A. Suppose you wanted to produce 1.00 L of a 3.50 M solution of H2SO4?
A)1. H2SO4 is the solute 2. Water is the solvent 3. Molarity = moles of solute / liter of solution = N / V Rearrange the formula to find N N = M x V Here are the known values, M = 3.5M N = x mol V = 1.00L Plug it in and solve for N(the number of moles of H2SO4 in the solution) N = 3.5M x 1.00 L = 3.50 mol of H2SO4 Molecular weight of H2SO4 is 1g/mole H x 2 + 32.1g/mol S + 16g/mol O x 4 = 98.1g/mol H2SO4 N = molecular weight / mole = X /mol Rearrange to get X = N x mol Solve for unknown X X = 98.1g/mol H2SO4 x 3.50mol H2SO4 = 343g H2SO4 <-answer B) Given values and unknown M = 1.75M Ba(NO3)2 V = 2.50L N = x mol M = N / V rearrange into N = M x V N = 1.75M Ba(NO3)2 x 2.50L = 4.375mol Ba(NO3)2 molecular weight of Ba(NO3)2 = 137.33g/mol Ba + 14.01g/mol N x 2 + 16g/mol O x 6 = 261.35g/mol Ba(NO3)2 N = molecular weight / mole = X /mol Rearrange to get X = N x mol Solve for unknown X X = 4.375mol Ba(NO3)2 x 261.35g/mol Ba(NO3)2 = 1143g Ba(NO3)2. <--answer
A. Suppose you wanted to produce 1.00L of a 3.5M solution of H2SO4?
the solute : H2SO4 the solvent : water molarity = (mass/MW) / Liters of water 3.5mol/L = (mass/98.078)mol / 1L mass of H2SO4 = 343.27 grams molarity = (mass/MW) / Liters of water 1.75 = (mass/261.337) / 2.5 mass = 1143.35 g . .
How many liters of solution can be produced from 2.50 moles of solute if a 2.00 M solution is needed?
2.5mol/xL = 2.00 mol/L x = 1.25 L
How do you make a 3M solution of KBr? How many moles of KBr are in 1 liter of a .03 M solution?
M = molarity = moles of solute/1 L of solution Therefore, 3M KBr = 3 moles of KBr/1 L of solution 3 moles of KBr = (3 moles)*(119.002 g/mol) = 357.006 g of KBr (molar mass from http://en.wikipedia.org/wiki/Potassium_b... So one could prepare a 3M KBr solution by dissolving 357.006 g of solid KBr in water to a total volume of 1 L. "... How many moles of KBr are in 1 liter of a .03 M solution ..." molarity = moles of solute/1 L of solution 0.03M KBr = 0.03 moles/1 L of solution Can you see the answer now?
How many moles of KI are present in 500ml of a 0.2 M solution?
M (Molarity) means ‘moles per liter’, and 500 mL is half a liter, so 500 mL of 0.2 M solution contains 0.1 moles.
What is the mole fraction of the solute in a 2.5m aqueous solution?
According to me, 2.5 molal aqueous solution means 2.5 moles of solute in 1 kg solvent,⇒ moles of solute=2.5moles of water=1000/18=55.55(1000/ H2O as water has 18)so mole fraction = 2.5/(2.5+55.55)=(moles of solute/ moles of solute +solvent)=0.043(approx)Hope it helps…
What is the molarity of resulting solution obtain by mixing 2.5L of 0.5M urea solution and 500ml of 2m urea solution?
No. Of moles in first solution = 0.5 x 2.5 = 1.25No. Of moles in the second solution = 2 x 0.5 =1Total moles = 1.25 + 1 = 2.25Total volume = 2.5 + 0.5 = 3.0Molarity = 2.25 ÷ 3 = 0.75 M
How much 0.7M solution of (NH 4) 2 SO 4 do you have to use so that it contains 3.500g of the substance?
This is a Molarity problem.First, we start with the Molarity formula which states thatM = (moles of solute) / (volume of solution in liters)M = mol / LWe now need to find how many moles of the substance 3.500 g is equal to.We are given 3.500 g of the substance so we need to convert this to moles.Simply add up all the atomic masses of the elements in the substance for how many of each there are. (You get these values from the periodic table as the number under the Symbol)From this we get the number 132. This means that a single mole of substance is 132 grams. Divide the given number 3.500 g by 132 g to get the number of moles.This yields 0.0265 moles when roundedNow we can plug in our given value for M and the number of moles into the equation to solve for Liters!M = mol / L0.7 = 0.0265 / LSimply solve for Liters and we get0.0379 Liters of (NH4)2SO4Hope this helps!
How many moles of H2SO4?
molarity = (moles of solute) / (liters of solution) or moles of solute = (molarity)(liters of solution) molarity = 4.25 M liters of solution = 2.50 L moles of H2SO4 = (4.25 M)(2.50 L) moles of H2SO4 = 10.6 mol Answer: There are 10.6 moles of H2SO4 are in 2.50 L of a 4.25 M aqueous solution.
How much solution can be made with a 2.50M solution using 50g of PbO?
2.5M = 2.5mol/L50g × 1 mol/223.2g = 0.224 mol of PbO available0.224 mol × 1 L/2.5 mol = 0.0896 L of 2.5M PbO solution can be made from 50g of PbO.Or 89.6 mL of 2.5M PbO solution can be made from 50g of PbO.