How many words can you make out of the letters C-D-E-F-G-A-B?
cad,cafe,cage,cab,cabage,deaf,dab, deb,dead,badge,bad, bag, bee,abed,bed,beg,bead, age,ace, ad,add,egg,ed,edd, ebb,ear,fad,fade, fab,fed,feed,fee,face, gad,gab,gag,gage,gee,
How many words can be made out from the letters of the word independence in which the vowels always come together?
There are 12 letters in the word independence with 5 vowels (4e’s & 1 i) and 7 consonants (3 n's, 2 d’s and 1 each of p & c). Now, bunch up all 5 vowels together as one letter so as to assume a word with 8 letters which can be arranged in [math]\frac{8!}{3!2!}=3360[/math] ways. And the bunch of 5 vowels can be arranged among themselves in [math]\frac{5!}{4!}=5[/math] ways. Hence, total arrangements of the letters with vowels always coming together is [math]5*3360=16800[/math]
How many words can you make with the letters:f i s g h t?
fights for one FIGHTS GIFTS SIGHT SHIFT FIGHT THIS FITS **** FISH GIFT FIGS FIST SIFT GIST SIGH HITS HIST HIT FIT IFS FIG SIT ITS TIS HIS TI IT IF IS HI I
In how many ways can the letters in the word "house" be arranged?
5! = 120.
How many arrangements can be made with the letters of the word mathematics?
This is complicated by the repetition of "m" and "a" and "t" which has been overlooked. That accounts for dividing by 2 * 2 * 2 to get the right answer. 4 vowels at the start * 9 letters other than h at the end * 9! for the rest = 4 * 9 * 9! Then divide by 2! for the two t's, 2! for the two a's, and 2! for the two m's Answer is 4 * 9 * 9 * 7! = 1632960
In how many distinct ways can the letters of the word SELLS be arranged?
5x4x3x2x1/2x1x2x1=120/4=30 ways.
How many words can be formed by using all letters of the word ‘daughter’ so that the vowels always come together?
The letters of the word daughter are “ d, a, u, g, h, t, e, r”.so, the vowels are ‘a, u, e’ and the consonants are “d, g, h, t, r”.Now, all the vowels should come together, so consider the bundle of vowels as one letter, then total letters will be 6.so, the number of words formed by these letter will be 6[math]![/math]but, the vowels can be arranged differently in the bundle, resulting in different words, so we have to consider the arrangements of the 3 vowels.so, the arrangements of vowels will be [math]3![/math]Thus, the total number of words formed will be equal to ([math]6! * 3!) = 4320[/math]
How many words can you make using the letters RAGEDG?
AGE ARE DAG EAR EGG ERA ERG GAD GAE GAG GAR GED RAD RAG RED REG AGED AGER DARE DEAR DRAG DREG EGAD GAED GAGE GEAR GRAD RAGE READ AGGER EGGAR GAGED GAGER GRADE RAGED DAGGER RAGGED
In how many ways can the letters of the word 'LEADER' be arranged?
6!/2!=360