How To Divide 0.1 By 5.2

How are square roots of decimals calculated?

Suppose you have to find square root for 27The nearest perfect square is 25 whose square root is 5Keep 5 aside and now work on the remainder which is 2Divide the remainder by the perfect square root.Divide 2 by 5 (2/5=0.4) and add 5 which is equal to 5.4Now ( 5 + 5.4 ) / 2 = 5.2 which is your answer .Hence , square root of 29 = 5.2 (approx)

What is the molarity of a solution in which 5.0 g of sodium carbonate (Na2CO3) are dissolved in 200. mL of solution?

First you need to know the molecular weight of Na2CO3. It is 106 g/mol. Now, calculate the number of moles is represented by 5 g. This is 5 g/106 g/mol or 0.0472 mol. Now divide by the number of liters to get the concentration or 0.0472 mol/0.2 L = 0.236 mol/L or 0.236 M.

Is 0.5 odd or even?

No, not even if we generalized oddness-and-evenness to real (or at least rational) numbers, say following the technique described by Gabriel EhrlichA big question for oddness/eveness/parity is how these sorts of numbers interact with each other, so the question is how they multiply and add. If we think of even and odd numbers* as defined by following the behavioreven+even = evenodd+odd = eveneven+odd = oddeven*odd = evenodd*odd = oddeven*even = even.with addition and multiplication working as in traditional real-number arithmetic, we'll see that 0.5 runs into issues. For the sake of mathematical completeness,  we'll assume that there has to be at least one even and one odd number in our abstract definition.0.5+0.5 = 1, which is odd.* So if 0.5 was either odd or even, it would break the defining rules above since its sum with itself is odd. Thus, it will be neither.*Even and odd functions, meanwhile, follow a completely different set of rules.**Is it? 1 could be even, odd, or neither. If we define 1 to be even then ALL numbers that can be classified as even or odd must also be even, since 1*x = x (and even*odd = even). So, as there exists at least one odd element, 1 cannot be even***. 1 follows the multiplicative rules for odd numbers, (it doesn't change the parity), and how about for addition?(odd+1)*odd = odd*odd+odd = odd+odd=even -> odd+1 is even.(even+1)*odd = even*odd+odd = even+odd=odd -> even+1 is odd.So 1 acts like an odd number in addition, changing even numbers to odd numbers***Unless all odd numbers are also even, in which case it doesn't really make much sense to have a definition like this.

How many volts are equal to 1 ampere?

Volts to amps calculation with wattsThe current I in amps (A) is equal to the power P in watts (W) , divided by the voltage V in volts (V):I(Amps) = P(Watts) / V(V)oramps = watt / voltwe need to find out the current flow of an electrical circuit that has power consumption of 45 watts and voltage supply of 15 volts?I = 45W / 15V = 3AVolts to amps calculation with ohmsThe current I in amps (A) is equal to the voltage V in volts (V) divided by the resistance R in ohms (Ω):I(Amps) = V(Volts) / R(Ω)oramps = volt / ohmswe need to find out the current flow of an electrical circuit that has voltage supply of 30 volts and resistance of 10Ω?I = 30V / 10Ω = 3AFor complete understanding of Volts to amps calculation visit hereHow to convert Volts to amps

How do you prepare 0.1N KMnO4 in 1 litre?

N (normality) describes a solution that contains 1 gram equivalent weight (gEW) per litre solution. An equivalent weight is equal to the molecular weight divided by the valence (here it gets a little tricky, for acids ands bases it refers to the number of H+ or OH-, in salts it must be expressed which ion is meant unless the ratio is 1:1). In the case of KMnO4, equivalent wt is reaction specific. When KMnO4 is used in acid medium as oxidiser, 5 electrons are gained by Mn atom. So equivalent wt of KMnO4 in acid medium = Molecular wt/no.of electrons gained in redox reaction = 158/5 =31.6.  So for 0.1N KMnO4 solution, you have to dissolve 3.16g KMnO4 in 1L water. (Usually a little bit excess is taken, say 3.25g, since some crystals of KMnO4 will be remained undissolved that have to be removed by filtration. So even though u r preparing 0.1N KMnO4 solution by accurate weighing, it is not a primary standard and u have to standardise it against a primary std such as oxalic acid or sodium oxalate.In alkaline or neutral medium, reaction of KMnO4 is different and Mn gains 3 electrons in redox reaction. So, for alkaline medium redox titrations, equivalent wt of KMnO4 will be 158/3 = 52.6.  So for 0.1N KMnO4 solution in alkaline medium redox titration, dissolve 5.26g in 1L water.

How is [math]10/0.1[/math] equal to [math]100[/math]?

Consider this example,Say you have 10 chocolates, and a lot of people in line waiting to receive the chocolate.One chocolate can be divided in a maximum of 10 pieces.To how many people you would be able to give a piece of chocolate, assuming there's no wastage etc.?Your answer should be such, 10 pieces per chocolate, so 10 people per chocolate and there are a total of 10 chocolates so you can serve maximum of 10+10+10+10+10+10+10+10+10+10 people that is 100 people.Seeing such cases it can be established that if you have 10 no. of any quantity and you would like to distribute one tenth of that thing to people so can serve 100 people.Thus, it can be said that 10/.1=100 in most cases.

How many molecules are in 5.5 grams of CO2?

To know how many molecules are in a weight of a substance, you need to find out how many moles are in the substance.To get moles, you divide grams of a substance by molecular weight. The molecular weight of CO2 is 44.0095 g/mol. 5.5g divided by 44.0095g/mol is 0.12497 moles.You then need to multiply moles by Avogadro’s constant (6.022x10^23). That gives you 7.526x10^22 molecules in 5.5 grams of CO2.