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Jimmy Drives 6 Miles On The East Highway And 9 Miles On The West Highway To Get To His Friends

Homework Question: Joe walked 4 miles north, 9 miles east, 8 miles north, and then 7 miles east. If Joe now decides to walk straight back to where he started, how far must he walk?

The answer provided by User-9597828242429937573 is great, but there are couple of omissions that make its precision unacceptable for practical purposes:1. Our planet is not spherical: its height is less than width due to its rotation. We should take it into account;2. Joe is not a point, but rather a material object. We have to make calculations probably for his geometrical center or, maybe, his center of mass. It should be discussed and decided. If agreed upon geometrical center, 1/2 of Joe's height should be added to the radius;3. Since the journey is long, the result depends on the time he starts and his speed - because of thermal expansion of the Earth's surface heated by the Sun. If Joe is walking while the surface is expanding, his trip back may be longer if the temperature is still high;4. Of course, we should consider the Earth deformation due to the Moon's gravity;5. The answer has to be expressed in closest integer number of Plank lengths. Otherwise, it would be absolutely unrealistic.Other than that, it is pretty accurate and will probably satisfy Joe. :)

How many remember the 'Dog N Suds' Root Beer Drive Inn Stand?

I grew up in Southern Indiana, where a few Dog N Suds Stands were when I grew up. I believe A & W was more popular, but we had DNS in our hometown, which I liked better. DNS was famous for their 'coney dog sauce,' not to be mistaken for chili dog sauce. Crisp and golden Tater Tots were another side and of course the delicious root beer filled chilled mugs. When you pulled into the Drive Inn stand, you either left your headlights on, or honked the horn, to alert the carhops you were ready to order. Your order was written down on pad as opposed to ordering on a speaker as today's 'Sonic' does. The jukebox playing music inside was relayed on speakers outside for all to hear while they you enjoyed your meal or hung out watching all the guys drive their hot, cars around the stand. I am wondering as far as geographical area where the Dog N Suds Drive Inn stands were located, I wonder if they may have been regional. Do you ever remember a Dog N Suds stand anywhere or had one in your own hometown? What was the name of the most popular teen hangout when you grew up, and what foods were their biggest specialty?

A car travels from A to B at the rate of 40 miles per hour, and then returns from B to A at the rate of 60 miles per hour. Is the average rate for the round trip more or less than 50 miles per hour? Why?

it 'll be 48 mph.let, the distance of A to B be 1mile.so,first the time=1/40hr.on return,it'll be 1/60hrso, in all for 2 mile the time=1/40+1/60hr.so, avg=2/(1/40+1/60)=48.

A person goes 10 km north and 20 km east. What will be their displacement from the initial point?

Using the triangular law of vector addition.The displacement line is given by the hypotenuse which joins the start point and the end point.Hence hypotenuse is sqrt(N^2+E^2)=Sqrt(10^2+20^2) = 22.36 kmDirection of the displacement vector is given by atan(opposite/adjacent) = atan(10/20) = 26.56 degrees with respect to east measured anticlockwise.P.S: please avoid asking such silly questions. Let's make Quora a knowledge sharing platform (knowledge which matters and not thought in school)

How can I find average speed if a boy walks to his school at a distance of 6 km with a speed of 2.5 km/h and walks back with a constant speed 5km/hr?

This question is very simple.Average speed = Total Distance / Total Time TakenWe have given speeds S1 and S2S1 = 2.5 km/hrS2 = 5 km/hrAnd Distance D1 and D2D1 = 6 kmD2 = 6 kmTotal Distance = D1 + D2 = 6 + 6 = 12 kmNowT1 = D1/S1T1 = 6/2.5 = 2.4 hrT2 = D2/S2T2 = 6/5 = 1.2 hrTotal Time = T1 + T2 = 2.4 + 1.2 = 3.6 hrNowAverage Speed = Total Distance / Total Time = 12 / 3.6Average Speed = 3.33 km/hr

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