approx 4.8 x 10^4 kJ 2nd problem can be solved in a similar manner. 1 mole of iron = 56 grams. 224 g gives out 1.65 x 10^3 kJ Therefore, 100 g gives 0.737 x 10^3 kJ Answer: 7.37 x 10^2 kJ
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