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I Might Have A Tough Math Question. Someone Good In Math Can You Help

Math is hard i need help on one question?

59.85-(59.85*.15)=50.87
50.87-(50.87*.25)=38.15 which is final price

Need help with difficult Math Question?

I'm beating my head against the wall trying to figure this math problem out, maybe I'm trying to hard, any help or guidance would be greatly appreciated.

It is Better to Give Than Receive

One spring day as fowers were blooming on the ground of Grandfather Pennywise's large mansion, he called to all his grandchildren to gather round his easy chair in his den. Excitement was in the air, because they knew what was coming. The tradition was about to be enacted for another year. Dear old "rich" Grandfather "Moneybags" (as the children called him) always gave money to them on HIS birthday.

And he always did so in an unusual and unique way. (some adults called it eccentric). You see, he gave to each of his grandsons as many dollars as there were grandsons, and to each of his granddaughters as many dollars as there were granddaughters.

Now years ago when there were fewer offspring, the monetary value of each gift was rather low. But as years have brought more children, the amount each child receives has likewise grown. And much to the delight of each child, I might add.

This year the girls were especially happy due to the birth of twin girls just a month earlier. They would receive more per person than the boys for the first time in quite some spell.

After all the envelopes containing each child's portion were handed out, Linda exclaimed, "Grandpa, you've just given out $841 this year! Thank You."

Of course, every grandchild (except the newborns) rushed to grandfather to give him a hug and wish him a Happy Birthday.

How many hugs did the kind gentleman receive?

Hi all, can you help me with some difficult maths questions?

Hi, I have a few. I'm having a lot of trouble with them. Any help is greatly appreciated. May you please include working out so I can better understand the question, it's driving me nuts!!

A shopkeeper buys a crate of eggs at $1.50 per dozen. He buys another crate, containing 3 dozen more than the first crate, at $2.00 per dozen. He sells them all for $2.50 a dozen and makes $15 profit. How many dozens were there in each of the crates?

Jess walked for 45 minutes at 3 km/h and then ran for half an hour at x km/h. At the end of that time she was 6 km from the starting point. Find the value of x.

A shopkeeper sold his entire stock of shirts and ties in a sale for $10 000. The shirts were priced at 3 for $100 and the ties $20 each. If he had sold only half the shirts and two-thirds of the ties we would have received $6000. How many of each did he sell in the sale?

Thank you so much in advance! I've spent hours on these!

I got a tough math question here?

150

If we first ignore that each color be used once, there are 3^5 ways to paint the train.
Then, subtract 2^5 ways that the train could be painted with only red or blue, subtract 2^5 with only blue or yellow and subtract 2^5 ways with only red and yellow then add 3 back because we subtracted all blue , all red and all yellow twice each.
=243 - 3*2^5 + 3
=243 - 96 + 3
=150

Hey can someone help me with this math riddle? It's a hard problem for me. puzzle?

Aha... I think i have a clever way to solve this. First, the answer:

1 2 4 8 16 32 2816

Now, on how to solve it:

The first thing to note is that every child must have a multiple of the first child. So, the number of pennies the first child has must be a multiple of 2879. In other words, if the first child has x, the second child has ax, the third has bx, etc. -- 2879 has to be a factor of x. But, 2879 is a prime number. Therefore, the only possible value of x is 1. The first child has one penny.

Take that penny out of the pile, leaving 2878. Using similar logic, the number of pennies the second child has must be a multiple of 2878. 2878 = 2 * 1439, and 1439 is a prime number. Giving 1439 to the second child would cut the pile in half - not enough to keep going. Therefore, since the second child must have a different number of pennies from the first child, the only possible value for the second child is 2. The second child has two pennies.

Take two more pennies out of the pile, leaving 2876, and keep going... the number of pennies the third child has must be a multiple of 2876. 2876 = 4 * 719. 719 is a prime number. Therefore, the only possible value for the third child is 4. The third child has four pennies.

Take four more pennies out of the pile, leaving 2872. The number of pennies the fourth child has must be a multiple of 2872. 2872 = 8 * 359. 359 is a prime number. Therefore, the only possible value for the fourth child is 8. The fourth child has eight pennies.

Take eight pennies out of the pile, leaving 2864. The number of pennies the fifth child has must be a multiple of 2864. 2864 = 16 * 179. 179 is a prime number. Therefore, the only possible value for the fifth child is 16. The fifth child has 16 pennies.

Take 16 pennies out of the pile, leaving 2848. Now factor 2848 = 32 * 89. Yep, 89 is once again a prime number. (Whoever created this problem must've worked really hard to find a number that worked.) The last two children must both have a multiple of 32, leaving only one possibility: the sixth child has 32 pennies and the last child has the rest of them.

Cute problem!

Hard Math Question. Can you figure out the answer?

Besides what smci has explained:
N = N^2
1 = 1
2 = 4
3 = 9
4 = 16
5 = 25
6 = 36
7 = 49
8 = 64
9 = 81

1) Possible answer can not have 5 with any of the even digits

2) If the number have all digits >=4 then multiplication of squares will result in a number greater than the original number (e.g. 44 < 16*16 = 256), so the possible answer has to have "balanced combination" of numbers {1,2,3} with {4,5,6,7,8,9}

BTW I tried to find such numbers using program but No such number exists within 10^7,

However I have noticed that there are numbers with following property
a^2 x b^2 x c^2 = abc + 1
(They are also rare!!!)

One of them as you have already mentioned is 143
Others are 323,11663

On analysis of above numbers my eyes remained wide open!!!

Just Imagine, these numbers are product of two TWIN PRIMES (with difference 2)!!!!
143 = 11 * 13
323 = 17 * 19
11663 = 107 * 109


Now I am searching for both type of numbers

Addendum:
I have finished searching till 1382529243, I have searched for both types of numbers, with no success, so largest twin composite number which I have found for other type is 11663

Expected Value Math Question?

I'm having a tough time with this, if someone could help I would be greatful:

In a game, you have 1/41 probability of winning $87 and 40/41 probability of losing $9. What is your expected value?

Thanks :)

If I know how to answer really hard math questions does that mean I will become a good software engineer?

Mathematicians do work as software engineers and they write special algorithms for improving older applications software written in languages like Fortran on newer hardware utilising the multi-processing abilities of the newer chipsets. My son has a PhD in Mathematics (from Warwick University in UK) and worked at the Austin Teas TACC university for about 6 years on supercomputing performance and tuning of Big Data for things like weather systems or space data analysis. He know works for AMD in Austin - so a good maths degree really gives you a LOT of opportunities in the employment market.

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