# I Need Your Input For A Statistics Survey

How to input survey responses into SPSS?

I have 2 surveys looking to see if there is a relationship between offender remorse and custodial sentence length. 1 survey is being answered after reading a vignette where the offender is remorseful, and the 2nd survey is answered after reading a vignette where the offender isn't. This is between subjects design.
Each survey has 15 questions.
How do I input this data into SPSS? I'm very stuck and need help ASAP.
Thanks

I need statistic data for spss assignment?

Use survey_sample.sav from sample folder in the SPSS installation

Bye

Statistics Problem?

I'm currently taking a statistics class that is making me feel beyond stupid. I've taken calculus with no problem, but statistics is making my brain melt. Any help would be appreciated.

"In the 2011 Current Population Survery conducted by the U.S. Census Bureau, two average household incomes were reported: \$49,445 and \$67,530. One of these averages is the mean and the other is the median. Which is the mean? Support your data."

The way I see it is that there's no way to come to an answer with the information provided. There's no range given, just two averages that represent the same data. Any input would be great. Thanks in advance.

What is a great way to make an online survey, run statistics on the input, and present the analyzed data on a web page in real-time?

How should I go about a survey data analysis?

What do you mean by few inputs from the survey taker! do you mean the respondents? if yes, are the responses or most of the responses open or close ended? Are they likert-scale type questions (how many? if applicable), are we looking at a set of nominal data responses? quantitative inputs by respondents based on responses?.Anyway, first step requires that you enter the data responses in excel. Arrange data in column please (see below snapshot), IF CLOSED-ENDED.Call up the recommended software of analysis, export the data to the application environment and run. Note here, that your objectives ought to have been clearly articulated (SMART) in line with the pre-analysis guide (methodology) and so i suppose you already what you are testing and the test procedure that fits the data and study objectives since these are all constituents of a well thought out methodology. After obtaining specific estimates, run the analysis, interpret ‘make sense out of the data”; this is what i call extracting the juice…Kingsley Ukwuoma (@kingsleyredfox) • Instagram photos and videosRegards,

AP Statistics Question HELP?

For the confidence interval for the difference between two proportions you can input your data here:

For the significance test, use this calculator:

http://www.wessa.net/rwasp_hypothesispro...

I can tellyou by eyeballing the first question that there is not a significant difference from 50% for the Americans. With that sample size and a proportion close to fifty, you have a margin of error of 3 or so percentage points.

Your textbook should have an explanation of what the calculators are doing for you. Stattrek.com is also a good source for tutorials.

The procedure is pretty straightforward. There is only one little quirk: When you are calculating the standard deviation of the sample proportion, with a hypothesis test you use the population values of p and (1-p) found in the null hypothesis, because you conduct the test assuming it holds. Inthis case, 50/50.

For a confidence interval, you use the sample proportions and their complements, because there is no null hypothesis.

Statistics Quick Question Help!?

John

You need to solve two linear equations with two unknowns (mean and standard deviation) ...

Using the Standard Normal table ...

If P(X < 1) = 0.25, then the z-value is -0.6745
If P(X > 2) = 0.05, then the z-value is 1.645

Let μ equal the mean and σ be the standard deviation unknowns. Here are the two equations to solve ...

(1 - μ ) / σ = -0.6745

(2 - μ ) / σ = 1.645

Using either substitution or elimination method to solve two systems of linear equations ...

μ = 1.2908
σ = 0.43113

Finally, the z-value associated with P(Z < z*) = 0.60 is z* = 0.2533

Answer = 1.2908 + (0.2533)(0.43113) = 1.4 hours

hope that helps

I have to conduct an offline survey with a population of about 1000 residents who are not primarily online, and then input the data in an online format that allows for analysis, charts, and narrative.  Any suggestions?

Enalyzer’s reporting tool can provide you with the tools you need to really dig into your data. Btw, I work there.Without knowing what your survey is about, I would like to point out some reporting features that apply to any type of research:Benchmark is a great way to compare and contrast your data. This is done with data series, which is a grouping of data based on one, or more, filters. This allows you to benchmark anything!Filtering. With the right background variables, you can really drill into your reports. For example, if you have to separate people through regions or demographics.Pareto principle in charts. Also known as the the 80/20 rule, is a principle that states that 80% of the effects come from 20% of the causes, e.g. 80% of sales comes from 20% of customers. With Enalyzer, you can apply the Pareto principle to a bar chart and the result will be values plotted in decreasing order of occurrence, organized from left to right. As a result, the chart clearly illustrates which factors have the greatest impact and what problems need the most attention, making them extremely useful in a variety of situations.BONUS - if you’re going to conduct this survey throughout time, then time series are a great asset!Time series charts allow you to track variables over time and give you an insight into patterns within your data.Plus, the reports are very appealing to the eye and can be shared online and downloaded to PDF, Excel and PowerPoint!Create an account and try it out: Home | Enalyzer

1 ) A large corporation knows that the proportion of their employees that have children is 0.76. The director of human resources is going to take a random sample of 102 employees. What is the standard error of the proportion in this situation?

2) 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were pursuing liberal arts degrees. The sample proportion is 0.413.
What is the margin of error for a 95% confidence interval for this sample?
What is the lower endpoint for the 95% confidence interval?

3) In a certain city, there are 1 million homes. As part of an environmental status survey, it was desired to estimate the proportion of homes in this city which contain lead based paints. A simple random sample of 150 households revealed that 49 homes had lead based paints in at least one room. What is the sample proportion?

Thanks so much! I appreciate it! :)

What is the method of the least squares in statistics?

It's about estimating parameters of a mathematical/statistical model. Gauss prooved that minimizing the sum of squared deviations from actual values leads to the best model fit. If you try to model a process you have to estimate its parameters. You may have a formula to predict an outcome based on some inputs. In statistics, all inputs are called features or input variables (a statistician wants them to be independent) and the outcome is called dependent variable or target. And there are parameters in the body of formula. For example, a linear regression model in of a form Y = BX +A, where X represent independent input variables, and A and B are model's parameters which we try to guess given set of observations. The Least Squares Method can be used to do that.