A light of wavelenght 6000 A in air, enters a medium of refractive index 1.5. What will be the frequency and wavelenght of light in the medium?
c = Speed of light in air → 3 X 10^8 m/sW → Wavelengthn → Refractive index of the medium = 1.5W in air = 6000 A = 6 X 10^-7 metresλ → Frequency in air = c / W in air = 5 X 10^14 Hzn = W in air / W in the medium1.5 = 6000 / W in the mediumW in the medium = 4000 AMagnitude of frequency depends upon the light producing source hence it remains constant throughout ( 5 X 10^14 Hz) .