If You Were To Cross Two Lasers That Were Different Colors Is It Possible To Create Different

In general, when light beams have low intensity, they do not interact. This is the region of linear optics. When light is of higher intensity, in the right medium (e.g., in special crystals such as Lithium Niobate) and under specific conditions, beams intact nonlinearly and can create light of wavelength/frequency that was not there before the interaction. For example, second harmonic generation is a nonlinear optical effect where 2 photons of one wavelength (say Red at 800 nm) are converted into a single photon at half the wavelength or twice the frequency (Blue at 400 nm). So two beams of different colors at the right intensity intersect inside a nonlinear optical medium (and the right conditions), they can create a new beam that is, for example, at the sum of the original frequencies (remember that the frequency is related to the color). If the beams are at low intensity or intersect in vacuum (or in a medium that has no or very weak nonlinearity), they just go through each other and do not affect each other at all.

A species of animal, as defined by my university professor, is any creature that can breed with other members and produce viable offspring via genetic exchange. This means that dogs are all one species, as it’s genetically possible for any two breeds to mate and produce a fertile puppy, while a cat and dog are not likely to cross breed.One species becomes two when the genetic difference between them means that the members cannot breed and produce viable offspring. Dolphins and giraffes are probably too genetically distinct to make a baby. While lions and tigers can create a liger, the liger is sterile. Same goes for donkeys, horses, and mules. The genetic difference between the parent animals is too great to create a fertile offspring, if any at all.What’s fun is that “ring species” exist, where the members of a species have subtle genetic mutations that nearby members can mate with each other to produce viable offspring, but the two at the end cannot. For example:A, B, C, and D are all birds of a ring species.A can mate with B to create AB, which is fertile.B can mate with C to create BC, which is fertile.C can mate with D to create CD, which is fertile.D however, cannot create offspring at all by mating with A. Note that if D and A were to spawn a child, but it is infertile, it would still be considered a ring species.The reason for the name “ring species” is because the most common physical distribution of these kinds of species are, well, a ring!

The brightness and visibility of the scattered light is proportional to the product of how much light shine on the air particles and how the air particles respond to the light.Assume the particles arent saturated, the more light we shine on the particles the brighter the scattered light is.So in general, the answer is yes.

Scientists “collide” lasers commonly in the lab. If you have two laser pointers, you can do it yourself at home. The major advantage that scientists in labs have over you at home is that they typically use an “optical bench” — a heavy, vibration-isolated bench to which optical devices (precision mirrors, lenses, etc) can be placed and carefully aligned.What happens depends mainly on the power of the lasers (mainly in terms of color; how “blue” are they), and if there is anything at the point of collision.If there is nothing at the point of collision, then the two lasers merely pass through each other, without interacting. If the lasers are both extremely blue (as in you are working with gamma-ray lasers), then there’s a chance that they could interact to create electron-positron pairs, which will recombine to form gamma-rays, and thus effectively scatter the laser beams. This is at a much higher energy level than most people or scientists will ever run across.If there is something at the point of collision, each laser will push on it or otherwise try to scatter it. Some scientists use this to take sets of 6 lasers colliding from 6 different directions at one point to make a “trap” for groups of atoms. By adjusting the strength of the lasers, they can slow the atoms, move them from one place to another, etc, all very carefully. Since at an atomic level temperature is related to how fast atoms or molecules are moving, this technique, or a closely related one, is also known as “laser cooling”.

For the most part, nothing. Theres an area of study called Two-photon physics that looks at ways that photons can interact, but, I’ll leave it to the far more thorough Wikipedia article to leave it at ‘only in higher-order’ interactions in things like gamma rays.That is, however, only what the laser beams (groups of photons with more or less the same wavelength and phase) do to each other.If you throw in the lasers interacting with other parts of the universe, then you can, for instance, use crossing laser beams to make an ion trap for Laser cooling, where the energy/momentum transfer between atoms and the laser photons will lead to some atoms coming to near zero motion in the beam intersection, generating nano-kelvin temperatures on small scales.

Other answers have pointed out that in materials it is very possible to have two invisible beams of light become a single point of visible light where they intersect.  Some of the other answers claim that it is impossible to do this in free space.  They are mostly correct, but there is one way that you could have a very very dim light in free space when two intense beams of light cross.This is possible because beams of laser light are indeed invisible in free space when they are not directed at your eye.  However if two beams cross at a point, there is a very small probability that photons from one beam could collide with photons from the other beam and scatter towards your eye and become visible.  The Feynman diagram for the only allowed "collisional" interaction of two visible light photons is this:It turns out that this diagram predicts a very small probability for two visible light photons to collide in this way.  I don't know the exact probability but for all practical purposes, ordinary visible laser light photons do not collide and just pass right past each other.  So if you take two laser beams and shine them at each other they will mostly just pass by each other - it would only be a very rare pair of photons that would scatter out of their respective beam directions and towards your eye.  However if you managed to create EXTREMELY intense beams of visible light photons, then there might be enough photons that do collide to create a very very dim light where they cross.  So it is certainly not easy to do and would not be worth doing because the dot would be very very dim.

No.This takes a bit to explain why.First: The mirrors have to be perfectly parallel to each other. Perfectly. If they aren’t, even the smallest error will cause the laser to drift to the edge of the mirror, assuming the beam hasn’t scattered to much to see this effect. As such, it is impossible to know for certain that your mirrors are perfectly aligned.Second: The laser emitter needs to be perfectly perpendicular to both of the mirrors. As such, you can’t know for certain if it’s properly aligned.Third: The emitter gets in the way. This is supposed to be taking place in the real world, and laser emitters have opaque components. So the laser bounces of the mirror and hits itself, blocking the light from continuing to the next mirror.Fourth: Lasers scatter. They don’t do it as quickly as other light sources because the emitter concentrates the photons more tightly, making a beam. But the whole reason you see this beam in the first is because the light is scattering as soon as it leaves the emitter. So, eventually, the laser would scatter enough that it wouldn’t look or function like a laser anymore.Those are all the reasons I can think of right now, but they make this project impossible. :(EDIT: I urge all viewers to take this with a grain of salt. It’s a hypothetical situation in a field that, I’ll be honest, I’m not the most knowledgable person in. I’ve just seen questions similar to this and stuff.However, thanks for all the feedback! I urge everyone to read the comments!