For every mole of NaCl in water, how many moles of ions are generated?
The balanced equation you give tells you. One mole NaCl gives 1 mole Na+ and 1 mole of Cl- .. total TWO MOLES of ions. However, if you want to be very accurate, you should give the answer ZERO because the Na+ and Cl- ions AREN'T generated by the water at all .. they are present in the original salt crystal. One mole of NaCl aready contains 1 mole Na+ and 1 mole of Cl- .. total TWO MOLES of ions. Is this meant to be a trick question? It is certainly liable to confuse many students like you! Does your teacher actually have a chemistry degree as it is a silly question to ask.?
How many moles and molecules of water are there for every ion of Cl- in the solution?
MWt (4 sig fig) of BaCl2 is 208.2 hence 45.0 g is 45.0/208.2 = 0.2161 mol. In soln this produces 0.4322 mol of Cl^-. Concentration in 750 mL = (0.4322/750)×1000 = 0.5763 M Conc of water (divide by MWt of H2O) =(748/750)[1/18.015]×1000 = 55.36 M Moles of water that are there for every ion of Cl- in the solution = 55.36/0.5763 = 96.1 mol # molecules (X Avogadro Const) = 96.1×(6.022×10^23) = 5.78×10^25 molecules (!)
How many moles of ions are there in 2.5mol of NaCl?
We usually talk about a solution so, let me rephrase your question. How many ions of Na+ and Cl- are present in a solution in which 1 mole of NaCl is completely dissolved in water?First, NaCl is very soluble in water.Solid NaCl dissociates completely into ions of Na+ and Cl- when forming an aqueous solution. This is written:1 NaCl (s) → 1 Na+ (aq) + 1 Cl- (aq)There are two moles of ions (one sodium and one chloride) on the product side. A mole is Avagadro’s number.2 moles x 6.02 x 10^23 ions/mole = 1.2 x 10^24 ions.
If we have 0.2 molar solution of NaCl (for example),how come the molarity of ions (Na+) = 0.2M and (Cl-) = 0.2 M is also the same?
NaCl dissociates in a 1:1:1 ratio according to the equation:NaCl --> Na+ + Cl-So, based on this ratio if you have 0.2 molar NaCl you will get 0.2 molar Na+ and Cl-. The 1:1:1 ratio means that the molarity of each of the ions will be the same as the molarity of NaCl.Contrast this to the situation for MgCl2. This dissociates in a 1:1:2 ratio:MgCl2 --> Mg2+ + 2Cl-In this case if you have 0.2 molar MgCl2, it will dissociate to give 0.2 molar Mg2+ but 0.4 molar Cl- because there are twice as many Cl- ions as MgCl2 particles.
How many number of moles are present in 3.6gram of water (H2O)?
As we know,Mole = weight in gram / molar massHere, weight = 3.6 gmMolar mass (H2O) = (2*1)+16 = 18By putting the values..Moles = 3.6/18 = 0.2Therefore 0.2 mole are present in 3.6 gms of H20.Hope it will help you..Thanks..:-)
How many chloride ions are in 2.0 moles of CaCl2.Someone please help me.?
What I like to do with stoichiometry is set up a grid, with all the unit conversions on the top and bottom of the grid. That way, things are laid out for easy cancellation. For your problem, the grid will look like this: 2.0 moles CaCl2 | 2 moles Cl- ions | 6.02*10^23 Cl- ions ---------------------+----------------... ...........................| 1 mole CaCl2 | 1 mole Cl- ions The first "region" of the grid has the original amount, the 2.0 moles of CaCl2. The second "region" has the first conversion, moles of CaCl2 to moles of Cl-. We know that there are two Cl's in every CaCl2. The third "region" is moles to molecules. That one's easy. So, notice all the units cancel from the top of one "region" and the bottom of another, except the units we want at the end, number of Cl- ions. Cancelling out all the units, we're left with just numbers: 2.0 | 2 | 6.02*10^23 Cl- ions ----+---+------------------------- ......| 1 | 1 This becomes: 2.0 * 2 * 6.02*10^23 / 1 / 1 = 2.408*10^24 Cl- ions If you can understand this, this makes stoichiometry SO much easier. I still use this well into college.