Need Help With A C Lab

Need help on Lab Report?

"To find a pattern we need to construct an X/Y scatter plot using a "standard curve." A standard curve provides known information that can then be used to find information about unknown data samples. Information should plot on a standard Cartesian coordinate system (to create your standard curve) is shown in the box......Draw a line of "best fit" through the data."

I have made my XY scattered plot. I'm just confused about the standard curve and the line of "best fit." Are they two separate lines or are they the same line?
I know to add lines on Microsoft Excel 2007 you click on "trendlines" and click one. Which one would I use?
And what is a Cartesian coordinate system? And how do I use it?

I need help with a science lab?

in college technology training are divided into 2 so each and each 300 and sixty 5 days you're taking a technology type you're in fact taking 2 seperate classes one type is a lecture type, and the different is a lab type case in point, shall we say you choose to take biology you may take a lecture type have been your instructor explains all approximately vegetation and whatnot than additionally you may take a lab type, the place you truthfully prepare what you discovered in lecture and reveal it, so in bio lab you may seem at vegetation decrease than microscopes its truthfully a tremendously cool deal, because of fact in many circumstances the lecturers won't assign homework on the grounds which you're taking 2 training for the concern so yea you ought to take the lab with the lecture. you may not do one or the different, must be the two. yet they correlate with eachother and generally circumstances have an analogous instructor

I need help with a Biology Lab?

Physical agents such as heat and radiation will damage cells by coagulating their contents ( similiar to cooking. High temperature increases the permeability of cell membrane which causes cell death.

Water is the main constituent of milk and to make it a solid the water must be removed from either by evaporation or through milking machines. If milk is left to stand, a layer of crem forms on the surface.


Good luck with your yogurt.

C++ lab and Need help?

Here's an algorithm,

int number =100, lineCount = 0;
final int maxLineCount = 5, maxNumber = 150;

for (int number, number <= maxNumber, number++)
{
if (number % 2 ==0) // checking for even numbers
{
cout << number;
lineCount++; // increment the counter every time new number
//printed on the line
}
if (lineCount == 5) // I think 5 should be max since starting from 0
{
cout << endl; // new line
lineCount = 0; // reset the counter to 0, new line reached
}
}

Try using a similar algorithm and let me know what happens.
I just noticed you specified "while loop" rather than a "for
loop" The same logic inside the for loop can be applied in
your while loop.

Need help with an Enzyme lab report?

Hi I have an enzyme lab report to do and I have a couple of questions the lab was how does different things effect enzyme activity and it had 4 parts
how does temperature , pH, enzyme concentration and substrate concentration effect the rate of a reaction.
So my question is for each of those parts what would be the independent and dependent variable and in the direction it tells me to discuss the variables and I'm a little confuse on what I have to talk about in there
any help is greatly appriciated thanks =]

I need help with a c++ programming lab?

Give us a clue: what is the unhandled exception and where does it occur? I for one have little inclination to wade through 100 lines of unindented code looking for any possible problem rather than focusing on the specific error you are experiencing.

Need help with physics lab?

Hi :-) As you increase the voltage the current also increases causing the filament in the light bulb to get hot, the current starts to even out because the filament has already become hot enought and can't get any hotter, the resistance also increase because when you use the formula V=IR to get R we use R= V/I and if the voltage is still increasing by a large amount but the current is not then you are basically getting a higher resistance because the the current would more or less stay the same but you are dividing a bigger voltage with the same current so it is bigger, It is the same for the smaller current, the resistance and voltage is more or less proportional because as you increase V, R has to increase to maintain the correct current through the lighbulb, I=V/R if the voltage is rising and the resistance is aswell then I would not change because both V and R are rising :-) If you wanna know anything else email me ;-) I'm from the UK aswell :-)

I need help with my lab questions!! please help?

The stomach has hydrochloric acid (a ph level 4-5). It's not a strong acid compared to other strong acids. If the acidity of the stomach was constantly a 1-2 then it would have burn through the stomach.

I don't know if this is the answer you were looking for. Hope it helps somehow. There are links below about the acidity in the stomach.

Need help with this lab! You don't have to answer just tell me how to do it!?

check the question again::::


I am not sure which one is part I and which is part II

The following is just my suggestion. I hope it makes sense

NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l)

???????????? what is the molarity of HCl and NaOH
let's say you are given 0.5M of each

moles = molarity x volume
n = MV

NaOH: n = (0.5 mol/L) (100.0mL * 1L /1000mL) = 0.0500 mol NaOH
HCl: n = (0.5 mol/L) (100.5mL * 1L /1000mL) = 0.05025 mol HCl

limiting agent: NaOH (0.0500 mol < 0.05025 mol)

mass = moles x molar mass
m = n(W)
NaOH: m = 0.0500(39.997) = 2.000g
HCl: m = 0.05025(36.46094) = 1.832g
total mass = mass of NaOH(aq) + mass of HCl(aq)
`````````````

Heat gained by the water = heat due to reaction
mass of water = volume x density
m(w) = (100.5ml + 100.0 ml)(1 g/ml)
m(w) = 200.5 g
`````````````````````
H = m(w) * C(w) *ΔT
H = 200.5g (4.1813 J/(g*K) ) [ (28.2 + 273.15) - (25.2 + 273.15) ]K
H = 2515.05 J
H = 2.515 kJ

Heat due reaction = - 2.515 kJ
0.0500 mol NaOH = => -2.515 kJ
1 mol NaOH ==> ?

1 mol NaOH(aq) x (-2.515 kJ ) / (0.0500 mol NaOH )
= -50.3 kJ/mol NaOH
`````````````````````````````` remember you didn't provide molarity....the answer here could be different if molarity given was 1.0M or 0.8M


hess's law
NaOH (s) + HCl (aq) → NaCl (aq) + H₂O (l)
heat of formation of NaOH(s): ΔfH⁰ = −425.93 kJ/mol
heat of formation of HCl(aq): ΔfH⁰ = −167.2 kJ/mol
heat of formation of NaCl(aq): ΔfH⁰ = −407.27 kJ/mol
heat of formation of H₂O: ΔfH⁰ = −285.8 kJ/mol

ΔH⁰ = ∑(moles * ΔfH⁰ of products) - ∑(moles* ΔfH⁰ of reactants)
ΔH⁰ = (-407.27 kJ/mol * 1 mol - 285.8 kJ/mol * 1 mol) - (-425.93 kJ/mol * 1 mol - 167.2 kJ/mol *1 mol)
ΔH⁰ = -99.94 kJ
`````````````````````