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Malaysian Flight 17 Was A Setup

If I say "Malaysia," what is the first thing that comes into your mind?

HomeI’ve lived here most of my life. If I was asked which country I would live in besides Malaysia, I cannot imagine any other country.Race. Everything is in a variety. Culture, food, clothes, language, celebrations and many more. You would think that we are racist but racism isn’t often as you think. Obviously they would be and it cannot be help. But overall, we live peacefully. *Usually the person who says that racism is a thing is a person who doesnt have multi race in their country or based their opinion on medias.2. Cost of living. When I went to UK, I felt like dying. Everything was expensive. The number of the price may be the same in Malaysia but the value is different. If you get me. Malaysia is a pretty cheap place to live at3. Weather. I do not have to care if winter is near. I can wear pretty clothrs thru out the year.4. Islam. Living as a muslim is easy here. Education is easy. Finding halal food is easy and not worrisome. Finding a place to pray is very easy… In other countries, I have to walk far to find a mosque. Food are mostly non halal so I have to be a temporary vegetarian. And to seek knowledge of Islam is toughThere is many but I couldn’t think much now.

A marksman aims a rifle directly at a target that is 185 m away and on the same level as his rifle.?

The two general equations of motion required are v = u + gt and s = ut + (1/2)gt^2.

The vertical component of motion is u*sin(θ).
The horizontal component is u*cos(θ).

The vertical equations are then :
v = u*sin(θ) + gt
s = u*sin(θ)*t + (1/2)gt^2

And the horizontal equations are :
v = u*cos(θ) + gt
s = u*cos(θ)*t + (1/2)gt^2

I haven't made it easy with my use of variables, but keep in mind
that v and s vertically, are different things from v and s horizontally.

Now, firing horizontally means that θ = 0º.
So we have, sin(0º) = 0 and cos(0º) = 1.

Plugging these into the equations gives these simpler forms :

Vertical equations :
v = gt
s = (1/2)gt^2

Horizontal equations (remember that gravity has no effect, so g = 0) :
v = u
s = ut

Now to your question :

Horizontally, we have s = 185 m, u = 480 m/s.
Using s = ut gives t = s/u = 185/480 sec.
So it takes the bullet 185/480 seconds to reach 185 metres.

During this same time, the bullet falls vertically, so now we use
the vertical equation, s = (1/2)gt^2.

Plugging in g = 9.81 m/s^2 and t = 185/480 gives :

s = (1/2)(9.81)(185/480)^2 = 0.729 metres,

which means the bullet falls a distance of 0.729 metres below its original height,
so this is the distance by which the bullet will miss the target.

How many pounds does 1 gallon of jet fuel weigh??

The standard is 6.79 lbs/gal. One of the cheats I used to regularly use when a calculator wasn't available and a pilot requested his fuel in pounds, (taught to me by another jet pilot,) "divide by ten, add half again."

If I take a Hawker pilot, (ex-army,) who used to routinely request overwing fueling in pounds, as an example, and the thousand pounds he thought he'd burn on a short flight,... 1000/10= 100. I add half of that number and I come up with 150 gallons of fuel. I divide by 2 and I'm at 75 gallons each wing.

Using the calculator, if I divide 1000/6.79, I'm showing 148 gallons. My guesstimation was only off by 2 gallons; If that's going to make a difference, the pilot has problems before the engines are started.

There are temperature/volume compensators for dispensing units, (those were a bastard to calibrate,) available from Veeder-Root, due to the fact that heavier fuels react differently to temperature changes.

Unless you live in a rapidly changing climate, 6.79 pounds per gallon is what Exxon, Cheveron and Gammon tech trained me to expect and use to make calculations. Like I said before, if an additional gallon or two of fuel makes a difference, you're already screwed.

Is Salt Lake City SLC airport big?

It depends on what you consider big. Im from and worked in the Atlanta airport for Delta and to me SLC is not big. But if you are coming from a small airport like Billings, MT then yeah its big. Ive provided the link with a copy of the map and lay out of the airport. Size is all relative to what you are used to. For me, SLC isnt that big. It is a Hub for Delta, so it's size is larger by comparison, but there are much larger airports.

Physics Homework Help Please?

A student releases a block of mass m at the top of a slide of height h1. the block moves down the slide and off the end of the table of height h2, landing on the floor a horizontal distance d from the edge of the table. Friction and air resistance are negligible. The overall height H of the setup is determined by the height of the room. Therefore, if h1 is increased, h2 must decrease by the same amount so that the sum h1+h2 remains equal to H. The student wants to adjust h1 and h2 to make d as large as possible.

A) 1) Without using equations, explain why making h1 very small would cause d to be small, even though
h2 would be very large?

2) Without using equations, explain why making h2 very small would cause d to be small, even though
h1 would be large

B)Derive an equation for d in terms of h1, h2, m, and physical constants as appropriate.

C) 1) write the equation or step in your derivation in part (B)(not your final answer) that supports your
reasoning in part A1
Briefly explain your choice
2) write the equation or step in your derivation in part (B)(not your final answer) that supports your
reasoning in part A2
Briefly explain your choice
D) If the experiment is repeated on the moon without changing h1 or h2, will the new landing distance d be greater than, less than, or the same as the lading distance when the experiment is performed on Earth.
Briefly explain how you arrived at your answer

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