How will the kinetic energy change if the momentum of a particle is doubled?
Kinetic Energy(E) = 1/2mv^2 ——(1)Momentum(P) = m*v ————(2)From equation 11/2 * m * v *v1/2 * p*vSo, E = 1/2pv.This is the relation that is been induced from these two equations.
How the potential and kinetic energies vary with twice the frequency of displacement and velocity?
Think of a simple pendulum as an example. In ONE full cycle there a TWO times the potential and kinetic energies are at maximum. Max KE occurs as the pendulum passes through the central position (at max sped). This happens TWICE per cycle - when the pendulum is moving left and when it is moving right. Max PE occurs as the pendulum reaches the highest points. This happens TWICE per cycle - when the pendulum is at the left side and when it is at the right side. Look at the link - the red line is the displacement graph.
Simple harmonic motion spring question... finding the period of oscillation!?
This one's a 2-parter... however, I did get the first part. A spring is suspended from a ceiling. When a 1.19kg mass is hung from its lower end, it stretches by 10.3 cm. (a) what is the spring constant? -- 113N/m (b) the mass is now displaced by an additional 4.9 cm and is released from rest. Find the ensuing period of oscillation. I tried finding a new spring constant (which incorporates the 4.9cm), then plugging it into T = 2*pi*(m/k)^1/2, but that doesn't give me the right answer... how do you approach this question? Thanks!