How far down the opposite will it land?
A colony of troglodytes has been in a lengthy feud with its neighbors on the adjacent cliff. Colony A finally develops an important military breakthrough: it rolls bombs off its cliff at known rates of speed, thus gaining pinpoint accuracy in its attacks.If the cliffs are separated by 42.3 m and a bomb is rolled at 5.4 m/s, how far down the opposite cliff will it land? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of m.
How far down the opposite cliff will it land? and at what speed must a bomb be rolled to get him?
If the cliffs are separated by 48.1 m and a bomb is rolled at 6.3 m/s, 1) how far down the opposite cliff will it land? (The acceleration due to gravity is 9.8 m/s2 .) From the information above, I assume that the direction of the bomb’s initial velocity is horizontal; and the height of the two cliffs is the same. To determine how far down the opposite cliff will it land, we need to determine the time the bomb is in the air. Use the following equation to determine the time. Horizontal distance = horizontal velocity * time 48.1 = 6.3 * t, t = 48.1 ÷ 6.3 ≈ 7.635 seconds Use the following equation to determine how far down the opposite cliff will it land. d = vi * t + ½ * 9.8 * t^2, vi = 0 d = ½ * 9.8 * (48.1 ÷ 6.3)^2 The distance is approximately 285.63 meters The troglodyte war continues, and a particularly offensive member of colony B is located 141 m below the top. 2) At what speed must a bomb be rolled to get him? This time, we know how far down the opposite cliff will it land. (141 m) We can use this information and the following equation to determine the time the bomb is in the air. d = vi * t + ½ * 9.8 * t^2, vi = 0 141 = ½ * 9.8 * t^2, t = √(141 ÷ 4.9) ≈ 5.364 seconds Horizontal distance = horizontal velocity * time 48.1 = horizontal velocity * √(141 ÷ 4.9) horizontal velocity = 48.1 ÷ √(141 ÷ 4.9) ≈ 8.9667 m/s
Villain cliches?
i am writing a story making fun of all those stories with cliched villains, does anyone know of a list of villain cliches? thanks! Additional Details 0 seconds ago like an online list or if you know any write them here thanks
How do you survive impact with the ground falling at terminal velocity without a parachute?
Pray.Based on wind resistance, for example, the terminal velocity of a skydiver in a belly-to-earth (i.e., face down) free-fall position is about 195 km/h (122 mph or 54 m/s).At 195 km/h, you can’t do much to survive. Of course, people have survived falling at terminal velocities, but the events that caused them not to die were beyond their control.Vesna Vulović: She fell from 10,160 meters high. In an interview, she commented that according to the man who found her, "...I was in the middle part of the plane. I was found with my head down and my colleague on top of me. One part of my body with my leg was in the plane and my head was out of the plane. A catering trolley was pinned against my spine and kept me in the plane. The man who found me says I was very lucky. He was in the German Army as a medic during World War II. He knew how to treat me at the site of the accident."Ivan Chisov: He fell from a height of about 7,000 m. Chisov struck the edge of a snowy ravine at an estimated speed of somewhere between 190 and 240 km/h, then slid, rolled, and plowed his way to the bottom. The aerial battle had been seen by cavalry commanded by General Pavel Alexeyevich Belov. When Chisov was seen falling to the ground, cavalrymen rushed to the site, and were surprised to find Chisov alive, still wearing his unopened parachute. Chisov regained consciousness a short time later.Alan Magee: He fell from a height of 6,700 m. He crashed through the glass roof of the St. Nazaire railroad station. The glass roof shattered, mitigating the force of Magee's impact. Rescuers found him still alive on the floor of the station.Nicholas Alkemade: He fell from a height of 5,500 m. His fall was broken by pine trees and a soft snow cover on the ground. He was able to move his arms and legs and suffered only a sprained leg.Juliane Koepcke: She fell from a height of about 3,000 m. The LANSA Lockheed Electra OB-R-941 commercial airliner was struck by lightning during a severe thunderstorm and broke up in mid-air, disintegrating at 3.2 km. Koepcke, who was seventeen years old, fell to earth still strapped into her seat. She survived the fall with only a broken collarbone, a gash to her right arm, and her right eye swollen shut. "I was definitely strapped in [the airplane seat] when I fell," she said later. "It must have turned and buffered the crash, otherwise I wouldn't have survived."
PHYSICS PROBLEM!! NEED ANSWER BY TOMORROW!?
A colony of troglodytes has been in a lengthy feud with its neighbors on the adjacent cliff. Colony A finally develops an important military breakthrough: it rolls bombs off its cliff at known rates of speed, thus gaining pinpoint accuracy in its attacks. Part 1: If the cliffs are separated by 44.9 m and a bomb is rolled at 5.1 m/s, how far down the opposite cliff will it land? The acceleration due to gravity is 9.8 m/s2 . Answer in units of m. Part 2: The troglodyte war continues, and a particularly offensive member of colony B is located 143 m below the top. At what speed must a bomb be rolled to get him? Answer in units of m/s. ** I figured out part 1, but I'm stuck on part 2. I don't know what to do!
A colony of troglodytes has been in a lengthy feud with its neighbors on the adjacent cliff?
A/. There will be no horizontal forces acting on the bomb in the horizontal direction, meaning no horizontal acceleration and therefore the horizontal velocity is constant. Therefore the time it takes to hit the opposite side of the cliff will be horizontal distance divided by horizontal velocity = (43.8 m)/(5.1 m/s) = 8.588 s. Now we turn our attention to the vertical direction. The vertical distance it travels, which is how far down the cliff it hits, is the distance it falls in 8.588 s. As the bomb leaves the cliff travelling horizontally, its initial vertical component of velocity is 0 m/s, and therefore the distance it has fallen as a function of time is d = 1/2 at² where a is the acceleration due to gravity. As this is equal to 9.8 m/s² the distance is d = 4.9t² and substituting the given value of t gives a distance of 361 m. B/. First find the time it takes to fall 147 m. t² = 147/4.9 = 30 and taking the square root gives a time of 5.477 s. So the bomb must travel a horizontal distance of 43.8 m in a time of 5.477 s and therefore its horizontal velocity must be (43.8 m)/(5.477 s) = 8.00 m/s.