How much battery power is required to run a 5hp ac 3-phase motor for 4 hours with 1500 rpm?
As the exact Name plate readings are not MentionedAssumptions for worst case scenario, since the battery has to supply for all cases. 1.You have a Inverter to convert Dc to AcLets say its efficiency is 90%,Reason : I just saw the specifications of some inverters available in market, good inverters are 90%.2.Power factor of the Operating Induction Motor is 0.85Reason :The power factor of induction motors varies with load, typically from around 0.85 or 0.90 at full load to as low as 0.35 at no-load, due to stator and rotor leakage and magnetizing reactance3.The motor full load efficiency is 85% Reason : Full load motor efficiency varies from about 85 % to 97 %, related motor losses being broken down roughly as follows:Friction and windage, 5 % – 15 %Iron or core losses, 15 % – 25 %Stator losses, 25 % – 40 %Rotor losses, 15 % – 25 %Stray load losses, 10 % 20%. 4. Last but Not the least Line to line Voltage 415V and Frequency be 50Hz, Star winded Stator.Lets start the Math Output of Motor is 5hp =5*.746kW=3.73kwMotor efficiency is 85% so the input real power to the motor is 3.73/.85=4.388kwPower battery has to supply is 4.388/.90=4.875KwAmperes battery need to supply is 4875/415= 11.75Ampsas it needs to run the motor for 4 hours its rating would come to 47AhAs the exact parameters of the conversion for the inverter are not known I would recommend you to use 50Ah, 415V battery That would suit your purpose.If a 72V battery is used instead a 275Ah battery would be sufficientAnswer editted as per the convincing comments below..Any suggestions and corrections are welcomed!!
What is the wattage of single phase welding machine?
20 kVA = 20 kW. Volt-amps , 20KVA refers to the maximum amount of power that the machine could normally handle at it's highest settings.If the rated input power is 20kVA or 20kW and the rated out put current is 300 amps, then at 100 amps you are using 1/3 the rated output.Single phase Welding machine specifications:Power supply - 220V +/- 10%Frequency - 50-60 HzPhase - SingleRated Input - 20 KVAAmpere Range - 55-300Rated Welding Current - 300 AMPSref credits: Guide to Stick, MIG, TIG, Oxy, multi-process & engine-driven models
What is the consumption of electricity in 1/2 H.P. motor in one hour?
Energy Consumed is expressed in kiloWatt hour (kWh) or what we commonly call as unitEnergy = Power x Time(for getting Energy in “kiloWatt hour or unit”, make Power in kilo Watts and Time in Hours).So Here,Power = 1/2 H.P or 373 Watts or 0.373 kilo WattsTime = 1 HoursSo Energy (in kWh or Unit) = 0.373 kW x 1 hour = 0.373 kWh or 0.373 UnitNote : 1 H.P = 746 Watts or 0.743 kiloWattPlease support by “UPVOTE”ing if you are satisfied with the answer.
I want to run 1 HP Electric motor using UPS. so i want to buy UPS of what amps & voltage.?
Poor One has got it right. Firstly, small electric motors (assuming single phase AC) are quite inefficient. In your case, I'd assume an efficiency of 50% (being a bit harsh). This means that your 750 Watt motor uses the same "full load" power as about a 1.5kW motor. Also, electric motors will use 4 to 8 times the "full load current" on startup. As Poor One said, this is where the "locked rotor current" is useful. If you don't have this info, you can assume a median value of 6 times the Full Load Current (FLA) just to be on the safe side. UPS's, transformers & generators are rated in VA. To convert kW to VA, ignore Power Factor. Example - a single phase 240 volt motor uses 5 amps at a Power Factor of 0.7. What is the VA of the motor? VA = 240v x 5A VA = 1200VA (Full Load) Startup VA = 1200VA x 6 Startup VA = 7200VA Startup current = startup VA divided by 240 Startup current = 7200 divided by 240 Startup current = 30 amps. Unless you provide more information, an exact answer cannot be given.
How many watts does a 2 HP motors have?
2HP = 1492 watts! To provide for starting current rule of thumb is to quadruple full load Amps shown on nameplate. Whilst 2HP = 1492 Watts the actual power drawn will be greater due to losses within the motor and can be roughly calculated by multiplying Amps by Volts also as shown on the nameplate.
How many units of electricity will be consumed if we run a 1 HP, 1-phase motor for 24 hours?
Unit of electrical power is kWh (in SI system). This is actually 1000 Watt-hour. That means if a 1000 Watt equipment runs for an hour it will consume 1 unit of electricity.Now, 1HP (Foot-Pound-Second unit system) is equivalent to 746W. It is independent of number of phase of the motor. If the motor is run for 24 hours then total kilo watt-hour is -> 746*24/1000= 17.9 kWhThus total electrical power consumption is 17.9 unit for 24 hours.The above is true considering that the motor has run in full load for the entire duration of 24 hours. For overload and under-load it will consume more and less power respectively. Thanks for asking.
How many units of electricity will be consumed if we run a 3 HP, 3-phase motors for 24 hours?
1 HP = 746 watts3HP= 3*746watts = 2238 watts1 unit = 1 kWh= 1000 WhSo, if 3 HP runs one hour it consume2238/1000= 2.238 unitsSo, in 24 hour = 24*2.238 = 53.72 units in 24 hr.
How many volts are needed to a 1 HP water pump?
First, let me adjust your question. Horsepower is a unit of power. The electrical unit of power is a watt. So to ask how many “volts” are needed is a nonsensical question.Watts = Volts x Amps1 Horsepower = 745.699872 WattsTherefore,If Voltage = 120 volts, thenCurrent (amps) = 745.699872 / 120 = 6.214 ampsIf Voltage = 240 volts, thenCurrent (amps) = 745.699872 / 240 = 3.107 ampsTypically, a motor is designed to operate at a specific voltage. You would design your circuit based on the available voltage. If the voltage is 120, then you would need a breaker that is greater than 6.214 amps. Normally a 120 volt circuit in a house will use 12 gauge copper wire which can carry 20 amps safely, or 14 gauge wire which can carry 15 amps safely.Hopefully, this has answered your question.