What is the mass of 2.5 moles of H2O?
n = m/ MW m = MW * n MW (molecular weight of water) = 18 g/mol m = 18 g/mol * 2.5 mol m = 45 grams
How much iron is there in 1.75 moles of Fe2O3?
SimpleMole =grams /molecular weight1 mole Fe2O3 contain 2 mole FeSo 1.75 mole Fe2O3 contains 3.5 mole FeNow3.5 = grams of iron /56Grams of iron = 196 grams
Chemistry help with the mole?
Plz help i dont understand the mole subject.... 14-What is the mass of 5.13 mol of ammonia vapor (NH3)? Answer in units of g. 15-Calculate the mass of 0.100 mol of calcium nitrate (Ca(NO3)2). Answer in units of g. 16-How many moles are in 3.30 g of (NH4)2SO4? Answer in units of mol. 17-How many grams are in 0.250 moles of C6H12O6? 1. 720 g 2. 90.0 g 3. 45.0 g 4. 180 g 18-How much does 0.250 mole of iron(III) oxide (Fe2O3) weigh? 1. 180.0 g 2. 18.0 g 3. 0.250 g 4. 39.9 g 19-Assume that you take 4.7 mol of CuCl2 and do some chemistry on it such that all of the copper and chlorine are separated. How much copper should you have? Answer in units of g. 20-What is the weight of a single molecule of CO2? Answer in units of g/molec.
Find the mass of 1.112 mol of HF?
you need to find the atomic mass of hydrogen and fluorine. Mass of hydrogen is 1 and of fluorine its 19. So molecular mass is 20 this means that 1 mole would weigh 20 grams. So to find 1.112 moles we do 1.112 x 20 and we get 22.24 grams so the mass is 22.24 grams
How many moles of iron (iii) oxide are formed when 6.2 mol of iron reacts?
Fe + O2 → Fe2O3 (unbalanced equation)4Fe + 3O2 → 2Fe2O3 (balanced equation)Actual moles of Fe2O3 produced = (theoritical moles of Fe x theoreotical moles of Fe2O3 )/(actual moles of Fe used)= (6.2 moles x 2 moles)/(4 moles)= 3.1 moles
What is the equivalent weight of kmno4?
KMnO4 has a Molar mass of 158.04 g/molNow, there are two possibillities:1. KMnO4 as an oxidizer in acidic media:MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant)and to find out the Eq.wt of any element we use the formula, Eq.wt = molar mass/ no. Of electrons lost or gained.therefore, Eq. wt. of KMnO4 = 158.04/5 = 31.61 grams/equivalent2. KMnO4 as an oxidizer in basic media:MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons)Eq. wt. of KMnO4 = 158.04/3 = 52.68 grams/equivalent
How do you determine the mass of one mole of oxygen gas?
Thanks for A2ACalculation of One Mole Of Oxygen Gas Using Avagadro Number1 Avagadro Number=6.022 X 1023 molecules1 mole of oxygen molecules = 32 g of oxygen = 6.022 X 1023 molecules6.022 X 1023 molecules of O2 weight 32 g.1 molecule of O2 weight = 32 / 6.022 X 1023= 5.313 x 10−23(10 power -23) g