GCSE Maths Help!!!! Exam Tomorrow!!!!!!! HELP!!!!!!!!!!!!!!!!!!!!!!!!!!...
22a, find two numbers that multiply to -21 and add to +4. The numbers are +7 and -3. (x+7)(x-3) 22b no middle term says that you find a such that (+a) (-a) = -25. Obviously it is 5. There are two options for 4 of the x^2 term but we want them to be equal. So the answer is (2x + 5)(2x - 5) 22c. I would argue that the only non-variable common term is 2 so we get -2y(a + x) and the other terms are b(a + x). we can add these (since (a + b) is common and get (b-2y) (a + x) 23. (m - n) (m + n) use this when the middle term is missing and the other terms have roots. 25a. factor out 3 an then use the same idea used in 22b 3(a-2b)(a+2b) 25b expand these polynomials and then add like terms 26a is similar to 22a 26b. expand then then factorize. Good luck!
I have a maths exam tomorrow, help!?
Make sure you have any info/ equipment you need, such as exam number, room, time, pen, table of formulae, calculator (if allowed), compasses, You have done all your revision by the sound of it, so leave it alone now. Distract yourself. Go for a walk. Eat a light meal. Watch a comedy program or film. Get to bed early, perhaps with a (non-maths) book. Set an alarm for the morning in case you are overtired. Reassure yourself that recent tests gave you reasonable marks Camomile tea if still restless, but nothing stronger than that. We all know how you feel, but you will be fine. Good luck. Regards - Ian
HELP with maths...got a mock exam tomorrow!?
hi for this sequence if you put n=1 you get u1 similarly u2,u3 etc If you put n=1 you get 4=a+b+c if you put n=2 you get 10=4a+2b+c if you put n=3 18=9a+3b+c so the 3 eqns are 18=9a+3b+c ---- 1 10=4a+2b+c ---- 2 4=a+b+c ----- 3 1-2 5a+b=8 ----- 4 2-3 3a+b=6 ----- 5 4-5 you get 2a=2 a=1 sub a=1 in 4 you get b=3 sub a=1,b=3 in 1 you get c=0 so a=1 b=3 c=0 :)
I have got a math exam day after tomorrow and I still don't feel like studying, what can I do to be motivated? I want to score at least 50-60%. Help.
First of all it is bad to know you have already set a goal of 60%. I am not talking about whatever is possible but presetting a goal will make you slack even more.Then to prepare- look for the previous year question papers. You will definitely find some topics that are repetitive and the chapter that are more important. First learn to solve the repetitive problems.If you cannot get in touch with previous year papers, look for the topics covered after the previous exam of your school/college. Most of the paper is from the recently covered topics.Then in chapter of maths, there are always certain type of problems which can come from a topic. Prepare those.Concetrate on concepts more and after reading the concepts do one problem of each type present in the exercise. Study few topics with full concentration instead of trying to cover everything up. Remember if you try to cram everything up, it all gets jumbled up and you end up with very less marks.Before the exam, always fool yourself and also motivate yourself by telling yourself you know everything. That way you try to solve the entire question paper. If you don't know anything in a question write down whatever you can remember about that topic. It can earn you marks if your instructor is a merciful person.If your problem is not being able to concentrate leave it and sleep for like 4 to 6 hours to refresh your mind. You can also try meditation or exercise for better focus.If nothing works, think about how your parents will scold yoa after seeing your marks, that should provide enough motivation.All the best!
TOP 3 confusing Maths!.... Help...! Exam tomorrow..?! +10 PTS.?
1. you should show all your work. _ _ | m^(4) |^(2) | ------------------ | | -5m^(-2)*n^(3) | -- -- =m^(8)/[(-25)*m^(1/2*2)*n^(6)] =m^(8)/[(-25)*m*n^(6)] =m^(7)/[-26*n(6)] #2. I Don't know. #3. You're given gallons, and ounces/minute. You're right in converting ounces/minute to gallons/year. 1.5oz/min=xgal/year given gal=128oz therefore gal/128=oz given 60min/hr * 24hr/day * 365day/year = 525600min/year therefore year=525600min by substitution: 1.5 (gal /128) / min=x gal / 525600min simplify: [1.5 (gal / 128) / min ] * 525600 min=x gal [.0117 gal/min] * 525600 min = x gal 6159.375 gal = x gal x=6159.375 (Notice how the units are eqaul? This lets me know I did the conversion correctly. If I ended up with "x gal/min = y gal" I would know something was wrong.) So: 1.5oz/min = 6159.375gal/year Total water - (leak rate * time spent leaking) = 0 Using information from the problem and from our previous claclulation: 1.3*10^15gal-(6159.375gal/year * zyear)=0 we solve for z 1.3*10^15 gal = 6159.375gal/year * zyear 1.3*10^15gal/(6159.375gal/year)=z year (1.3gal/6159.375gal/year)*10^15=z year (2.1106*10^(-4) year* 10^(15)=z year 2.1106*10(11)year=z year z= 2.1106*10^11 Answer: 2.1106810^11 years or 211 billion years
Please help me with these math questions.. exams tomorrow?
you shood b studying, not asking stuff on Y!A