I need a lot of help!!!?
F = 5 Q = 1 N = 9 X = 6 T = 2 Z = 0 H = 3 S = 7 U = 4 E = 8 7029 *519 -------- 63261 7029 35145 ---------- 3648051
I need a lot of help in math ?
The width of a rectangle is 33 centimeters. The perimeter is at least 776 centimeters. a.) Write and solve an inequality to fing the length of the rectangle. b.) Write an inequality to find the area of the rectangle. Please&&Thankyou
Why do I need help?
You don’t need help. You have a problem with expectation. You are expecting a lot of help. Stop, expecting and try to do things on your own. Feel the difference!
Makeover HELP I NEED a lot of HELP?
Hey Girl, One thing that stands out right off the bat is you need to have healthy goals. According to your goals, you want to lose 50lbs this summer. Even if you needed to lose that much weight, trying to lose it in a short amount of time could lead to some SERIOUS health problems for you. First of all, if you look at your Body Mass Index (BMI) at http://www.revolutionhealth.com/calculators/body-mass-index-bmi you'll see that right now you are in the mid-range for a healthy body in your height category. If you lose the 50 lbs you say you want to, that will put you in the underweight category and according to them that BMI is below the range for optimal health. You may be at risk for vitamin deficiencies, thinning bones and infections. Do you really want to look like Nicole Ritchie, the Olsen twins and all those other anorexic celebrities? If you want to get rid of your 'baby fat' (I suspect that is all that it is), all you have to do is enjoy this summer by being active, playing sports, going for walks and/or swims and cutting out some of the junk food. You'll have fun, get a tan, slim-up, feel great and worry less about what others think. And regarding buying a new wardrobe, try looking around in second-hand/funky stores that you wouldn't normally shop in. You might get some great ideas or pick up an accessory that makes your outfits more 'you' and make you stand out in a crowd as someone who isn't afraid to have fun with their fashion sense. Good luck!
Solve please! I need a lot of help PLEASE?
2m-2=6m-4 2m=6m-4+2 2m=6m-2 6m-2=2m 6m-2m-2=0 4m-2=0 4m=2 divide by 2 2m=1 divide by 2 m=1/2 I think its elaborate enough lol :) All the best Hope this helps
I am going through a lot of stress and need some help. What should I do?
Not sure what MNC means so I’ll respond (since I was asked to).Continue working in IT and go back to school to get your degree in Accounting/Auditing. Whatever schools you apply to will tell you what courses you need to get the Acctg/Auditing degree.Then start looking at jobs in Acctg/Auditing.Don’t just leave one job to go back to school as you already have a career. Since you want to work in Accounting, ask the IT place where you work now to allow you to transfer to the accounting dept AFTER you get your degree (or at least have taken some core courses.) If you don’t want to wait that long, ask them to transfer you, but expect a pay cut since you aren’t “degree’d” in Accounting yet.
I need a lot of help with this math equation?
Many years ago on the island of Banio, the people considered 2 hammers worth 3 knives and a needle. They would trade 25 pineapples for 3 hammers, 2 needles, and 1 knife. 3 needles were worth 2 hammers and one knife. How many pinapples would they trade for one hammer? one kife? one needle? i do not understand this at all. :D
Which is correct, "need a help" or "need help"?
Use "need help" (no "a"). If you need a helper (a person to help you), then "a help" is a little more unusual and might be workable but only in speech (since the listener can confirm with you).
I Need A Lot of Chemistry Help Here?!?
Calculate the ph of a solution contaiing 0.118 M acetic acid (Ka=1.76 x 10^-4) and 0.172 sodium acetate? 4.077 5.432 8.568 8.7370 Calculate the ph of a solution prepared by dissolving 0.37 moles of formic acid (HCO2H) and 0.23 moles of sodium formate (NaCo2H) in 1.00 L of solution? Ka= 1.x10^-4 2.09 10.46 3.54 3.20 Calculate the concentration of iodide ions in a saturated solution of lead iodide (Ksp = 1.39 x 10^-8) 4.21 x 10 ^-4 3.03 x 10 ^ -3 3.48 x 10 ^-9 The solubility of ZX3 in water at 298 K is 4.0 x 10^ -4 M Ksp fpr ZX3 is