Simplify exponent equation?
Your negative number comes from ^-5 term ****Because a negative raised to an odd exponent is negative Example: -2^3 = -2 * -2 * -2 ==> -8 but if the exponent is positive -2^4 = -2 * -2 *-2 * -2 ==> 16 So all your calculations are right, it's negative because you have a negative number raised to an odd exponent. Hope that helped! ***oh and you might be thinking that -4^2 will give you a positive, but the ENTIRE term is negative, not just the 4, so you have to look at it like (-(4^2v^7w^-2))^-5) Hope I didn't confuse you!
Simplify variables with an exponent. Process used?
I'm not sure exactly what you're asking but in general here are some problems w/exponents: x^5 + x³ ....we can factor this. what do they have in common? x³ x³ (x² + 1) ....factored. --- How about multiplying them? x³ * x² ...since the base (x) is the same, we may multiply these. you keep the base, and add the exponents x^ (3+2) = x^5 ---- Now, division: x³ / x² Again, the base (x) is the same. this time, we subtract the exponents. x^(3-1) = x --- If you have (x³)² , ie. a power raised to a power, you multiply the exponents. x^(3*2) = x^6 ---- (xy)³ ...Each term inside the parenthesis is cubed. x³y³ ---- Finally, let's do an example: x³y³ / xy ..... Here, you must remember that you must have the same base (x or y) to simplify On the bottom, we have x & y, which is the same as x^1 * y^1 x^(3-1) * y^(3-1) = x²y² Again, Im sorry I couldnt answer a specific question but maybe these will help ya. Below is a good wesite for reviewing exponents.
How can I get rid of exponents in an equation?
I mean, you can’t “get rid” of them, but you can move them. For example[math]x^2=10[/math]I want very badly to know what x is explicitly. You know how when you have multiplication and you want to “undo it” you multiply both sides by the reciprocal? Exponents work similarly[math](x^2)^{.5}=10^{.5}[/math]Which then reduces cleanly to (If you’re not sure how this happens exactly, look into exponent rules a little bit to freshen up)[math]x=10^{.5}[/math]Which is more commonly written as[math]x=\sqrt{10}[/math]Technically, plus or minus the square root of 10.
Simplifying radical equations with variables and exponents?
It is simple first of all you need to know that sqrt(a*b) = sqrt(a)*(sqrt(b) so sqrt(169*s^5*t^10) = sqrt(169)*sqrt(s^5)*sqrt(t^10) sqrt(169) = 13 sqrt(s^5) is the same of = (s^5)^1/2 so it is equal to s^(5/2) sqrt(t^10) is the same of = (t^10)^1/2 so it is euqal to t^(10/2) = t^5 s^(5/2) is the same of = s^(1/2) * s^(2) = s^(5/2) because (1/2)+(2) = 5/2 so you have 13*s^(2)*s^(1/2)*t^5 13*s^2*t^5*sqrt(s)
Simplify. assume that variable exponents represent positive integers.?
I could have done with a few more parentheses to clarify, but I read this as: ((t^m)^n) * ((t^n)^(n - m)) Simplify. Raising an exponent to another exponent results in an exponent that is the product of the two. (t^(mn)) * (t^(n² - mn)) Multiplying two terms that have the same base but different exponents results in the same base with an exponent that it is the sum of the original two: t^(mn + n² - mn) Combine like terms. t^(n²)
How can I add variables with different exponents?
1.) You CAN’T add or subtract them.2.)You CAN multiply or divide them.Example:x^2(x^3) = x^(2+3) = x^5
Simplify (assume the variable exponents represent positive integers): x^2(x^k - x^k^-^1 + x^k^-^2)?
If you want k - 1 all in the exponent of x, then write x^(k-1). I assume you wanted to simplify: x^2(x^k - x^(k-1) + x^(k-2)) = Since k is positive, k-1 must be smaller than k and k-2 must be smaller than k and k-1. So factor out x^(k-2) (x^2)*(x^(k-2))*(x^2 - x + 1) = (x^(2+k-2))*(x^2 - x + 1) = x^k(x^2 - x + 1) = x^(k+2) - x^(k+1) + x^k Hope this helps you!
Simplify the expression. Assume that the variables in the denominator are nonzero?
1. When multiplying terms, you are adding exponents. When dividing terms, you are subtracting exponents. E.g... (30a^6b^7/a^1b^4)(2b^2/6a^3b^9) = 30 * 2/6 * a^(6)b^(7 + 2)/(a^(1 + 3)b^(4 + 9)) = 10a^(6 - 4)b^(9 - 13) = 10a²b^(-4) 2. Set each term with the power of -3 to get: 4^(-3)/(xy²)^(-3) = (xy²)³/4³ [note that a^(-n) = 1/aⁿ] = x³y^(2 * 3)/64 = x³y^6/64 The last problem is the combination of first and second problems. 3. Assume that the semi-simplified expression is (y^3x^(-6))^(5)/(x^(-4)y³)^(4). Then, y^(15)x^(-30)/(x^(-16)y^(12)) = y^(15 - 12)x^(-30 - (-16)) = y³x^(-30 + 16) = x^(-14)y³ I hope this helps!
Simplify the expression but how without using negative exponents. Assume that all variables are positive?
Simplify the expression. Write your answer without using negative exponents. Assume that all variables are positive real numbers. ( a ^(5/2) x c^(1/4) )^-2